\[lo < -1 \cdot 10^{+308} \land hi > 10^{+308}\]
Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\frac{x - lo}{hi - lo}
\]
↓
\[1 + \sqrt{{\left(\frac{1}{1 - \frac{hi}{lo}}\right)}^{2}} \cdot \frac{hi - x}{lo}
\]
(FPCore (lo hi x) :precision binary64 (/ (- x lo) (- hi lo))) ↓
(FPCore (lo hi x)
:precision binary64
(+ 1.0 (* (sqrt (pow (/ 1.0 (- 1.0 (/ hi lo))) 2.0)) (/ (- hi x) lo)))) double code(double lo, double hi, double x) {
return (x - lo) / (hi - lo);
}
↓
double code(double lo, double hi, double x) {
return 1.0 + (sqrt(pow((1.0 / (1.0 - (hi / lo))), 2.0)) * ((hi - x) / lo));
}
real(8) function code(lo, hi, x)
real(8), intent (in) :: lo
real(8), intent (in) :: hi
real(8), intent (in) :: x
code = (x - lo) / (hi - lo)
end function
↓
real(8) function code(lo, hi, x)
real(8), intent (in) :: lo
real(8), intent (in) :: hi
real(8), intent (in) :: x
code = 1.0d0 + (sqrt(((1.0d0 / (1.0d0 - (hi / lo))) ** 2.0d0)) * ((hi - x) / lo))
end function
public static double code(double lo, double hi, double x) {
return (x - lo) / (hi - lo);
}
↓
public static double code(double lo, double hi, double x) {
return 1.0 + (Math.sqrt(Math.pow((1.0 / (1.0 - (hi / lo))), 2.0)) * ((hi - x) / lo));
}
def code(lo, hi, x):
return (x - lo) / (hi - lo)
↓
def code(lo, hi, x):
return 1.0 + (math.sqrt(math.pow((1.0 / (1.0 - (hi / lo))), 2.0)) * ((hi - x) / lo))
function code(lo, hi, x)
return Float64(Float64(x - lo) / Float64(hi - lo))
end
↓
function code(lo, hi, x)
return Float64(1.0 + Float64(sqrt((Float64(1.0 / Float64(1.0 - Float64(hi / lo))) ^ 2.0)) * Float64(Float64(hi - x) / lo)))
end
function tmp = code(lo, hi, x)
tmp = (x - lo) / (hi - lo);
end
↓
function tmp = code(lo, hi, x)
tmp = 1.0 + (sqrt(((1.0 / (1.0 - (hi / lo))) ^ 2.0)) * ((hi - x) / lo));
end
code[lo_, hi_, x_] := N[(N[(x - lo), $MachinePrecision] / N[(hi - lo), $MachinePrecision]), $MachinePrecision]
↓
code[lo_, hi_, x_] := N[(1.0 + N[(N[Sqrt[N[Power[N[(1.0 / N[(1.0 - N[(hi / lo), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]], $MachinePrecision] * N[(N[(hi - x), $MachinePrecision] / lo), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\frac{x - lo}{hi - lo}
↓
1 + \sqrt{{\left(\frac{1}{1 - \frac{hi}{lo}}\right)}^{2}} \cdot \frac{hi - x}{lo}