?

Average Error: 74.86% → 0.82%
Time: 21.2s
Precision: binary64
Cost: 21768

?

\[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
\[\begin{array}{l} t_0 := {\left(1 + \frac{i}{n}\right)}^{n}\\ t_1 := \frac{t_0 + -1}{\frac{i}{n}}\\ \mathbf{if}\;t_1 \leq 5 \cdot 10^{-310}:\\ \;\;\;\;\frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right) \cdot 100}{\frac{i}{n}}\\ \mathbf{elif}\;t_1 \leq 1000000000:\\ \;\;\;\;n \cdot \frac{t_0 \cdot 100 + -100}{i}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{n}{1 + i \cdot \left(-0.5 + i \cdot 0.08333333333333333\right)}\\ \end{array} \]
(FPCore (i n)
 :precision binary64
 (* 100.0 (/ (- (pow (+ 1.0 (/ i n)) n) 1.0) (/ i n))))
(FPCore (i n)
 :precision binary64
 (let* ((t_0 (pow (+ 1.0 (/ i n)) n)) (t_1 (/ (+ t_0 -1.0) (/ i n))))
   (if (<= t_1 5e-310)
     (/ (* (expm1 (* n (log1p (/ i n)))) 100.0) (/ i n))
     (if (<= t_1 1000000000.0)
       (* n (/ (+ (* t_0 100.0) -100.0) i))
       (* 100.0 (/ n (+ 1.0 (* i (+ -0.5 (* i 0.08333333333333333))))))))))
double code(double i, double n) {
	return 100.0 * ((pow((1.0 + (i / n)), n) - 1.0) / (i / n));
}
double code(double i, double n) {
	double t_0 = pow((1.0 + (i / n)), n);
	double t_1 = (t_0 + -1.0) / (i / n);
	double tmp;
	if (t_1 <= 5e-310) {
		tmp = (expm1((n * log1p((i / n)))) * 100.0) / (i / n);
	} else if (t_1 <= 1000000000.0) {
		tmp = n * (((t_0 * 100.0) + -100.0) / i);
	} else {
		tmp = 100.0 * (n / (1.0 + (i * (-0.5 + (i * 0.08333333333333333)))));
	}
	return tmp;
}
public static double code(double i, double n) {
	return 100.0 * ((Math.pow((1.0 + (i / n)), n) - 1.0) / (i / n));
}
public static double code(double i, double n) {
	double t_0 = Math.pow((1.0 + (i / n)), n);
	double t_1 = (t_0 + -1.0) / (i / n);
	double tmp;
	if (t_1 <= 5e-310) {
		tmp = (Math.expm1((n * Math.log1p((i / n)))) * 100.0) / (i / n);
	} else if (t_1 <= 1000000000.0) {
		tmp = n * (((t_0 * 100.0) + -100.0) / i);
	} else {
		tmp = 100.0 * (n / (1.0 + (i * (-0.5 + (i * 0.08333333333333333)))));
	}
	return tmp;
}
def code(i, n):
	return 100.0 * ((math.pow((1.0 + (i / n)), n) - 1.0) / (i / n))
def code(i, n):
	t_0 = math.pow((1.0 + (i / n)), n)
	t_1 = (t_0 + -1.0) / (i / n)
	tmp = 0
	if t_1 <= 5e-310:
		tmp = (math.expm1((n * math.log1p((i / n)))) * 100.0) / (i / n)
	elif t_1 <= 1000000000.0:
		tmp = n * (((t_0 * 100.0) + -100.0) / i)
	else:
		tmp = 100.0 * (n / (1.0 + (i * (-0.5 + (i * 0.08333333333333333)))))
	return tmp
function code(i, n)
	return Float64(100.0 * Float64(Float64((Float64(1.0 + Float64(i / n)) ^ n) - 1.0) / Float64(i / n)))
end
function code(i, n)
	t_0 = Float64(1.0 + Float64(i / n)) ^ n
	t_1 = Float64(Float64(t_0 + -1.0) / Float64(i / n))
	tmp = 0.0
	if (t_1 <= 5e-310)
		tmp = Float64(Float64(expm1(Float64(n * log1p(Float64(i / n)))) * 100.0) / Float64(i / n));
	elseif (t_1 <= 1000000000.0)
		tmp = Float64(n * Float64(Float64(Float64(t_0 * 100.0) + -100.0) / i));
	else
		tmp = Float64(100.0 * Float64(n / Float64(1.0 + Float64(i * Float64(-0.5 + Float64(i * 0.08333333333333333))))));
	end
	return tmp
end
code[i_, n_] := N[(100.0 * N[(N[(N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision] - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
code[i_, n_] := Block[{t$95$0 = N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision]}, Block[{t$95$1 = N[(N[(t$95$0 + -1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, 5e-310], N[(N[(N[(Exp[N[(n * N[Log[1 + N[(i / n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]] - 1), $MachinePrecision] * 100.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$1, 1000000000.0], N[(n * N[(N[(N[(t$95$0 * 100.0), $MachinePrecision] + -100.0), $MachinePrecision] / i), $MachinePrecision]), $MachinePrecision], N[(100.0 * N[(n / N[(1.0 + N[(i * N[(-0.5 + N[(i * 0.08333333333333333), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]]
100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}
\begin{array}{l}
t_0 := {\left(1 + \frac{i}{n}\right)}^{n}\\
t_1 := \frac{t_0 + -1}{\frac{i}{n}}\\
\mathbf{if}\;t_1 \leq 5 \cdot 10^{-310}:\\
\;\;\;\;\frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right) \cdot 100}{\frac{i}{n}}\\

\mathbf{elif}\;t_1 \leq 1000000000:\\
\;\;\;\;n \cdot \frac{t_0 \cdot 100 + -100}{i}\\

\mathbf{else}:\\
\;\;\;\;100 \cdot \frac{n}{1 + i \cdot \left(-0.5 + i \cdot 0.08333333333333333\right)}\\


\end{array}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original74.86%
Target74.94%
Herbie0.82%
\[100 \cdot \frac{e^{n \cdot \begin{array}{l} \mathbf{if}\;1 + \frac{i}{n} = 1:\\ \;\;\;\;\frac{i}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{i}{n} \cdot \log \left(1 + \frac{i}{n}\right)}{\left(\frac{i}{n} + 1\right) - 1}\\ \end{array}} - 1}{\frac{i}{n}} \]

Derivation?

  1. Split input into 3 regimes
  2. if (/.f64 (-.f64 (pow.f64 (+.f64 1 (/.f64 i n)) n) 1) (/.f64 i n)) < 4.999999999999985e-310

    1. Initial program 72.39

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Applied egg-rr0.46

      \[\leadsto \color{blue}{\frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right) \cdot 100}{\frac{i}{n}}} \]

    if 4.999999999999985e-310 < (/.f64 (-.f64 (pow.f64 (+.f64 1 (/.f64 i n)) n) 1) (/.f64 i n)) < 1e9

    1. Initial program 5.57

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Simplified5.42

      \[\leadsto \color{blue}{n \cdot \frac{\mathsf{fma}\left(100, {\left(1 + \frac{i}{n}\right)}^{n}, -100\right)}{i}} \]
      Proof

      [Start]5.57

      \[ 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]

      associate-/r/ [=>]5.54

      \[ 100 \cdot \color{blue}{\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i} \cdot n\right)} \]

      associate-*r* [=>]5.56

      \[ \color{blue}{\left(100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i}\right) \cdot n} \]

      *-lft-identity [<=]5.56

      \[ \left(100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i}\right) \cdot \color{blue}{\left(1 \cdot n\right)} \]

      associate-*r* [=>]5.56

      \[ \color{blue}{\left(\left(100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i}\right) \cdot 1\right) \cdot n} \]

      *-commutative [=>]5.56

      \[ \color{blue}{n \cdot \left(\left(100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i}\right) \cdot 1\right)} \]

      *-commutative [=>]5.56

      \[ n \cdot \color{blue}{\left(1 \cdot \left(100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i}\right)\right)} \]

      *-lft-identity [=>]5.56

      \[ n \cdot \color{blue}{\left(100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i}\right)} \]

      associate-*r/ [=>]5.42

      \[ n \cdot \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i}} \]

      sub-neg [=>]5.42

      \[ n \cdot \frac{100 \cdot \color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} + \left(-1\right)\right)}}{i} \]

      distribute-lft-in [=>]5.53

      \[ n \cdot \frac{\color{blue}{100 \cdot {\left(1 + \frac{i}{n}\right)}^{n} + 100 \cdot \left(-1\right)}}{i} \]

      fma-def [=>]5.42

      \[ n \cdot \frac{\color{blue}{\mathsf{fma}\left(100, {\left(1 + \frac{i}{n}\right)}^{n}, 100 \cdot \left(-1\right)\right)}}{i} \]

      metadata-eval [=>]5.42

      \[ n \cdot \frac{\mathsf{fma}\left(100, {\left(1 + \frac{i}{n}\right)}^{n}, 100 \cdot \color{blue}{-1}\right)}{i} \]

      metadata-eval [=>]5.42

      \[ n \cdot \frac{\mathsf{fma}\left(100, {\left(1 + \frac{i}{n}\right)}^{n}, \color{blue}{-100}\right)}{i} \]
    3. Applied egg-rr5.53

      \[\leadsto n \cdot \frac{\color{blue}{100 \cdot {\left(1 + \frac{i}{n}\right)}^{n} + -100}}{i} \]

    if 1e9 < (/.f64 (-.f64 (pow.f64 (+.f64 1 (/.f64 i n)) n) 1) (/.f64 i n))

    1. Initial program 99.11

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Taylor expanded in n around inf 97.63

      \[\leadsto \color{blue}{100 \cdot \frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
    3. Simplified21.92

      \[\leadsto \color{blue}{\frac{n}{\frac{i}{\mathsf{expm1}\left(i\right)}} \cdot 100} \]
      Proof

      [Start]97.63

      \[ 100 \cdot \frac{n \cdot \left(e^{i} - 1\right)}{i} \]

      *-commutative [=>]97.63

      \[ \color{blue}{\frac{n \cdot \left(e^{i} - 1\right)}{i} \cdot 100} \]

      associate-/l* [=>]97.63

      \[ \color{blue}{\frac{n}{\frac{i}{e^{i} - 1}}} \cdot 100 \]

      expm1-def [=>]21.92

      \[ \frac{n}{\frac{i}{\color{blue}{\mathsf{expm1}\left(i\right)}}} \cdot 100 \]
    4. Taylor expanded in i around 0 1.03

      \[\leadsto \frac{n}{\color{blue}{1 + \left(0.08333333333333333 \cdot {i}^{2} + -0.5 \cdot i\right)}} \cdot 100 \]
    5. Simplified1.03

      \[\leadsto \frac{n}{\color{blue}{1 + i \cdot \left(-0.5 + i \cdot 0.08333333333333333\right)}} \cdot 100 \]
      Proof

      [Start]1.03

      \[ \frac{n}{1 + \left(0.08333333333333333 \cdot {i}^{2} + -0.5 \cdot i\right)} \cdot 100 \]

      +-commutative [=>]1.03

      \[ \frac{n}{1 + \color{blue}{\left(-0.5 \cdot i + 0.08333333333333333 \cdot {i}^{2}\right)}} \cdot 100 \]

      *-commutative [=>]1.03

      \[ \frac{n}{1 + \left(\color{blue}{i \cdot -0.5} + 0.08333333333333333 \cdot {i}^{2}\right)} \cdot 100 \]

      *-commutative [=>]1.03

      \[ \frac{n}{1 + \left(i \cdot -0.5 + \color{blue}{{i}^{2} \cdot 0.08333333333333333}\right)} \cdot 100 \]

      unpow2 [=>]1.03

      \[ \frac{n}{1 + \left(i \cdot -0.5 + \color{blue}{\left(i \cdot i\right)} \cdot 0.08333333333333333\right)} \cdot 100 \]

      associate-*l* [=>]1.03

      \[ \frac{n}{1 + \left(i \cdot -0.5 + \color{blue}{i \cdot \left(i \cdot 0.08333333333333333\right)}\right)} \cdot 100 \]

      distribute-lft-out [=>]1.03

      \[ \frac{n}{1 + \color{blue}{i \cdot \left(-0.5 + i \cdot 0.08333333333333333\right)}} \cdot 100 \]
  3. Recombined 3 regimes into one program.
  4. Final simplification0.82

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{{\left(1 + \frac{i}{n}\right)}^{n} + -1}{\frac{i}{n}} \leq 5 \cdot 10^{-310}:\\ \;\;\;\;\frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right) \cdot 100}{\frac{i}{n}}\\ \mathbf{elif}\;\frac{{\left(1 + \frac{i}{n}\right)}^{n} + -1}{\frac{i}{n}} \leq 1000000000:\\ \;\;\;\;n \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} \cdot 100 + -100}{i}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{n}{1 + i \cdot \left(-0.5 + i \cdot 0.08333333333333333\right)}\\ \end{array} \]

Alternatives

Alternative 1
Error1.95%
Cost21768
\[\begin{array}{l} t_0 := {\left(1 + \frac{i}{n}\right)}^{n}\\ t_1 := \frac{t_0 + -1}{\frac{i}{n}}\\ \mathbf{if}\;t_1 \leq 5 \cdot 10^{-310}:\\ \;\;\;\;n \cdot \left(\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right) \cdot \frac{100}{i}\right)\\ \mathbf{elif}\;t_1 \leq 1000000000:\\ \;\;\;\;n \cdot \frac{t_0 \cdot 100 + -100}{i}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{n}{1 + i \cdot \left(-0.5 + i \cdot 0.08333333333333333\right)}\\ \end{array} \]
Alternative 2
Error1.8%
Cost21768
\[\begin{array}{l} t_0 := {\left(1 + \frac{i}{n}\right)}^{n}\\ t_1 := \frac{t_0 + -1}{\frac{i}{n}}\\ \mathbf{if}\;t_1 \leq 5 \cdot 10^{-310}:\\ \;\;\;\;n \cdot \frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}{\frac{i}{100}}\\ \mathbf{elif}\;t_1 \leq 1000000000:\\ \;\;\;\;n \cdot \frac{t_0 \cdot 100 + -100}{i}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{n}{1 + i \cdot \left(-0.5 + i \cdot 0.08333333333333333\right)}\\ \end{array} \]
Alternative 3
Error18.92%
Cost7244
\[\begin{array}{l} t_0 := n \cdot \left(\frac{100}{i} \cdot \mathsf{expm1}\left(i\right)\right)\\ \mathbf{if}\;n \leq -8.5 \cdot 10^{-168}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;n \leq 2.25 \cdot 10^{-222}:\\ \;\;\;\;100 \cdot \frac{0}{\frac{i}{n}}\\ \mathbf{elif}\;n \leq 9 \cdot 10^{+17}:\\ \;\;\;\;\frac{n \cdot 100}{1 + i \cdot \left(-0.5 + i \cdot 0.08333333333333333\right)}\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \]
Alternative 4
Error18.53%
Cost7244
\[\begin{array}{l} t_0 := 100 \cdot \frac{n}{\frac{i}{\mathsf{expm1}\left(i\right)}}\\ \mathbf{if}\;n \leq -1.96 \cdot 10^{-169}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;n \leq 7.2 \cdot 10^{-211}:\\ \;\;\;\;100 \cdot \frac{0}{\frac{i}{n}}\\ \mathbf{elif}\;n \leq 2 \cdot 10^{+17}:\\ \;\;\;\;\frac{n \cdot 100}{1 + i \cdot \left(-0.5 + i \cdot 0.08333333333333333\right)}\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \]
Alternative 5
Error18.63%
Cost7244
\[\begin{array}{l} t_0 := \frac{i}{\mathsf{expm1}\left(i\right)}\\ \mathbf{if}\;n \leq -1.96 \cdot 10^{-169}:\\ \;\;\;\;\frac{n \cdot 100}{t_0}\\ \mathbf{elif}\;n \leq 2.3 \cdot 10^{-219}:\\ \;\;\;\;100 \cdot \frac{0}{\frac{i}{n}}\\ \mathbf{elif}\;n \leq 2 \cdot 10^{+17}:\\ \;\;\;\;\frac{n \cdot 100}{1 + i \cdot \left(-0.5 + i \cdot 0.08333333333333333\right)}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{n}{t_0}\\ \end{array} \]
Alternative 6
Error21.21%
Cost6980
\[\begin{array}{l} \mathbf{if}\;i \leq -0.001:\\ \;\;\;\;100 \cdot \frac{\mathsf{expm1}\left(i\right)}{\frac{i}{n}}\\ \mathbf{else}:\\ \;\;\;\;\frac{n \cdot 100}{1 + i \cdot \left(-0.5 + i \cdot 0.08333333333333333\right)}\\ \end{array} \]
Alternative 7
Error21.44%
Cost6980
\[\begin{array}{l} \mathbf{if}\;i \leq -0.00068:\\ \;\;\;\;\mathsf{expm1}\left(i\right) \cdot \left(100 \cdot \frac{n}{i}\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{n \cdot 100}{1 + i \cdot \left(-0.5 + i \cdot 0.08333333333333333\right)}\\ \end{array} \]
Alternative 8
Error28.82%
Cost1224
\[\begin{array}{l} \mathbf{if}\;n \leq -2.15 \cdot 10^{-169}:\\ \;\;\;\;n \cdot \frac{1}{0.01 + i \cdot -0.005}\\ \mathbf{elif}\;n \leq 2.25 \cdot 10^{-222}:\\ \;\;\;\;100 \cdot \frac{0}{\frac{i}{n}}\\ \mathbf{else}:\\ \;\;\;\;\left(-100 + i \cdot -50\right) \cdot \frac{n}{-1 + i \cdot \left(i \cdot 0.25\right)}\\ \end{array} \]
Alternative 9
Error28.9%
Cost1096
\[\begin{array}{l} \mathbf{if}\;n \leq -1.96 \cdot 10^{-169}:\\ \;\;\;\;n \cdot \frac{1}{0.01 + i \cdot -0.005}\\ \mathbf{elif}\;n \leq 1.22 \cdot 10^{-216}:\\ \;\;\;\;100 \cdot \frac{0}{\frac{i}{n}}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{n}{1 + i \cdot \left(-0.5 + i \cdot 0.08333333333333333\right)}\\ \end{array} \]
Alternative 10
Error31%
Cost972
\[\begin{array}{l} \mathbf{if}\;i \leq -0.000135:\\ \;\;\;\;-1 + \left(1 + \frac{n}{i} \cdot -200\right)\\ \mathbf{elif}\;i \leq 1.32 \cdot 10^{+71}:\\ \;\;\;\;n \cdot \left(100 + i \cdot \left(50 + i \cdot 16.666666666666668\right)\right)\\ \mathbf{elif}\;i \leq 6.2 \cdot 10^{+114}:\\ \;\;\;\;n \cdot \frac{-100}{1 + i \cdot -0.5}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{0}{\frac{i}{n}}\\ \end{array} \]
Alternative 11
Error29%
Cost968
\[\begin{array}{l} \mathbf{if}\;n \leq -1.96 \cdot 10^{-169}:\\ \;\;\;\;n \cdot \frac{1}{0.01 + i \cdot -0.005}\\ \mathbf{elif}\;n \leq 2.45 \cdot 10^{-222}:\\ \;\;\;\;100 \cdot \frac{0}{\frac{i}{n}}\\ \mathbf{else}:\\ \;\;\;\;\frac{n}{0.01 + i \cdot \left(-0.005 + i \cdot 0.0008333333333333334\right)}\\ \end{array} \]
Alternative 12
Error29.7%
Cost841
\[\begin{array}{l} \mathbf{if}\;n \leq -1.96 \cdot 10^{-169} \lor \neg \left(n \leq 3.4 \cdot 10^{-222}\right):\\ \;\;\;\;n \cdot \frac{1}{0.01 + i \cdot -0.005}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{0}{\frac{i}{n}}\\ \end{array} \]
Alternative 13
Error29.7%
Cost840
\[\begin{array}{l} \mathbf{if}\;n \leq -1.96 \cdot 10^{-169}:\\ \;\;\;\;n \cdot \frac{1}{0.01 + i \cdot -0.005}\\ \mathbf{elif}\;n \leq 2.25 \cdot 10^{-222}:\\ \;\;\;\;100 \cdot \frac{0}{\frac{i}{n}}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{n}{1 + i \cdot -0.5}\\ \end{array} \]
Alternative 14
Error29.7%
Cost713
\[\begin{array}{l} \mathbf{if}\;n \leq -1.96 \cdot 10^{-169} \lor \neg \left(n \leq 6.6 \cdot 10^{-211}\right):\\ \;\;\;\;\frac{n}{0.01 + i \cdot -0.005}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{0}{\frac{i}{n}}\\ \end{array} \]
Alternative 15
Error33.06%
Cost712
\[\begin{array}{l} \mathbf{if}\;i \leq -1.6:\\ \;\;\;\;\frac{n}{i} \cdot -200\\ \mathbf{elif}\;i \leq 1.35 \cdot 10^{+92}:\\ \;\;\;\;n \cdot \left(100 + i \cdot 50\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{-200}{\frac{i}{n}}\\ \end{array} \]
Alternative 16
Error33.51%
Cost585
\[\begin{array}{l} \mathbf{if}\;i \leq -2 \lor \neg \left(i \leq 1.35 \cdot 10^{+92}\right):\\ \;\;\;\;\frac{n}{i} \cdot -200\\ \mathbf{else}:\\ \;\;\;\;n \cdot 100\\ \end{array} \]
Alternative 17
Error33.41%
Cost584
\[\begin{array}{l} \mathbf{if}\;i \leq -2:\\ \;\;\;\;\frac{n}{i} \cdot -200\\ \mathbf{elif}\;i \leq 1.35 \cdot 10^{+92}:\\ \;\;\;\;n \cdot 100\\ \mathbf{else}:\\ \;\;\;\;\frac{-200}{\frac{i}{n}}\\ \end{array} \]
Alternative 18
Error32.86%
Cost448
\[\frac{n}{0.01 + i \cdot -0.005} \]
Alternative 19
Error96.98%
Cost192
\[i \cdot -50 \]
Alternative 20
Error43.96%
Cost192
\[n \cdot 100 \]

Error

Reproduce?

herbie shell --seed 2023089 
(FPCore (i n)
  :name "Compound Interest"
  :precision binary64

  :herbie-target
  (* 100.0 (/ (- (exp (* n (if (== (+ 1.0 (/ i n)) 1.0) (/ i n) (/ (* (/ i n) (log (+ 1.0 (/ i n)))) (- (+ (/ i n) 1.0) 1.0))))) 1.0) (/ i n)))

  (* 100.0 (/ (- (pow (+ 1.0 (/ i n)) n) 1.0) (/ i n))))