?

Average Error: 10.7 → 0.4
Time: 17.3s
Precision: binary64
Cost: 6920

?

\[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
\[\begin{array}{l} t_0 := \frac{e^{-y}}{x}\\ \mathbf{if}\;x \leq -5:\\ \;\;\;\;t_0\\ \mathbf{elif}\;x \leq 0.14:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \]
(FPCore (x y) :precision binary64 (/ (exp (* x (log (/ x (+ x y))))) x))
(FPCore (x y)
 :precision binary64
 (let* ((t_0 (/ (exp (- y)) x)))
   (if (<= x -5.0) t_0 (if (<= x 0.14) (/ 1.0 x) t_0))))
double code(double x, double y) {
	return exp((x * log((x / (x + y))))) / x;
}
double code(double x, double y) {
	double t_0 = exp(-y) / x;
	double tmp;
	if (x <= -5.0) {
		tmp = t_0;
	} else if (x <= 0.14) {
		tmp = 1.0 / x;
	} else {
		tmp = t_0;
	}
	return tmp;
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp((x * log((x / (x + y))))) / x
end function
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8) :: t_0
    real(8) :: tmp
    t_0 = exp(-y) / x
    if (x <= (-5.0d0)) then
        tmp = t_0
    else if (x <= 0.14d0) then
        tmp = 1.0d0 / x
    else
        tmp = t_0
    end if
    code = tmp
end function
public static double code(double x, double y) {
	return Math.exp((x * Math.log((x / (x + y))))) / x;
}
public static double code(double x, double y) {
	double t_0 = Math.exp(-y) / x;
	double tmp;
	if (x <= -5.0) {
		tmp = t_0;
	} else if (x <= 0.14) {
		tmp = 1.0 / x;
	} else {
		tmp = t_0;
	}
	return tmp;
}
def code(x, y):
	return math.exp((x * math.log((x / (x + y))))) / x
def code(x, y):
	t_0 = math.exp(-y) / x
	tmp = 0
	if x <= -5.0:
		tmp = t_0
	elif x <= 0.14:
		tmp = 1.0 / x
	else:
		tmp = t_0
	return tmp
function code(x, y)
	return Float64(exp(Float64(x * log(Float64(x / Float64(x + y))))) / x)
end
function code(x, y)
	t_0 = Float64(exp(Float64(-y)) / x)
	tmp = 0.0
	if (x <= -5.0)
		tmp = t_0;
	elseif (x <= 0.14)
		tmp = Float64(1.0 / x);
	else
		tmp = t_0;
	end
	return tmp
end
function tmp = code(x, y)
	tmp = exp((x * log((x / (x + y))))) / x;
end
function tmp_2 = code(x, y)
	t_0 = exp(-y) / x;
	tmp = 0.0;
	if (x <= -5.0)
		tmp = t_0;
	elseif (x <= 0.14)
		tmp = 1.0 / x;
	else
		tmp = t_0;
	end
	tmp_2 = tmp;
end
code[x_, y_] := N[(N[Exp[N[(x * N[Log[N[(x / N[(x + y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / x), $MachinePrecision]
code[x_, y_] := Block[{t$95$0 = N[(N[Exp[(-y)], $MachinePrecision] / x), $MachinePrecision]}, If[LessEqual[x, -5.0], t$95$0, If[LessEqual[x, 0.14], N[(1.0 / x), $MachinePrecision], t$95$0]]]
\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x}
\begin{array}{l}
t_0 := \frac{e^{-y}}{x}\\
\mathbf{if}\;x \leq -5:\\
\;\;\;\;t_0\\

\mathbf{elif}\;x \leq 0.14:\\
\;\;\;\;\frac{1}{x}\\

\mathbf{else}:\\
\;\;\;\;t_0\\


\end{array}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original10.7
Target8.1
Herbie0.4
\[\begin{array}{l} \mathbf{if}\;y < -3.7311844206647956 \cdot 10^{+94}:\\ \;\;\;\;\frac{e^{\frac{-1}{y}}}{x}\\ \mathbf{elif}\;y < 2.817959242728288 \cdot 10^{+37}:\\ \;\;\;\;\frac{{\left(\frac{x}{y + x}\right)}^{x}}{x}\\ \mathbf{elif}\;y < 2.347387415166998 \cdot 10^{+178}:\\ \;\;\;\;\log \left(e^{\frac{{\left(\frac{x}{y + x}\right)}^{x}}{x}}\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{e^{\frac{-1}{y}}}{x}\\ \end{array} \]

Derivation?

  1. Split input into 2 regimes
  2. if x < -5 or 0.14000000000000001 < x

    1. Initial program 10.5

      \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
    2. Taylor expanded in x around inf 0.1

      \[\leadsto \frac{e^{\color{blue}{-1 \cdot y}}}{x} \]
    3. Simplified0.1

      \[\leadsto \frac{e^{\color{blue}{-y}}}{x} \]
      Proof

      [Start]0.1

      \[ \frac{e^{-1 \cdot y}}{x} \]

      rational_best-simplify-2 [=>]0.1

      \[ \frac{e^{\color{blue}{y \cdot -1}}}{x} \]

      rational_best-simplify-12 [=>]0.1

      \[ \frac{e^{\color{blue}{-y}}}{x} \]

    if -5 < x < 0.14000000000000001

    1. Initial program 11.0

      \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
    2. Taylor expanded in x around 0 0.7

      \[\leadsto \color{blue}{\frac{1}{x}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification0.4

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -5:\\ \;\;\;\;\frac{e^{-y}}{x}\\ \mathbf{elif}\;x \leq 0.14:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{e^{-y}}{x}\\ \end{array} \]

Alternatives

Alternative 1
Error9.7
Cost192
\[\frac{1}{x} \]

Error

Reproduce?

herbie shell --seed 2023096 
(FPCore (x y)
  :name "Numeric.SpecFunctions:invIncompleteBetaWorker from math-functions-0.1.5.2, F"
  :precision binary64

  :herbie-target
  (if (< y -3.7311844206647956e+94) (/ (exp (/ -1.0 y)) x) (if (< y 2.817959242728288e+37) (/ (pow (/ x (+ y x)) x) x) (if (< y 2.347387415166998e+178) (log (exp (/ (pow (/ x (+ y x)) x) x))) (/ (exp (/ -1.0 y)) x))))

  (/ (exp (* x (log (/ x (+ x y))))) x))