\[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}
\]
↓
\[\begin{array}{l}
t_0 := {\left(1 + \frac{i}{n}\right)}^{n} + -1\\
t_1 := \frac{t_0}{\frac{i}{n}}\\
\mathbf{if}\;t_1 \leq 0:\\
\;\;\;\;\frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right) \cdot 100}{\frac{i}{n}}\\
\mathbf{elif}\;t_1 \leq 100000000000:\\
\;\;\;\;\frac{100 \cdot \left(n \cdot t_0\right)}{i}\\
\mathbf{else}:\\
\;\;\;\;-1 + \left(1 + n \cdot 100\right)\\
\end{array}
\]
(FPCore (i n)
:precision binary64
(* 100.0 (/ (- (pow (+ 1.0 (/ i n)) n) 1.0) (/ i n))))
↓
(FPCore (i n)
:precision binary64
(let* ((t_0 (+ (pow (+ 1.0 (/ i n)) n) -1.0)) (t_1 (/ t_0 (/ i n))))
(if (<= t_1 0.0)
(/ (* (expm1 (* n (log1p (/ i n)))) 100.0) (/ i n))
(if (<= t_1 100000000000.0)
(/ (* 100.0 (* n t_0)) i)
(+ -1.0 (+ 1.0 (* n 100.0)))))))double code(double i, double n) {
return 100.0 * ((pow((1.0 + (i / n)), n) - 1.0) / (i / n));
}
↓
double code(double i, double n) {
double t_0 = pow((1.0 + (i / n)), n) + -1.0;
double t_1 = t_0 / (i / n);
double tmp;
if (t_1 <= 0.0) {
tmp = (expm1((n * log1p((i / n)))) * 100.0) / (i / n);
} else if (t_1 <= 100000000000.0) {
tmp = (100.0 * (n * t_0)) / i;
} else {
tmp = -1.0 + (1.0 + (n * 100.0));
}
return tmp;
}
public static double code(double i, double n) {
return 100.0 * ((Math.pow((1.0 + (i / n)), n) - 1.0) / (i / n));
}
↓
public static double code(double i, double n) {
double t_0 = Math.pow((1.0 + (i / n)), n) + -1.0;
double t_1 = t_0 / (i / n);
double tmp;
if (t_1 <= 0.0) {
tmp = (Math.expm1((n * Math.log1p((i / n)))) * 100.0) / (i / n);
} else if (t_1 <= 100000000000.0) {
tmp = (100.0 * (n * t_0)) / i;
} else {
tmp = -1.0 + (1.0 + (n * 100.0));
}
return tmp;
}
def code(i, n):
return 100.0 * ((math.pow((1.0 + (i / n)), n) - 1.0) / (i / n))
↓
def code(i, n):
t_0 = math.pow((1.0 + (i / n)), n) + -1.0
t_1 = t_0 / (i / n)
tmp = 0
if t_1 <= 0.0:
tmp = (math.expm1((n * math.log1p((i / n)))) * 100.0) / (i / n)
elif t_1 <= 100000000000.0:
tmp = (100.0 * (n * t_0)) / i
else:
tmp = -1.0 + (1.0 + (n * 100.0))
return tmp
function code(i, n)
return Float64(100.0 * Float64(Float64((Float64(1.0 + Float64(i / n)) ^ n) - 1.0) / Float64(i / n)))
end
↓
function code(i, n)
t_0 = Float64((Float64(1.0 + Float64(i / n)) ^ n) + -1.0)
t_1 = Float64(t_0 / Float64(i / n))
tmp = 0.0
if (t_1 <= 0.0)
tmp = Float64(Float64(expm1(Float64(n * log1p(Float64(i / n)))) * 100.0) / Float64(i / n));
elseif (t_1 <= 100000000000.0)
tmp = Float64(Float64(100.0 * Float64(n * t_0)) / i);
else
tmp = Float64(-1.0 + Float64(1.0 + Float64(n * 100.0)));
end
return tmp
end
code[i_, n_] := N[(100.0 * N[(N[(N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision] - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[i_, n_] := Block[{t$95$0 = N[(N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision] + -1.0), $MachinePrecision]}, Block[{t$95$1 = N[(t$95$0 / N[(i / n), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, 0.0], N[(N[(N[(Exp[N[(n * N[Log[1 + N[(i / n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]] - 1), $MachinePrecision] * 100.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$1, 100000000000.0], N[(N[(100.0 * N[(n * t$95$0), $MachinePrecision]), $MachinePrecision] / i), $MachinePrecision], N[(-1.0 + N[(1.0 + N[(n * 100.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]]
100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}
↓
\begin{array}{l}
t_0 := {\left(1 + \frac{i}{n}\right)}^{n} + -1\\
t_1 := \frac{t_0}{\frac{i}{n}}\\
\mathbf{if}\;t_1 \leq 0:\\
\;\;\;\;\frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right) \cdot 100}{\frac{i}{n}}\\
\mathbf{elif}\;t_1 \leq 100000000000:\\
\;\;\;\;\frac{100 \cdot \left(n \cdot t_0\right)}{i}\\
\mathbf{else}:\\
\;\;\;\;-1 + \left(1 + n \cdot 100\right)\\
\end{array}
Alternatives
| Alternative 1 |
|---|
| Error | 1.1 |
|---|
| Cost | 21768 |
|---|
\[\begin{array}{l}
t_0 := {\left(1 + \frac{i}{n}\right)}^{n} + -1\\
t_1 := \frac{t_0}{\frac{i}{n}}\\
\mathbf{if}\;t_1 \leq 0:\\
\;\;\;\;100 \cdot \left(n \cdot \frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}{i}\right)\\
\mathbf{elif}\;t_1 \leq 100000000000:\\
\;\;\;\;\frac{100 \cdot \left(n \cdot t_0\right)}{i}\\
\mathbf{else}:\\
\;\;\;\;-1 + \left(1 + n \cdot 100\right)\\
\end{array}
\]
| Alternative 2 |
|---|
| Error | 1.0 |
|---|
| Cost | 21768 |
|---|
\[\begin{array}{l}
t_0 := {\left(1 + \frac{i}{n}\right)}^{n} + -1\\
t_1 := \frac{t_0}{\frac{i}{n}}\\
\mathbf{if}\;t_1 \leq 0:\\
\;\;\;\;n \cdot \left(100 \cdot \frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}{i}\right)\\
\mathbf{elif}\;t_1 \leq 100000000000:\\
\;\;\;\;\frac{100 \cdot \left(n \cdot t_0\right)}{i}\\
\mathbf{else}:\\
\;\;\;\;-1 + \left(1 + n \cdot 100\right)\\
\end{array}
\]
| Alternative 3 |
|---|
| Error | 9.0 |
|---|
| Cost | 7113 |
|---|
\[\begin{array}{l}
\mathbf{if}\;n \leq -2 \cdot 10^{+28} \lor \neg \left(n \leq 1.8 \cdot 10^{-52}\right):\\
\;\;\;\;n \cdot \frac{\mathsf{expm1}\left(i\right)}{\frac{i}{100}}\\
\mathbf{else}:\\
\;\;\;\;\frac{n}{0.01 + 0.01 \cdot \left(i \cdot \left(\frac{0.5}{n} + -0.5\right)\right)}\\
\end{array}
\]
| Alternative 4 |
|---|
| Error | 9.1 |
|---|
| Cost | 7113 |
|---|
\[\begin{array}{l}
\mathbf{if}\;n \leq -2 \cdot 10^{+28} \lor \neg \left(n \leq 1.8 \cdot 10^{-52}\right):\\
\;\;\;\;100 \cdot \frac{n \cdot \mathsf{expm1}\left(i\right)}{i}\\
\mathbf{else}:\\
\;\;\;\;\frac{n}{0.01 + 0.01 \cdot \left(i \cdot \left(\frac{0.5}{n} + -0.5\right)\right)}\\
\end{array}
\]
| Alternative 5 |
|---|
| Error | 19.7 |
|---|
| Cost | 841 |
|---|
\[\begin{array}{l}
\mathbf{if}\;i \leq -8.5 \cdot 10^{-37} \lor \neg \left(i \leq 0.0018\right):\\
\;\;\;\;-1 + \left(1 + n \cdot 100\right)\\
\mathbf{else}:\\
\;\;\;\;n \cdot 100 + 50 \cdot \left(i \cdot n\right)\\
\end{array}
\]
| Alternative 6 |
|---|
| Error | 19.3 |
|---|
| Cost | 841 |
|---|
\[\begin{array}{l}
\mathbf{if}\;n \leq -1.85 \cdot 10^{-165} \lor \neg \left(n \leq 5 \cdot 10^{-157}\right):\\
\;\;\;\;\frac{100}{\frac{1 + i \cdot -0.5}{n}}\\
\mathbf{else}:\\
\;\;\;\;-1 + \left(1 + n \cdot 100\right)\\
\end{array}
\]
| Alternative 7 |
|---|
| Error | 15.2 |
|---|
| Cost | 832 |
|---|
\[\frac{n}{0.01 + 0.01 \cdot \left(i \cdot \left(\frac{0.5}{n} + -0.5\right)\right)}
\]
| Alternative 8 |
|---|
| Error | 21.0 |
|---|
| Cost | 713 |
|---|
\[\begin{array}{l}
\mathbf{if}\;i \leq -1.6 \lor \neg \left(i \leq 3500000000000\right):\\
\;\;\;\;-200 \cdot \frac{n}{i}\\
\mathbf{else}:\\
\;\;\;\;n \cdot \left(100 + i \cdot 50\right)\\
\end{array}
\]
| Alternative 9 |
|---|
| Error | 19.7 |
|---|
| Cost | 713 |
|---|
\[\begin{array}{l}
\mathbf{if}\;i \leq -2.2 \cdot 10^{-36} \lor \neg \left(i \leq 0.006\right):\\
\;\;\;\;-1 + \left(1 + n \cdot 100\right)\\
\mathbf{else}:\\
\;\;\;\;n \cdot \left(100 + i \cdot 50\right)\\
\end{array}
\]
| Alternative 10 |
|---|
| Error | 21.3 |
|---|
| Cost | 585 |
|---|
\[\begin{array}{l}
\mathbf{if}\;i \leq -2 \lor \neg \left(i \leq 3500000000000\right):\\
\;\;\;\;-200 \cdot \frac{n}{i}\\
\mathbf{else}:\\
\;\;\;\;n \cdot 100\\
\end{array}
\]
| Alternative 11 |
|---|
| Error | 62.1 |
|---|
| Cost | 192 |
|---|
\[i \cdot -50
\]
| Alternative 12 |
|---|
| Error | 28.4 |
|---|
| Cost | 192 |
|---|
\[n \cdot 100
\]