\[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}
\]
↓
\[\begin{array}{l}
t_0 := \pi \cdot \left(2 \cdot n\right)\\
\frac{\sqrt{t_0}}{\sqrt{k \cdot {t_0}^{k}}}
\end{array}
\]
(FPCore (k n)
:precision binary64
(* (/ 1.0 (sqrt k)) (pow (* (* 2.0 PI) n) (/ (- 1.0 k) 2.0))))
↓
(FPCore (k n)
:precision binary64
(let* ((t_0 (* PI (* 2.0 n)))) (/ (sqrt t_0) (sqrt (* k (pow t_0 k))))))
double code(double k, double n) {
return (1.0 / sqrt(k)) * pow(((2.0 * ((double) M_PI)) * n), ((1.0 - k) / 2.0));
}
↓
double code(double k, double n) {
double t_0 = ((double) M_PI) * (2.0 * n);
return sqrt(t_0) / sqrt((k * pow(t_0, k)));
}
public static double code(double k, double n) {
return (1.0 / Math.sqrt(k)) * Math.pow(((2.0 * Math.PI) * n), ((1.0 - k) / 2.0));
}
↓
public static double code(double k, double n) {
double t_0 = Math.PI * (2.0 * n);
return Math.sqrt(t_0) / Math.sqrt((k * Math.pow(t_0, k)));
}
def code(k, n):
return (1.0 / math.sqrt(k)) * math.pow(((2.0 * math.pi) * n), ((1.0 - k) / 2.0))
↓
def code(k, n):
t_0 = math.pi * (2.0 * n)
return math.sqrt(t_0) / math.sqrt((k * math.pow(t_0, k)))
function code(k, n)
return Float64(Float64(1.0 / sqrt(k)) * (Float64(Float64(2.0 * pi) * n) ^ Float64(Float64(1.0 - k) / 2.0)))
end
↓
function code(k, n)
t_0 = Float64(pi * Float64(2.0 * n))
return Float64(sqrt(t_0) / sqrt(Float64(k * (t_0 ^ k))))
end
function tmp = code(k, n)
tmp = (1.0 / sqrt(k)) * (((2.0 * pi) * n) ^ ((1.0 - k) / 2.0));
end
↓
function tmp = code(k, n)
t_0 = pi * (2.0 * n);
tmp = sqrt(t_0) / sqrt((k * (t_0 ^ k)));
end
code[k_, n_] := N[(N[(1.0 / N[Sqrt[k], $MachinePrecision]), $MachinePrecision] * N[Power[N[(N[(2.0 * Pi), $MachinePrecision] * n), $MachinePrecision], N[(N[(1.0 - k), $MachinePrecision] / 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
↓
code[k_, n_] := Block[{t$95$0 = N[(Pi * N[(2.0 * n), $MachinePrecision]), $MachinePrecision]}, N[(N[Sqrt[t$95$0], $MachinePrecision] / N[Sqrt[N[(k * N[Power[t$95$0, k], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]
\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}
↓
\begin{array}{l}
t_0 := \pi \cdot \left(2 \cdot n\right)\\
\frac{\sqrt{t_0}}{\sqrt{k \cdot {t_0}^{k}}}
\end{array}
Alternatives
| Alternative 1 |
|---|
| Error | 0.7 |
|---|
| Cost | 19908 |
|---|
\[\begin{array}{l}
\mathbf{if}\;k \leq 8.5 \cdot 10^{-37}:\\
\;\;\;\;\frac{\sqrt{\pi \cdot \left(2 \cdot n\right)}}{\sqrt{k}}\\
\mathbf{else}:\\
\;\;\;\;\sqrt{\frac{{\left(n \cdot \left(\pi \cdot 2\right)\right)}^{\left(1 - k\right)}}{k}}\\
\end{array}
\]
| Alternative 2 |
|---|
| Error | 0.5 |
|---|
| Cost | 19904 |
|---|
\[\frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(0.5 - \frac{k}{2}\right)}}{\sqrt{k}}
\]
| Alternative 3 |
|---|
| Error | 21.8 |
|---|
| Cost | 19584 |
|---|
\[\sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n}
\]
| Alternative 4 |
|---|
| Error | 21.9 |
|---|
| Cost | 19584 |
|---|
\[\frac{\sqrt{\pi \cdot \left(2 \cdot n\right)}}{\sqrt{k}}
\]
| Alternative 5 |
|---|
| Error | 31.9 |
|---|
| Cost | 13248 |
|---|
\[{\left(k \cdot \frac{0.5}{\pi \cdot n}\right)}^{-0.5}
\]
| Alternative 6 |
|---|
| Error | 31.9 |
|---|
| Cost | 13248 |
|---|
\[{\left(\frac{\frac{k}{\pi}}{2 \cdot n}\right)}^{-0.5}
\]
| Alternative 7 |
|---|
| Error | 32.6 |
|---|
| Cost | 13184 |
|---|
\[\sqrt{2 \cdot \left(n \cdot \frac{\pi}{k}\right)}
\]
| Alternative 8 |
|---|
| Error | 32.6 |
|---|
| Cost | 13184 |
|---|
\[\sqrt{2 \cdot \left(\pi \cdot \frac{n}{k}\right)}
\]
| Alternative 9 |
|---|
| Error | 32.6 |
|---|
| Cost | 13184 |
|---|
\[\sqrt{2 \cdot \frac{n}{\frac{k}{\pi}}}
\]
| Alternative 10 |
|---|
| Error | 32.6 |
|---|
| Cost | 13184 |
|---|
\[\sqrt{\frac{\pi}{\frac{k}{2 \cdot n}}}
\]