?

Average Error: 41.0 → 0.4
Time: 13.1s
Precision: binary64
Cost: 33476

?

\[\sqrt{\frac{e^{2 \cdot x} - 1}{e^{x} - 1}} \]
\[\begin{array}{l} t_0 := \frac{e^{2 \cdot x} - 1}{e^{x} - 1}\\ \mathbf{if}\;t_0 \leq 1.5:\\ \;\;\;\;\sqrt{t_0}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{{x}^{2} \cdot 0.5 + \left(\left(2 + x\right) + {x}^{3} \cdot 0.16666666666666666\right)}\\ \end{array} \]
(FPCore (x)
 :precision binary64
 (sqrt (/ (- (exp (* 2.0 x)) 1.0) (- (exp x) 1.0))))
(FPCore (x)
 :precision binary64
 (let* ((t_0 (/ (- (exp (* 2.0 x)) 1.0) (- (exp x) 1.0))))
   (if (<= t_0 1.5)
     (sqrt t_0)
     (sqrt
      (+
       (* (pow x 2.0) 0.5)
       (+ (+ 2.0 x) (* (pow x 3.0) 0.16666666666666666)))))))
double code(double x) {
	return sqrt(((exp((2.0 * x)) - 1.0) / (exp(x) - 1.0)));
}
double code(double x) {
	double t_0 = (exp((2.0 * x)) - 1.0) / (exp(x) - 1.0);
	double tmp;
	if (t_0 <= 1.5) {
		tmp = sqrt(t_0);
	} else {
		tmp = sqrt(((pow(x, 2.0) * 0.5) + ((2.0 + x) + (pow(x, 3.0) * 0.16666666666666666))));
	}
	return tmp;
}
real(8) function code(x)
    real(8), intent (in) :: x
    code = sqrt(((exp((2.0d0 * x)) - 1.0d0) / (exp(x) - 1.0d0)))
end function
real(8) function code(x)
    real(8), intent (in) :: x
    real(8) :: t_0
    real(8) :: tmp
    t_0 = (exp((2.0d0 * x)) - 1.0d0) / (exp(x) - 1.0d0)
    if (t_0 <= 1.5d0) then
        tmp = sqrt(t_0)
    else
        tmp = sqrt((((x ** 2.0d0) * 0.5d0) + ((2.0d0 + x) + ((x ** 3.0d0) * 0.16666666666666666d0))))
    end if
    code = tmp
end function
public static double code(double x) {
	return Math.sqrt(((Math.exp((2.0 * x)) - 1.0) / (Math.exp(x) - 1.0)));
}
public static double code(double x) {
	double t_0 = (Math.exp((2.0 * x)) - 1.0) / (Math.exp(x) - 1.0);
	double tmp;
	if (t_0 <= 1.5) {
		tmp = Math.sqrt(t_0);
	} else {
		tmp = Math.sqrt(((Math.pow(x, 2.0) * 0.5) + ((2.0 + x) + (Math.pow(x, 3.0) * 0.16666666666666666))));
	}
	return tmp;
}
def code(x):
	return math.sqrt(((math.exp((2.0 * x)) - 1.0) / (math.exp(x) - 1.0)))
def code(x):
	t_0 = (math.exp((2.0 * x)) - 1.0) / (math.exp(x) - 1.0)
	tmp = 0
	if t_0 <= 1.5:
		tmp = math.sqrt(t_0)
	else:
		tmp = math.sqrt(((math.pow(x, 2.0) * 0.5) + ((2.0 + x) + (math.pow(x, 3.0) * 0.16666666666666666))))
	return tmp
function code(x)
	return sqrt(Float64(Float64(exp(Float64(2.0 * x)) - 1.0) / Float64(exp(x) - 1.0)))
end
function code(x)
	t_0 = Float64(Float64(exp(Float64(2.0 * x)) - 1.0) / Float64(exp(x) - 1.0))
	tmp = 0.0
	if (t_0 <= 1.5)
		tmp = sqrt(t_0);
	else
		tmp = sqrt(Float64(Float64((x ^ 2.0) * 0.5) + Float64(Float64(2.0 + x) + Float64((x ^ 3.0) * 0.16666666666666666))));
	end
	return tmp
end
function tmp = code(x)
	tmp = sqrt(((exp((2.0 * x)) - 1.0) / (exp(x) - 1.0)));
end
function tmp_2 = code(x)
	t_0 = (exp((2.0 * x)) - 1.0) / (exp(x) - 1.0);
	tmp = 0.0;
	if (t_0 <= 1.5)
		tmp = sqrt(t_0);
	else
		tmp = sqrt((((x ^ 2.0) * 0.5) + ((2.0 + x) + ((x ^ 3.0) * 0.16666666666666666))));
	end
	tmp_2 = tmp;
end
code[x_] := N[Sqrt[N[(N[(N[Exp[N[(2.0 * x), $MachinePrecision]], $MachinePrecision] - 1.0), $MachinePrecision] / N[(N[Exp[x], $MachinePrecision] - 1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
code[x_] := Block[{t$95$0 = N[(N[(N[Exp[N[(2.0 * x), $MachinePrecision]], $MachinePrecision] - 1.0), $MachinePrecision] / N[(N[Exp[x], $MachinePrecision] - 1.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, 1.5], N[Sqrt[t$95$0], $MachinePrecision], N[Sqrt[N[(N[(N[Power[x, 2.0], $MachinePrecision] * 0.5), $MachinePrecision] + N[(N[(2.0 + x), $MachinePrecision] + N[(N[Power[x, 3.0], $MachinePrecision] * 0.16666666666666666), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]]]
\sqrt{\frac{e^{2 \cdot x} - 1}{e^{x} - 1}}
\begin{array}{l}
t_0 := \frac{e^{2 \cdot x} - 1}{e^{x} - 1}\\
\mathbf{if}\;t_0 \leq 1.5:\\
\;\;\;\;\sqrt{t_0}\\

\mathbf{else}:\\
\;\;\;\;\sqrt{{x}^{2} \cdot 0.5 + \left(\left(2 + x\right) + {x}^{3} \cdot 0.16666666666666666\right)}\\


\end{array}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation?

  1. Split input into 2 regimes
  2. if (/.f64 (-.f64 (exp.f64 (*.f64 2 x)) 1) (-.f64 (exp.f64 x) 1)) < 1.5

    1. Initial program 0.1

      \[\sqrt{\frac{e^{2 \cdot x} - 1}{e^{x} - 1}} \]

    if 1.5 < (/.f64 (-.f64 (exp.f64 (*.f64 2 x)) 1) (-.f64 (exp.f64 x) 1))

    1. Initial program 61.4

      \[\sqrt{\frac{e^{2 \cdot x} - 1}{e^{x} - 1}} \]
    2. Taylor expanded in x around 0 0.5

      \[\leadsto \sqrt{\color{blue}{0.16666666666666666 \cdot {x}^{3} + \left(2 + \left(0.5 \cdot {x}^{2} + x\right)\right)}} \]
    3. Simplified0.5

      \[\leadsto \sqrt{\color{blue}{{x}^{2} \cdot 0.5 + \left(\left(2 + x\right) + {x}^{3} \cdot 0.16666666666666666\right)}} \]
      Proof

      [Start]0.5

      \[ \sqrt{0.16666666666666666 \cdot {x}^{3} + \left(2 + \left(0.5 \cdot {x}^{2} + x\right)\right)} \]

      rational.json-simplify-41 [=>]0.5

      \[ \sqrt{0.16666666666666666 \cdot {x}^{3} + \color{blue}{\left(0.5 \cdot {x}^{2} + \left(x + 2\right)\right)}} \]

      rational.json-simplify-1 [<=]0.5

      \[ \sqrt{0.16666666666666666 \cdot {x}^{3} + \left(0.5 \cdot {x}^{2} + \color{blue}{\left(2 + x\right)}\right)} \]

      rational.json-simplify-41 [=>]0.5

      \[ \sqrt{\color{blue}{0.5 \cdot {x}^{2} + \left(\left(2 + x\right) + 0.16666666666666666 \cdot {x}^{3}\right)}} \]

      rational.json-simplify-2 [=>]0.5

      \[ \sqrt{\color{blue}{{x}^{2} \cdot 0.5} + \left(\left(2 + x\right) + 0.16666666666666666 \cdot {x}^{3}\right)} \]

      rational.json-simplify-2 [=>]0.5

      \[ \sqrt{{x}^{2} \cdot 0.5 + \left(\left(2 + x\right) + \color{blue}{{x}^{3} \cdot 0.16666666666666666}\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification0.4

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{e^{2 \cdot x} - 1}{e^{x} - 1} \leq 1.5:\\ \;\;\;\;\sqrt{\frac{e^{2 \cdot x} - 1}{e^{x} - 1}}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{{x}^{2} \cdot 0.5 + \left(\left(2 + x\right) + {x}^{3} \cdot 0.16666666666666666\right)}\\ \end{array} \]

Alternatives

Alternative 1
Error0.4
Cost33220
\[\begin{array}{l} t_0 := \frac{e^{2 \cdot x} - 1}{e^{x} - 1}\\ \mathbf{if}\;t_0 \leq 1.5:\\ \;\;\;\;\sqrt{t_0}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{{x}^{2} \cdot 0.5 + \left(2 + x\right)}\\ \end{array} \]
Alternative 2
Error17.8
Cost6464
\[\sqrt{2} \]

Error

Reproduce?

herbie shell --seed 2023075 
(FPCore (x)
  :name "sqrtexp (problem 3.4.4)"
  :precision binary64
  (sqrt (/ (- (exp (* 2.0 x)) 1.0) (- (exp x) 1.0))))