\[\frac{\tan \left(\frac{x}{y \cdot 2}\right)}{\sin \left(\frac{x}{y \cdot 2}\right)}
\]
↓
\[\begin{array}{l}
t_0 := {\left(\sqrt[3]{y}\right)}^{2}\\
t_1 := \frac{x}{y \cdot 2}\\
\mathbf{if}\;\frac{\tan t_1}{\sin t_1} \leq 3.5:\\
\;\;\;\;\frac{1}{\cos \left(\frac{\frac{\frac{x}{\frac{t_0}{0.5}}}{\sqrt[3]{t_0}}}{\sqrt[3]{\sqrt[3]{y}}}\right)}\\
\mathbf{else}:\\
\;\;\;\;1\\
\end{array}
\]
(FPCore (x y)
:precision binary64
(/ (tan (/ x (* y 2.0))) (sin (/ x (* y 2.0)))))
↓
(FPCore (x y)
:precision binary64
(let* ((t_0 (pow (cbrt y) 2.0)) (t_1 (/ x (* y 2.0))))
(if (<= (/ (tan t_1) (sin t_1)) 3.5)
(/ 1.0 (cos (/ (/ (/ x (/ t_0 0.5)) (cbrt t_0)) (cbrt (cbrt y)))))
1.0)))double code(double x, double y) {
return tan((x / (y * 2.0))) / sin((x / (y * 2.0)));
}
↓
double code(double x, double y) {
double t_0 = pow(cbrt(y), 2.0);
double t_1 = x / (y * 2.0);
double tmp;
if ((tan(t_1) / sin(t_1)) <= 3.5) {
tmp = 1.0 / cos((((x / (t_0 / 0.5)) / cbrt(t_0)) / cbrt(cbrt(y))));
} else {
tmp = 1.0;
}
return tmp;
}
public static double code(double x, double y) {
return Math.tan((x / (y * 2.0))) / Math.sin((x / (y * 2.0)));
}
↓
public static double code(double x, double y) {
double t_0 = Math.pow(Math.cbrt(y), 2.0);
double t_1 = x / (y * 2.0);
double tmp;
if ((Math.tan(t_1) / Math.sin(t_1)) <= 3.5) {
tmp = 1.0 / Math.cos((((x / (t_0 / 0.5)) / Math.cbrt(t_0)) / Math.cbrt(Math.cbrt(y))));
} else {
tmp = 1.0;
}
return tmp;
}
function code(x, y)
return Float64(tan(Float64(x / Float64(y * 2.0))) / sin(Float64(x / Float64(y * 2.0))))
end
↓
function code(x, y)
t_0 = cbrt(y) ^ 2.0
t_1 = Float64(x / Float64(y * 2.0))
tmp = 0.0
if (Float64(tan(t_1) / sin(t_1)) <= 3.5)
tmp = Float64(1.0 / cos(Float64(Float64(Float64(x / Float64(t_0 / 0.5)) / cbrt(t_0)) / cbrt(cbrt(y)))));
else
tmp = 1.0;
end
return tmp
end
code[x_, y_] := N[(N[Tan[N[(x / N[(y * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[Sin[N[(x / N[(y * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_] := Block[{t$95$0 = N[Power[N[Power[y, 1/3], $MachinePrecision], 2.0], $MachinePrecision]}, Block[{t$95$1 = N[(x / N[(y * 2.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[(N[Tan[t$95$1], $MachinePrecision] / N[Sin[t$95$1], $MachinePrecision]), $MachinePrecision], 3.5], N[(1.0 / N[Cos[N[(N[(N[(x / N[(t$95$0 / 0.5), $MachinePrecision]), $MachinePrecision] / N[Power[t$95$0, 1/3], $MachinePrecision]), $MachinePrecision] / N[Power[N[Power[y, 1/3], $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 1.0]]]
\frac{\tan \left(\frac{x}{y \cdot 2}\right)}{\sin \left(\frac{x}{y \cdot 2}\right)}
↓
\begin{array}{l}
t_0 := {\left(\sqrt[3]{y}\right)}^{2}\\
t_1 := \frac{x}{y \cdot 2}\\
\mathbf{if}\;\frac{\tan t_1}{\sin t_1} \leq 3.5:\\
\;\;\;\;\frac{1}{\cos \left(\frac{\frac{\frac{x}{\frac{t_0}{0.5}}}{\sqrt[3]{t_0}}}{\sqrt[3]{\sqrt[3]{y}}}\right)}\\
\mathbf{else}:\\
\;\;\;\;1\\
\end{array}