Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}
\]
↓
\[\begin{array}{l}
t_0 := \sqrt{b_2 \cdot b_2 - c \cdot a}\\
t_1 := -0.5 \cdot \frac{c}{b_2}\\
\mathbf{if}\;b_2 \leq -9.5 \cdot 10^{+79}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;b_2 \leq -9.5 \cdot 10^{-68}:\\
\;\;\;\;\frac{\frac{c \cdot \left(-a\right)}{b_2 - t_0}}{a}\\
\mathbf{elif}\;b_2 \leq -7.5 \cdot 10^{-102}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;b_2 \leq 8.6 \cdot 10^{+81}:\\
\;\;\;\;\frac{\left(-b_2\right) - t_0}{a}\\
\mathbf{else}:\\
\;\;\;\;\frac{b_2}{\frac{a}{-2}}\\
\end{array}
\]
(FPCore (a b_2 c)
:precision binary64
(/ (- (- b_2) (sqrt (- (* b_2 b_2) (* a c)))) a)) ↓
(FPCore (a b_2 c)
:precision binary64
(let* ((t_0 (sqrt (- (* b_2 b_2) (* c a)))) (t_1 (* -0.5 (/ c b_2))))
(if (<= b_2 -9.5e+79)
t_1
(if (<= b_2 -9.5e-68)
(/ (/ (* c (- a)) (- b_2 t_0)) a)
(if (<= b_2 -7.5e-102)
t_1
(if (<= b_2 8.6e+81) (/ (- (- b_2) t_0) a) (/ b_2 (/ a -2.0)))))))) double code(double a, double b_2, double c) {
return (-b_2 - sqrt(((b_2 * b_2) - (a * c)))) / a;
}
↓
double code(double a, double b_2, double c) {
double t_0 = sqrt(((b_2 * b_2) - (c * a)));
double t_1 = -0.5 * (c / b_2);
double tmp;
if (b_2 <= -9.5e+79) {
tmp = t_1;
} else if (b_2 <= -9.5e-68) {
tmp = ((c * -a) / (b_2 - t_0)) / a;
} else if (b_2 <= -7.5e-102) {
tmp = t_1;
} else if (b_2 <= 8.6e+81) {
tmp = (-b_2 - t_0) / a;
} else {
tmp = b_2 / (a / -2.0);
}
return tmp;
}
real(8) function code(a, b_2, c)
real(8), intent (in) :: a
real(8), intent (in) :: b_2
real(8), intent (in) :: c
code = (-b_2 - sqrt(((b_2 * b_2) - (a * c)))) / a
end function
↓
real(8) function code(a, b_2, c)
real(8), intent (in) :: a
real(8), intent (in) :: b_2
real(8), intent (in) :: c
real(8) :: t_0
real(8) :: t_1
real(8) :: tmp
t_0 = sqrt(((b_2 * b_2) - (c * a)))
t_1 = (-0.5d0) * (c / b_2)
if (b_2 <= (-9.5d+79)) then
tmp = t_1
else if (b_2 <= (-9.5d-68)) then
tmp = ((c * -a) / (b_2 - t_0)) / a
else if (b_2 <= (-7.5d-102)) then
tmp = t_1
else if (b_2 <= 8.6d+81) then
tmp = (-b_2 - t_0) / a
else
tmp = b_2 / (a / (-2.0d0))
end if
code = tmp
end function
public static double code(double a, double b_2, double c) {
return (-b_2 - Math.sqrt(((b_2 * b_2) - (a * c)))) / a;
}
↓
public static double code(double a, double b_2, double c) {
double t_0 = Math.sqrt(((b_2 * b_2) - (c * a)));
double t_1 = -0.5 * (c / b_2);
double tmp;
if (b_2 <= -9.5e+79) {
tmp = t_1;
} else if (b_2 <= -9.5e-68) {
tmp = ((c * -a) / (b_2 - t_0)) / a;
} else if (b_2 <= -7.5e-102) {
tmp = t_1;
} else if (b_2 <= 8.6e+81) {
tmp = (-b_2 - t_0) / a;
} else {
tmp = b_2 / (a / -2.0);
}
return tmp;
}
def code(a, b_2, c):
return (-b_2 - math.sqrt(((b_2 * b_2) - (a * c)))) / a
↓
def code(a, b_2, c):
t_0 = math.sqrt(((b_2 * b_2) - (c * a)))
t_1 = -0.5 * (c / b_2)
tmp = 0
if b_2 <= -9.5e+79:
tmp = t_1
elif b_2 <= -9.5e-68:
tmp = ((c * -a) / (b_2 - t_0)) / a
elif b_2 <= -7.5e-102:
tmp = t_1
elif b_2 <= 8.6e+81:
tmp = (-b_2 - t_0) / a
else:
tmp = b_2 / (a / -2.0)
return tmp
function code(a, b_2, c)
return Float64(Float64(Float64(-b_2) - sqrt(Float64(Float64(b_2 * b_2) - Float64(a * c)))) / a)
end
↓
function code(a, b_2, c)
t_0 = sqrt(Float64(Float64(b_2 * b_2) - Float64(c * a)))
t_1 = Float64(-0.5 * Float64(c / b_2))
tmp = 0.0
if (b_2 <= -9.5e+79)
tmp = t_1;
elseif (b_2 <= -9.5e-68)
tmp = Float64(Float64(Float64(c * Float64(-a)) / Float64(b_2 - t_0)) / a);
elseif (b_2 <= -7.5e-102)
tmp = t_1;
elseif (b_2 <= 8.6e+81)
tmp = Float64(Float64(Float64(-b_2) - t_0) / a);
else
tmp = Float64(b_2 / Float64(a / -2.0));
end
return tmp
end
function tmp = code(a, b_2, c)
tmp = (-b_2 - sqrt(((b_2 * b_2) - (a * c)))) / a;
end
↓
function tmp_2 = code(a, b_2, c)
t_0 = sqrt(((b_2 * b_2) - (c * a)));
t_1 = -0.5 * (c / b_2);
tmp = 0.0;
if (b_2 <= -9.5e+79)
tmp = t_1;
elseif (b_2 <= -9.5e-68)
tmp = ((c * -a) / (b_2 - t_0)) / a;
elseif (b_2 <= -7.5e-102)
tmp = t_1;
elseif (b_2 <= 8.6e+81)
tmp = (-b_2 - t_0) / a;
else
tmp = b_2 / (a / -2.0);
end
tmp_2 = tmp;
end
code[a_, b$95$2_, c_] := N[(N[((-b$95$2) - N[Sqrt[N[(N[(b$95$2 * b$95$2), $MachinePrecision] - N[(a * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / a), $MachinePrecision]
↓
code[a_, b$95$2_, c_] := Block[{t$95$0 = N[Sqrt[N[(N[(b$95$2 * b$95$2), $MachinePrecision] - N[(c * a), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, Block[{t$95$1 = N[(-0.5 * N[(c / b$95$2), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[b$95$2, -9.5e+79], t$95$1, If[LessEqual[b$95$2, -9.5e-68], N[(N[(N[(c * (-a)), $MachinePrecision] / N[(b$95$2 - t$95$0), $MachinePrecision]), $MachinePrecision] / a), $MachinePrecision], If[LessEqual[b$95$2, -7.5e-102], t$95$1, If[LessEqual[b$95$2, 8.6e+81], N[(N[((-b$95$2) - t$95$0), $MachinePrecision] / a), $MachinePrecision], N[(b$95$2 / N[(a / -2.0), $MachinePrecision]), $MachinePrecision]]]]]]]
\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}
↓
\begin{array}{l}
t_0 := \sqrt{b_2 \cdot b_2 - c \cdot a}\\
t_1 := -0.5 \cdot \frac{c}{b_2}\\
\mathbf{if}\;b_2 \leq -9.5 \cdot 10^{+79}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;b_2 \leq -9.5 \cdot 10^{-68}:\\
\;\;\;\;\frac{\frac{c \cdot \left(-a\right)}{b_2 - t_0}}{a}\\
\mathbf{elif}\;b_2 \leq -7.5 \cdot 10^{-102}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;b_2 \leq 8.6 \cdot 10^{+81}:\\
\;\;\;\;\frac{\left(-b_2\right) - t_0}{a}\\
\mathbf{else}:\\
\;\;\;\;\frac{b_2}{\frac{a}{-2}}\\
\end{array}