Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}
\]
↓
\[{k}^{m} \cdot \frac{a}{1 + k \cdot \left(k + 10\right)}
\]
(FPCore (a k m)
:precision binary64
(/ (* a (pow k m)) (+ (+ 1.0 (* 10.0 k)) (* k k)))) ↓
(FPCore (a k m)
:precision binary64
(* (pow k m) (/ a (+ 1.0 (* k (+ k 10.0)))))) double code(double a, double k, double m) {
return (a * pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k));
}
↓
double code(double a, double k, double m) {
return pow(k, m) * (a / (1.0 + (k * (k + 10.0))));
}
real(8) function code(a, k, m)
real(8), intent (in) :: a
real(8), intent (in) :: k
real(8), intent (in) :: m
code = (a * (k ** m)) / ((1.0d0 + (10.0d0 * k)) + (k * k))
end function
↓
real(8) function code(a, k, m)
real(8), intent (in) :: a
real(8), intent (in) :: k
real(8), intent (in) :: m
code = (k ** m) * (a / (1.0d0 + (k * (k + 10.0d0))))
end function
public static double code(double a, double k, double m) {
return (a * Math.pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k));
}
↓
public static double code(double a, double k, double m) {
return Math.pow(k, m) * (a / (1.0 + (k * (k + 10.0))));
}
def code(a, k, m):
return (a * math.pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k))
↓
def code(a, k, m):
return math.pow(k, m) * (a / (1.0 + (k * (k + 10.0))))
function code(a, k, m)
return Float64(Float64(a * (k ^ m)) / Float64(Float64(1.0 + Float64(10.0 * k)) + Float64(k * k)))
end
↓
function code(a, k, m)
return Float64((k ^ m) * Float64(a / Float64(1.0 + Float64(k * Float64(k + 10.0)))))
end
function tmp = code(a, k, m)
tmp = (a * (k ^ m)) / ((1.0 + (10.0 * k)) + (k * k));
end
↓
function tmp = code(a, k, m)
tmp = (k ^ m) * (a / (1.0 + (k * (k + 10.0))));
end
code[a_, k_, m_] := N[(N[(a * N[Power[k, m], $MachinePrecision]), $MachinePrecision] / N[(N[(1.0 + N[(10.0 * k), $MachinePrecision]), $MachinePrecision] + N[(k * k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[a_, k_, m_] := N[(N[Power[k, m], $MachinePrecision] * N[(a / N[(1.0 + N[(k * N[(k + 10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}
↓
{k}^{m} \cdot \frac{a}{1 + k \cdot \left(k + 10\right)}
Alternatives Alternative 1 Error 8.3 Cost 7304
\[\begin{array}{l}
t_0 := a \cdot \frac{{k}^{m}}{1 + 10 \cdot k}\\
t_1 := 1 + k \cdot 10\\
\mathbf{if}\;m \leq -9.2 \cdot 10^{-18}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;m \leq 7.8 \cdot 10^{-38}:\\
\;\;\;\;\frac{2 + k \cdot 20}{t_1 \cdot \left(t_1 \cdot \frac{2}{a}\right)}\\
\mathbf{else}:\\
\;\;\;\;t_0\\
\end{array}
\]
Alternative 2 Error 8.4 Cost 6920
\[\begin{array}{l}
t_0 := 1 + k \cdot 10\\
t_1 := {k}^{m} \cdot a\\
\mathbf{if}\;m \leq -105:\\
\;\;\;\;t_1\\
\mathbf{elif}\;m \leq 0.052:\\
\;\;\;\;\frac{2 + k \cdot 20}{t_0 \cdot \left(t_0 \cdot \frac{2}{a}\right)}\\
\mathbf{else}:\\
\;\;\;\;t_1\\
\end{array}
\]
Alternative 3 Error 29.1 Cost 2000
\[\begin{array}{l}
t_0 := 2 + k \cdot 20\\
t_1 := 1 + k \cdot 10\\
t_2 := \frac{t_0}{a \cdot \left(\frac{t_1}{a} \cdot \frac{t_0}{a}\right)}\\
t_3 := a \cdot \frac{t_1}{t_1 \cdot t_1}\\
\mathbf{if}\;a \leq -5 \cdot 10^{-22}:\\
\;\;\;\;t_3\\
\mathbf{elif}\;a \leq -1 \cdot 10^{-273}:\\
\;\;\;\;t_2\\
\mathbf{elif}\;a \leq 6.5 \cdot 10^{-226}:\\
\;\;\;\;\frac{8}{\frac{t_1 \cdot 8}{a}}\\
\mathbf{elif}\;a \leq 1.38 \cdot 10^{-167}:\\
\;\;\;\;t_2\\
\mathbf{else}:\\
\;\;\;\;t_3\\
\end{array}
\]
Alternative 4 Error 28.9 Cost 2000
\[\begin{array}{l}
t_0 := 1 + k \cdot 10\\
t_1 := 2 + k \cdot 20\\
t_2 := \frac{t_1}{a \cdot \left(\frac{t_0}{a} \cdot \frac{t_1}{a}\right)}\\
\mathbf{if}\;a \leq -1 \cdot 10^{+114}:\\
\;\;\;\;t_1 \cdot \frac{\frac{a}{\frac{t_1}{\frac{2}{a}}}}{t_0 \cdot \frac{2}{a}}\\
\mathbf{elif}\;a \leq -4.5 \cdot 10^{-273}:\\
\;\;\;\;t_2\\
\mathbf{elif}\;a \leq 6.5 \cdot 10^{-226}:\\
\;\;\;\;\frac{8}{\frac{t_0 \cdot 8}{a}}\\
\mathbf{elif}\;a \leq 6.1 \cdot 10^{-167}:\\
\;\;\;\;t_2\\
\mathbf{else}:\\
\;\;\;\;a \cdot \frac{t_0}{t_0 \cdot t_0}\\
\end{array}
\]
Alternative 5 Error 31.4 Cost 1344
\[\begin{array}{l}
t_0 := 1 + k \cdot 10\\
\frac{2 + k \cdot 20}{t_0 \cdot \left(t_0 \cdot \frac{2}{a}\right)}
\end{array}
\]
Alternative 6 Error 31.3 Cost 1216
\[\begin{array}{l}
t_0 := 1 + k \cdot 10\\
a \cdot \frac{t_0}{t_0 \cdot t_0}
\end{array}
\]
Alternative 7 Error 38.8 Cost 704
\[\frac{8}{\frac{\left(1 + k \cdot 10\right) \cdot 8}{a}}
\]
Alternative 8 Error 39.3 Cost 584
\[\begin{array}{l}
t_0 := 0.1 \cdot \frac{a}{k}\\
\mathbf{if}\;k \leq -0.1:\\
\;\;\;\;t_0\\
\mathbf{elif}\;k \leq 0.1:\\
\;\;\;\;a\\
\mathbf{else}:\\
\;\;\;\;t_0\\
\end{array}
\]
Alternative 9 Error 39.3 Cost 584
\[\begin{array}{l}
\mathbf{if}\;k \leq -0.1:\\
\;\;\;\;0.1 \cdot \frac{a}{k}\\
\mathbf{elif}\;k \leq 0.1:\\
\;\;\;\;a\\
\mathbf{else}:\\
\;\;\;\;a \cdot \frac{0.1}{k}\\
\end{array}
\]
Alternative 10 Error 39.2 Cost 584
\[\begin{array}{l}
\mathbf{if}\;k \leq -0.1:\\
\;\;\;\;0.1 \cdot \frac{a}{k}\\
\mathbf{elif}\;k \leq 0.1:\\
\;\;\;\;a\\
\mathbf{else}:\\
\;\;\;\;\frac{a}{k \cdot 10}\\
\end{array}
\]
Alternative 11 Error 38.8 Cost 576
\[\frac{2}{\frac{2 + k \cdot 20}{a}}
\]
Alternative 12 Error 39.1 Cost 448
\[\frac{a}{1 + k \cdot 10}
\]
Alternative 13 Error 46.8 Cost 64
\[a
\]