?

Average Error: 23.66% → 0.59%
Time: 7.2s
Precision: binary64
Cost: 7168

?

\[\tan^{-1} \left(N + 1\right) - \tan^{-1} N \]
\[\tan^{-1}_* \frac{1 + \left(N - N\right)}{1 + N \cdot \left(1 + N\right)} \]
(FPCore (N) :precision binary64 (- (atan (+ N 1.0)) (atan N)))
(FPCore (N)
 :precision binary64
 (atan2 (+ 1.0 (- N N)) (+ 1.0 (* N (+ 1.0 N)))))
double code(double N) {
	return atan((N + 1.0)) - atan(N);
}
double code(double N) {
	return atan2((1.0 + (N - N)), (1.0 + (N * (1.0 + N))));
}
real(8) function code(n)
    real(8), intent (in) :: n
    code = atan((n + 1.0d0)) - atan(n)
end function
real(8) function code(n)
    real(8), intent (in) :: n
    code = atan2((1.0d0 + (n - n)), (1.0d0 + (n * (1.0d0 + n))))
end function
public static double code(double N) {
	return Math.atan((N + 1.0)) - Math.atan(N);
}
public static double code(double N) {
	return Math.atan2((1.0 + (N - N)), (1.0 + (N * (1.0 + N))));
}
def code(N):
	return math.atan((N + 1.0)) - math.atan(N)
def code(N):
	return math.atan2((1.0 + (N - N)), (1.0 + (N * (1.0 + N))))
function code(N)
	return Float64(atan(Float64(N + 1.0)) - atan(N))
end
function code(N)
	return atan(Float64(1.0 + Float64(N - N)), Float64(1.0 + Float64(N * Float64(1.0 + N))))
end
function tmp = code(N)
	tmp = atan((N + 1.0)) - atan(N);
end
function tmp = code(N)
	tmp = atan2((1.0 + (N - N)), (1.0 + (N * (1.0 + N))));
end
code[N_] := N[(N[ArcTan[N[(N + 1.0), $MachinePrecision]], $MachinePrecision] - N[ArcTan[N], $MachinePrecision]), $MachinePrecision]
code[N_] := N[ArcTan[N[(1.0 + N[(N - N), $MachinePrecision]), $MachinePrecision] / N[(1.0 + N[(N * N[(1.0 + N), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\tan^{-1} \left(N + 1\right) - \tan^{-1} N
\tan^{-1}_* \frac{1 + \left(N - N\right)}{1 + N \cdot \left(1 + N\right)}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original23.66%
Target0.59%
Herbie0.59%
\[\tan^{-1} \left(\frac{1}{1 + N \cdot \left(N + 1\right)}\right) \]

Derivation?

  1. Initial program 23.66

    \[\tan^{-1} \left(N + 1\right) - \tan^{-1} N \]
  2. Applied egg-rr22.04

    \[\leadsto \color{blue}{\tan^{-1}_* \frac{N + \left(1 - N\right)}{\left(N + 1\right) + N \cdot N}} \]
  3. Simplified0.59

    \[\leadsto \color{blue}{\tan^{-1}_* \frac{1 + \left(N - N\right)}{\mathsf{fma}\left(N, N, 1 + N\right)}} \]
    Proof

    [Start]22.04

    \[ \tan^{-1}_* \frac{N + \left(1 - N\right)}{\left(N + 1\right) + N \cdot N} \]

    associate-+r- [=>]22.03

    \[ \tan^{-1}_* \frac{\color{blue}{\left(N + 1\right) - N}}{\left(N + 1\right) + N \cdot N} \]

    +-commutative [=>]22.03

    \[ \tan^{-1}_* \frac{\color{blue}{\left(1 + N\right)} - N}{\left(N + 1\right) + N \cdot N} \]

    associate--l+ [=>]0.59

    \[ \tan^{-1}_* \frac{\color{blue}{1 + \left(N - N\right)}}{\left(N + 1\right) + N \cdot N} \]

    +-commutative [=>]0.59

    \[ \tan^{-1}_* \frac{1 + \left(N - N\right)}{\color{blue}{N \cdot N + \left(N + 1\right)}} \]

    fma-def [=>]0.59

    \[ \tan^{-1}_* \frac{1 + \left(N - N\right)}{\color{blue}{\mathsf{fma}\left(N, N, N + 1\right)}} \]

    +-commutative [=>]0.59

    \[ \tan^{-1}_* \frac{1 + \left(N - N\right)}{\mathsf{fma}\left(N, N, \color{blue}{1 + N}\right)} \]
  4. Applied egg-rr0.59

    \[\leadsto \tan^{-1}_* \frac{1 + \left(N - N\right)}{\color{blue}{\left(N \cdot N + N\right) + 1}} \]
  5. Applied egg-rr0.59

    \[\leadsto \tan^{-1}_* \frac{1 + \left(N - N\right)}{\color{blue}{\left(1 + N\right) \cdot N} + 1} \]
  6. Final simplification0.59

    \[\leadsto \tan^{-1}_* \frac{1 + \left(N - N\right)}{1 + N \cdot \left(1 + N\right)} \]

Alternatives

Alternative 1
Error2.82%
Cost6921
\[\begin{array}{l} \mathbf{if}\;N \leq -1 \lor \neg \left(N \leq 1\right):\\ \;\;\;\;\tan^{-1}_* \frac{1}{N \cdot N}\\ \mathbf{else}:\\ \;\;\;\;\tan^{-1}_* \frac{1}{1}\\ \end{array} \]
Alternative 2
Error2.23%
Cost6921
\[\begin{array}{l} \mathbf{if}\;N \leq -0.62 \lor \neg \left(N \leq 1.6\right):\\ \;\;\;\;\tan^{-1}_* \frac{1}{N \cdot N}\\ \mathbf{else}:\\ \;\;\;\;\tan^{-1}_* \frac{1}{1 + N}\\ \end{array} \]
Alternative 3
Error1.97%
Cost6920
\[\begin{array}{l} \mathbf{if}\;N \leq -1:\\ \;\;\;\;\tan^{-1}_* \frac{1}{N + N \cdot N}\\ \mathbf{elif}\;N \leq 1.6:\\ \;\;\;\;\tan^{-1}_* \frac{1}{1 + N}\\ \mathbf{else}:\\ \;\;\;\;\tan^{-1}_* \frac{1}{N \cdot N}\\ \end{array} \]
Alternative 4
Error0.59%
Cost6912
\[\tan^{-1}_* \frac{1}{1 + \left(N + N \cdot N\right)} \]
Alternative 5
Error49.77%
Cost6528
\[\tan^{-1}_* \frac{1}{1} \]

Error

Reproduce?

herbie shell --seed 2023088 
(FPCore (N)
  :name "2atan (example 3.5)"
  :precision binary64

  :herbie-target
  (atan (/ 1.0 (+ 1.0 (* N (+ N 1.0)))))

  (- (atan (+ N 1.0)) (atan N)))