?

Average Error: 8.78% → 0.14%
Time: 4.1s
Precision: binary64
Cost: 708

?

\[x \cdot \left(1 + y \cdot y\right) \]
\[\begin{array}{l} \mathbf{if}\;y \cdot y \leq 2 \cdot 10^{+124}:\\ \;\;\;\;x + \left(y \cdot y\right) \cdot x\\ \mathbf{else}:\\ \;\;\;\;y \cdot \left(y \cdot x\right)\\ \end{array} \]
(FPCore (x y) :precision binary64 (* x (+ 1.0 (* y y))))
(FPCore (x y)
 :precision binary64
 (if (<= (* y y) 2e+124) (+ x (* (* y y) x)) (* y (* y x))))
double code(double x, double y) {
	return x * (1.0 + (y * y));
}
double code(double x, double y) {
	double tmp;
	if ((y * y) <= 2e+124) {
		tmp = x + ((y * y) * x);
	} else {
		tmp = y * (y * x);
	}
	return tmp;
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = x * (1.0d0 + (y * y))
end function
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8) :: tmp
    if ((y * y) <= 2d+124) then
        tmp = x + ((y * y) * x)
    else
        tmp = y * (y * x)
    end if
    code = tmp
end function
public static double code(double x, double y) {
	return x * (1.0 + (y * y));
}
public static double code(double x, double y) {
	double tmp;
	if ((y * y) <= 2e+124) {
		tmp = x + ((y * y) * x);
	} else {
		tmp = y * (y * x);
	}
	return tmp;
}
def code(x, y):
	return x * (1.0 + (y * y))
def code(x, y):
	tmp = 0
	if (y * y) <= 2e+124:
		tmp = x + ((y * y) * x)
	else:
		tmp = y * (y * x)
	return tmp
function code(x, y)
	return Float64(x * Float64(1.0 + Float64(y * y)))
end
function code(x, y)
	tmp = 0.0
	if (Float64(y * y) <= 2e+124)
		tmp = Float64(x + Float64(Float64(y * y) * x));
	else
		tmp = Float64(y * Float64(y * x));
	end
	return tmp
end
function tmp = code(x, y)
	tmp = x * (1.0 + (y * y));
end
function tmp_2 = code(x, y)
	tmp = 0.0;
	if ((y * y) <= 2e+124)
		tmp = x + ((y * y) * x);
	else
		tmp = y * (y * x);
	end
	tmp_2 = tmp;
end
code[x_, y_] := N[(x * N[(1.0 + N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
code[x_, y_] := If[LessEqual[N[(y * y), $MachinePrecision], 2e+124], N[(x + N[(N[(y * y), $MachinePrecision] * x), $MachinePrecision]), $MachinePrecision], N[(y * N[(y * x), $MachinePrecision]), $MachinePrecision]]
x \cdot \left(1 + y \cdot y\right)
\begin{array}{l}
\mathbf{if}\;y \cdot y \leq 2 \cdot 10^{+124}:\\
\;\;\;\;x + \left(y \cdot y\right) \cdot x\\

\mathbf{else}:\\
\;\;\;\;y \cdot \left(y \cdot x\right)\\


\end{array}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original8.78%
Target0.14%
Herbie0.14%
\[x + \left(x \cdot y\right) \cdot y \]

Derivation?

  1. Split input into 2 regimes
  2. if (*.f64 y y) < 1.9999999999999999e124

    1. Initial program 0.08

      \[x \cdot \left(1 + y \cdot y\right) \]
    2. Applied egg-rr0.07

      \[\leadsto \color{blue}{x \cdot \left(y \cdot y\right) + x} \]

    if 1.9999999999999999e124 < (*.f64 y y)

    1. Initial program 39.78

      \[x \cdot \left(1 + y \cdot y\right) \]
    2. Taylor expanded in y around inf 39.78

      \[\leadsto \color{blue}{{y}^{2} \cdot x} \]
    3. Simplified0.4

      \[\leadsto \color{blue}{y \cdot \left(y \cdot x\right)} \]
      Proof

      [Start]39.78

      \[ {y}^{2} \cdot x \]

      unpow2 [=>]39.78

      \[ \color{blue}{\left(y \cdot y\right)} \cdot x \]

      associate-*l* [=>]0.4

      \[ \color{blue}{y \cdot \left(y \cdot x\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification0.14

    \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot y \leq 2 \cdot 10^{+124}:\\ \;\;\;\;x + \left(y \cdot y\right) \cdot x\\ \mathbf{else}:\\ \;\;\;\;y \cdot \left(y \cdot x\right)\\ \end{array} \]

Alternatives

Alternative 1
Error0.15%
Cost708
\[\begin{array}{l} \mathbf{if}\;y \cdot y \leq 2 \cdot 10^{+124}:\\ \;\;\;\;x \cdot \left(y \cdot y + 1\right)\\ \mathbf{else}:\\ \;\;\;\;y \cdot \left(y \cdot x\right)\\ \end{array} \]
Alternative 2
Error10.27%
Cost580
\[\begin{array}{l} \mathbf{if}\;y \cdot y \leq 1:\\ \;\;\;\;x\\ \mathbf{else}:\\ \;\;\;\;\left(y \cdot y\right) \cdot x\\ \end{array} \]
Alternative 3
Error1.65%
Cost580
\[\begin{array}{l} \mathbf{if}\;y \cdot y \leq 0.1:\\ \;\;\;\;x\\ \mathbf{else}:\\ \;\;\;\;y \cdot \left(y \cdot x\right)\\ \end{array} \]
Alternative 4
Error32.83%
Cost64
\[x \]

Error

Reproduce?

herbie shell --seed 2023090 
(FPCore (x y)
  :name "Numeric.Integration.TanhSinh:everywhere from integration-0.2.1"
  :precision binary64

  :herbie-target
  (+ x (* (* x y) y))

  (* x (+ 1.0 (* y y))))