Linear.Quaternion:$ctan from linear-1.19.1.3

Average Error: 7.7 → 0.3

Time: 13.3s

Precision: binary64

Cost: 20424

Math

\[\frac{\cosh x \cdot \frac{y}{x}}{z} \]

↓

\[\begin{array}{l} t_0 := \cosh x \cdot \frac{y}{x}\\ \mathbf{if}\;t_0 \leq -1 \cdot 10^{+260}:\\ \;\;\;\;\frac{y}{x \cdot z}\\ \mathbf{elif}\;t_0 \leq 5 \cdot 10^{+282}:\\ \;\;\;\;\frac{t_0}{z}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{1}{x}}{\frac{z}{y}}\\ \end{array} \]

FPCore

(FPCore (x y z) :precision binary64 (/ (* (cosh x) (/ y x)) z))

↓

(FPCore (x y z)
 :precision binary64
 (let* ((t_0 (* (cosh x) (/ y x))))
   (if (<= t_0 -1e+260)
     (/ y (* x z))
     (if (<= t_0 5e+282) (/ t_0 z) (/ (/ 1.0 x) (/ z y))))))

C

double code(double x, double y, double z) {
	return (cosh(x) * (y / x)) / z;
}

↓

double code(double x, double y, double z) {
	double t_0 = cosh(x) * (y / x);
	double tmp;
	if (t_0 <= -1e+260) {
		tmp = y / (x * z);
	} else if (t_0 <= 5e+282) {
		tmp = t_0 / z;
	} else {
		tmp = (1.0 / x) / (z / y);
	}
	return tmp;
}

Fortran

real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = (cosh(x) * (y / x)) / z
end function

↓

real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: t_0
    real(8) :: tmp
    t_0 = cosh(x) * (y / x)
    if (t_0 <= (-1d+260)) then
        tmp = y / (x * z)
    else if (t_0 <= 5d+282) then
        tmp = t_0 / z
    else
        tmp = (1.0d0 / x) / (z / y)
    end if
    code = tmp
end function

Java

public static double code(double x, double y, double z) {
	return (Math.cosh(x) * (y / x)) / z;
}

↓

public static double code(double x, double y, double z) {
	double t_0 = Math.cosh(x) * (y / x);
	double tmp;
	if (t_0 <= -1e+260) {
		tmp = y / (x * z);
	} else if (t_0 <= 5e+282) {
		tmp = t_0 / z;
	} else {
		tmp = (1.0 / x) / (z / y);
	}
	return tmp;
}

Python

def code(x, y, z):
	return (math.cosh(x) * (y / x)) / z

↓

def code(x, y, z):
	t_0 = math.cosh(x) * (y / x)
	tmp = 0
	if t_0 <= -1e+260:
		tmp = y / (x * z)
	elif t_0 <= 5e+282:
		tmp = t_0 / z
	else:
		tmp = (1.0 / x) / (z / y)
	return tmp

Julia

function code(x, y, z)
	return Float64(Float64(cosh(x) * Float64(y / x)) / z)
end

↓

function code(x, y, z)
	t_0 = Float64(cosh(x) * Float64(y / x))
	tmp = 0.0
	if (t_0 <= -1e+260)
		tmp = Float64(y / Float64(x * z));
	elseif (t_0 <= 5e+282)
		tmp = Float64(t_0 / z);
	else
		tmp = Float64(Float64(1.0 / x) / Float64(z / y));
	end
	return tmp
end

MATLAB

function tmp = code(x, y, z)
	tmp = (cosh(x) * (y / x)) / z;
end

↓

function tmp_2 = code(x, y, z)
	t_0 = cosh(x) * (y / x);
	tmp = 0.0;
	if (t_0 <= -1e+260)
		tmp = y / (x * z);
	elseif (t_0 <= 5e+282)
		tmp = t_0 / z;
	else
		tmp = (1.0 / x) / (z / y);
	end
	tmp_2 = tmp;
end

Wolfram

code[x_, y_, z_] := N[(N[(N[Cosh[x], $MachinePrecision] * N[(y / x), $MachinePrecision]), $MachinePrecision] / z), $MachinePrecision]

↓

code[x_, y_, z_] := Block[{t$95$0 = N[(N[Cosh[x], $MachinePrecision] * N[(y / x), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -1e+260], N[(y / N[(x * z), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 5e+282], N[(t$95$0 / z), $MachinePrecision], N[(N[(1.0 / x), $MachinePrecision] / N[(z / y), $MachinePrecision]), $MachinePrecision]]]]

Target

Original	7.7
Target	0.4
Herbie	0.3

\[\begin{array}{l} \mathbf{if}\;y < -4.618902267687042 \cdot 10^{-52}:\\ \;\;\;\;\frac{\frac{y}{z}}{x} \cdot \cosh x\\ \mathbf{elif}\;y < 1.038530535935153 \cdot 10^{-39}:\\ \;\;\;\;\frac{\frac{\cosh x \cdot y}{x}}{z}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{y}{z}}{x} \cdot \cosh x\\ \end{array} \]

Derivation

1. Split input into 3 regimes

2. if (*.f64 (cosh.f64 x) (/.f64 y x)) < -1.00000000000000007e260

   1. Initial program 43.0

      \[\frac{\cosh x \cdot \frac{y}{x}}{z} \]

   2. Taylor expanded in x around 0 0.7

      \[\leadsto \color{blue}{\frac{y}{z \cdot x}} \]

   if -1.00000000000000007e260 < (*.f64 (cosh.f64 x) (/.f64 y x)) < 4.99999999999999978e282

   1. Initial program 0.2

      \[\frac{\cosh x \cdot \frac{y}{x}}{z} \]

   if 4.99999999999999978e282 < (*.f64 (cosh.f64 x) (/.f64 y x))

   1. Initial program 51.8

      \[\frac{\cosh x \cdot \frac{y}{x}}{z} \]

   2. Simplified 0.7

      \[\leadsto \color{blue}{\frac{\cosh x}{x} \cdot \frac{y}{z}} \]
      Proof

      [Start] 51.8	\[ \frac{\cosh x \cdot \frac{y}{x}}{z} \]
      associate-*r/ [=>] 51.8	\[ \frac{\color{blue}{\frac{\cosh x \cdot y}{x}}}{z} \]
      associate-/r* [<=] 0.8	\[ \color{blue}{\frac{\cosh x \cdot y}{x \cdot z}} \]
      times-frac [=>] 0.7	\[ \color{blue}{\frac{\cosh x}{x} \cdot \frac{y}{z}} \]

   3. Taylor expanded in x around 0 1.0

      \[\leadsto \color{blue}{\frac{1}{x}} \cdot \frac{y}{z} \]

   4. Applied egg-rr 0.9

      \[\leadsto \color{blue}{\frac{\frac{1}{x}}{\frac{z}{y}}} \]
3. Recombined 3 regimes into one program.

4. Final simplification 0.3

   \[\leadsto \begin{array}{l} \mathbf{if}\;\cosh x \cdot \frac{y}{x} \leq -1 \cdot 10^{+260}:\\ \;\;\;\;\frac{y}{x \cdot z}\\ \mathbf{elif}\;\cosh x \cdot \frac{y}{x} \leq 5 \cdot 10^{+282}:\\ \;\;\;\;\frac{\cosh x \cdot \frac{y}{x}}{z}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{1}{x}}{\frac{z}{y}}\\ \end{array} \]

Alternatives

Alternative 1
Error	1.0
Cost	7113

\[\begin{array}{l} \mathbf{if}\;z \leq -9.5 \cdot 10^{+95} \lor \neg \left(z \leq 2.45 \cdot 10^{+64}\right):\\ \;\;\;\;y \cdot \left(\frac{x \cdot 0.5}{z} + \frac{1}{x \cdot z}\right)\\ \mathbf{else}:\\ \;\;\;\;\cosh x \cdot \frac{\frac{y}{z}}{x}\\ \end{array} \]

Alternative 2
Error	0.3
Cost	7113

\[\begin{array}{l} \mathbf{if}\;z \leq -5 \cdot 10^{-15} \lor \neg \left(z \leq 7 \cdot 10^{-7}\right):\\ \;\;\;\;\frac{\cosh x \cdot y}{x \cdot z}\\ \mathbf{else}:\\ \;\;\;\;\cosh x \cdot \frac{\frac{y}{z}}{x}\\ \end{array} \]

Alternative 3
Error	0.8
Cost	7112

\[\begin{array}{l} \mathbf{if}\;z \leq -9.5 \cdot 10^{+95}:\\ \;\;\;\;y \cdot \left(\frac{x \cdot 0.5}{z} + \frac{1}{x \cdot z}\right)\\ \mathbf{elif}\;z \leq 0.0006:\\ \;\;\;\;\cosh x \cdot \frac{\frac{y}{z}}{x}\\ \mathbf{else}:\\ \;\;\;\;y \cdot \frac{\cosh x}{x \cdot z}\\ \end{array} \]

Alternative 4
Error	1.5
Cost	1097

\[\begin{array}{l} \mathbf{if}\;y \leq -2.2 \cdot 10^{+84} \lor \neg \left(y \leq 0.00018\right):\\ \;\;\;\;y \cdot \left(\frac{x \cdot 0.5}{z} + \frac{1}{x \cdot z}\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{y}{x} + 0.5 \cdot \left(x \cdot y\right)}{z}\\ \end{array} \]

Alternative 5
Error	1.7
Cost	1096

\[\begin{array}{l} t_0 := \frac{1}{x} + x \cdot 0.5\\ \mathbf{if}\;y \leq -2.1 \cdot 10^{+84}:\\ \;\;\;\;\frac{y}{z} \cdot t_0\\ \mathbf{elif}\;y \leq 3.8 \cdot 10^{+64}:\\ \;\;\;\;\frac{\frac{y}{x} + 0.5 \cdot \left(x \cdot y\right)}{z}\\ \mathbf{else}:\\ \;\;\;\;y \cdot \left(t_0 \cdot \frac{1}{z}\right)\\ \end{array} \]

Alternative 6
Error	1.7
Cost	969

\[\begin{array}{l} \mathbf{if}\;z \leq -4.35 \cdot 10^{+95} \lor \neg \left(z \leq 2.4 \cdot 10^{+64}\right):\\ \;\;\;\;\frac{y}{x \cdot z}\\ \mathbf{else}:\\ \;\;\;\;\frac{y}{z} \cdot \left(\frac{1}{x} + x \cdot 0.5\right)\\ \end{array} \]

Alternative 7
Error	1.2
Cost	969

\[\begin{array}{l} t_0 := \frac{1}{x} + x \cdot 0.5\\ \mathbf{if}\;z \leq -1 \cdot 10^{-29} \lor \neg \left(z \leq 10^{-20}\right):\\ \;\;\;\;y \cdot \frac{t_0}{z}\\ \mathbf{else}:\\ \;\;\;\;\frac{y}{z} \cdot t_0\\ \end{array} \]

Alternative 8
Error	1.4
Cost	968

\[\begin{array}{l} t_0 := \frac{1}{x} + x \cdot 0.5\\ \mathbf{if}\;y \leq -1.55 \cdot 10^{+41}:\\ \;\;\;\;\frac{y}{z} \cdot t_0\\ \mathbf{elif}\;y \leq 5.8 \cdot 10^{-36}:\\ \;\;\;\;\frac{y \cdot t_0}{z}\\ \mathbf{else}:\\ \;\;\;\;y \cdot \frac{t_0}{z}\\ \end{array} \]

Alternative 9
Error	1.7
Cost	968

\[\begin{array}{l} t_0 := \frac{1}{x} + x \cdot 0.5\\ \mathbf{if}\;y \leq -2.8 \cdot 10^{+84}:\\ \;\;\;\;\frac{y}{z} \cdot t_0\\ \mathbf{elif}\;y \leq 10^{+65}:\\ \;\;\;\;\frac{\frac{y}{x} + 0.5 \cdot \left(x \cdot y\right)}{z}\\ \mathbf{else}:\\ \;\;\;\;y \cdot \frac{t_0}{z}\\ \end{array} \]

Alternative 10
Error	2.1
Cost	585

\[\begin{array}{l} \mathbf{if}\;y \leq -3.5 \cdot 10^{+84} \lor \neg \left(y \leq 2 \cdot 10^{-66}\right):\\ \;\;\;\;\frac{y}{x \cdot z}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{y}{x}}{z}\\ \end{array} \]

Alternative 11
Error	8.1
Cost	320

\[\frac{y}{x \cdot z} \]

Reproduce

herbie shell --seed 2023066 
(FPCore (x y z)
  :name "Linear.Quaternion:$ctan from linear-1.19.1.3"
  :precision binary64

  :herbie-target
  (if (< y -4.618902267687042e-52) (* (/ (/ y z) x) (cosh x)) (if (< y 1.038530535935153e-39) (/ (/ (* (cosh x) y) x) z) (* (/ (/ y z) x) (cosh x))))

  (/ (* (cosh x) (/ y x)) z))