?

Average Error: 14.9 → 0.5
Time: 1.6s
Precision: binary64
Cost: 13640

?

\[\frac{1}{x + 1} - \frac{1}{x} \]
\[\begin{array}{l} t_0 := \frac{1}{{x}^{3}} - \frac{1}{{x}^{2}}\\ \mathbf{if}\;x \leq -240000:\\ \;\;\;\;t_0\\ \mathbf{elif}\;x \leq 320000:\\ \;\;\;\;\frac{1}{x + 1} - \frac{1}{x}\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \]
(FPCore (x) :precision binary64 (- (/ 1.0 (+ x 1.0)) (/ 1.0 x)))
(FPCore (x)
 :precision binary64
 (let* ((t_0 (- (/ 1.0 (pow x 3.0)) (/ 1.0 (pow x 2.0)))))
   (if (<= x -240000.0)
     t_0
     (if (<= x 320000.0) (- (/ 1.0 (+ x 1.0)) (/ 1.0 x)) t_0))))
double code(double x) {
	return (1.0 / (x + 1.0)) - (1.0 / x);
}
double code(double x) {
	double t_0 = (1.0 / pow(x, 3.0)) - (1.0 / pow(x, 2.0));
	double tmp;
	if (x <= -240000.0) {
		tmp = t_0;
	} else if (x <= 320000.0) {
		tmp = (1.0 / (x + 1.0)) - (1.0 / x);
	} else {
		tmp = t_0;
	}
	return tmp;
}
real(8) function code(x)
    real(8), intent (in) :: x
    code = (1.0d0 / (x + 1.0d0)) - (1.0d0 / x)
end function
real(8) function code(x)
    real(8), intent (in) :: x
    real(8) :: t_0
    real(8) :: tmp
    t_0 = (1.0d0 / (x ** 3.0d0)) - (1.0d0 / (x ** 2.0d0))
    if (x <= (-240000.0d0)) then
        tmp = t_0
    else if (x <= 320000.0d0) then
        tmp = (1.0d0 / (x + 1.0d0)) - (1.0d0 / x)
    else
        tmp = t_0
    end if
    code = tmp
end function
public static double code(double x) {
	return (1.0 / (x + 1.0)) - (1.0 / x);
}
public static double code(double x) {
	double t_0 = (1.0 / Math.pow(x, 3.0)) - (1.0 / Math.pow(x, 2.0));
	double tmp;
	if (x <= -240000.0) {
		tmp = t_0;
	} else if (x <= 320000.0) {
		tmp = (1.0 / (x + 1.0)) - (1.0 / x);
	} else {
		tmp = t_0;
	}
	return tmp;
}
def code(x):
	return (1.0 / (x + 1.0)) - (1.0 / x)
def code(x):
	t_0 = (1.0 / math.pow(x, 3.0)) - (1.0 / math.pow(x, 2.0))
	tmp = 0
	if x <= -240000.0:
		tmp = t_0
	elif x <= 320000.0:
		tmp = (1.0 / (x + 1.0)) - (1.0 / x)
	else:
		tmp = t_0
	return tmp
function code(x)
	return Float64(Float64(1.0 / Float64(x + 1.0)) - Float64(1.0 / x))
end
function code(x)
	t_0 = Float64(Float64(1.0 / (x ^ 3.0)) - Float64(1.0 / (x ^ 2.0)))
	tmp = 0.0
	if (x <= -240000.0)
		tmp = t_0;
	elseif (x <= 320000.0)
		tmp = Float64(Float64(1.0 / Float64(x + 1.0)) - Float64(1.0 / x));
	else
		tmp = t_0;
	end
	return tmp
end
function tmp = code(x)
	tmp = (1.0 / (x + 1.0)) - (1.0 / x);
end
function tmp_2 = code(x)
	t_0 = (1.0 / (x ^ 3.0)) - (1.0 / (x ^ 2.0));
	tmp = 0.0;
	if (x <= -240000.0)
		tmp = t_0;
	elseif (x <= 320000.0)
		tmp = (1.0 / (x + 1.0)) - (1.0 / x);
	else
		tmp = t_0;
	end
	tmp_2 = tmp;
end
code[x_] := N[(N[(1.0 / N[(x + 1.0), $MachinePrecision]), $MachinePrecision] - N[(1.0 / x), $MachinePrecision]), $MachinePrecision]
code[x_] := Block[{t$95$0 = N[(N[(1.0 / N[Power[x, 3.0], $MachinePrecision]), $MachinePrecision] - N[(1.0 / N[Power[x, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x, -240000.0], t$95$0, If[LessEqual[x, 320000.0], N[(N[(1.0 / N[(x + 1.0), $MachinePrecision]), $MachinePrecision] - N[(1.0 / x), $MachinePrecision]), $MachinePrecision], t$95$0]]]
\frac{1}{x + 1} - \frac{1}{x}
\begin{array}{l}
t_0 := \frac{1}{{x}^{3}} - \frac{1}{{x}^{2}}\\
\mathbf{if}\;x \leq -240000:\\
\;\;\;\;t_0\\

\mathbf{elif}\;x \leq 320000:\\
\;\;\;\;\frac{1}{x + 1} - \frac{1}{x}\\

\mathbf{else}:\\
\;\;\;\;t_0\\


\end{array}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation?

  1. Split input into 2 regimes
  2. if x < -2.4e5 or 3.2e5 < x

    1. Initial program 30.2

      \[\frac{1}{x + 1} - \frac{1}{x} \]
    2. Taylor expanded in x around inf 0.8

      \[\leadsto \color{blue}{\frac{1}{{x}^{3}} - \frac{1}{{x}^{2}}} \]

    if -2.4e5 < x < 3.2e5

    1. Initial program 0.1

      \[\frac{1}{x + 1} - \frac{1}{x} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification0.5

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -240000:\\ \;\;\;\;\frac{1}{{x}^{3}} - \frac{1}{{x}^{2}}\\ \mathbf{elif}\;x \leq 320000:\\ \;\;\;\;\frac{1}{x + 1} - \frac{1}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{{x}^{3}} - \frac{1}{{x}^{2}}\\ \end{array} \]

Alternatives

Alternative 1
Error1.0
Cost7944
\[\begin{array}{l} t_0 := \frac{1}{x + 1} - \frac{1}{x}\\ \mathbf{if}\;t_0 \leq -0.01:\\ \;\;\;\;t_0\\ \mathbf{elif}\;t_0 \leq 0:\\ \;\;\;\;\frac{-1}{{x}^{2}}\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \]
Alternative 2
Error16.1
Cost712
\[\begin{array}{l} t_0 := \frac{1}{x} - \frac{1}{x}\\ \mathbf{if}\;x \leq -1:\\ \;\;\;\;t_0\\ \mathbf{elif}\;x \leq 3.9 \cdot 10^{+61}:\\ \;\;\;\;\left(1 - x\right) - \frac{1}{x}\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \]
Alternative 3
Error14.9
Cost576
\[\frac{1}{x + 1} - \frac{1}{x} \]
Alternative 4
Error30.8
Cost192
\[\frac{-1}{x} \]
Alternative 5
Error62.1
Cost64
\[1 \]

Error

Reproduce?

herbie shell --seed 2023053 
(FPCore (x)
  :name "2frac (problem 3.3.1)"
  :precision binary64
  (- (/ 1.0 (+ x 1.0)) (/ 1.0 x)))