\[\frac{\cos th}{\sqrt{2}} \cdot \left(a1 \cdot a1\right) + \frac{\cos th}{\sqrt{2}} \cdot \left(a2 \cdot a2\right)
\]
↓
\[\frac{\mathsf{hypot}\left(a1, a2\right)}{\frac{\frac{\sqrt{2}}{\cos th}}{\mathsf{hypot}\left(a1, a2\right)}}
\]
(FPCore (a1 a2 th)
:precision binary64
(+
(* (/ (cos th) (sqrt 2.0)) (* a1 a1))
(* (/ (cos th) (sqrt 2.0)) (* a2 a2))))
↓
(FPCore (a1 a2 th)
:precision binary64
(/ (hypot a1 a2) (/ (/ (sqrt 2.0) (cos th)) (hypot a1 a2))))
double code(double a1, double a2, double th) {
return ((cos(th) / sqrt(2.0)) * (a1 * a1)) + ((cos(th) / sqrt(2.0)) * (a2 * a2));
}
↓
double code(double a1, double a2, double th) {
return hypot(a1, a2) / ((sqrt(2.0) / cos(th)) / hypot(a1, a2));
}
public static double code(double a1, double a2, double th) {
return ((Math.cos(th) / Math.sqrt(2.0)) * (a1 * a1)) + ((Math.cos(th) / Math.sqrt(2.0)) * (a2 * a2));
}
↓
public static double code(double a1, double a2, double th) {
return Math.hypot(a1, a2) / ((Math.sqrt(2.0) / Math.cos(th)) / Math.hypot(a1, a2));
}
def code(a1, a2, th):
return ((math.cos(th) / math.sqrt(2.0)) * (a1 * a1)) + ((math.cos(th) / math.sqrt(2.0)) * (a2 * a2))
↓
def code(a1, a2, th):
return math.hypot(a1, a2) / ((math.sqrt(2.0) / math.cos(th)) / math.hypot(a1, a2))
function code(a1, a2, th)
return Float64(Float64(Float64(cos(th) / sqrt(2.0)) * Float64(a1 * a1)) + Float64(Float64(cos(th) / sqrt(2.0)) * Float64(a2 * a2)))
end
↓
function code(a1, a2, th)
return Float64(hypot(a1, a2) / Float64(Float64(sqrt(2.0) / cos(th)) / hypot(a1, a2)))
end
function tmp = code(a1, a2, th)
tmp = ((cos(th) / sqrt(2.0)) * (a1 * a1)) + ((cos(th) / sqrt(2.0)) * (a2 * a2));
end
↓
function tmp = code(a1, a2, th)
tmp = hypot(a1, a2) / ((sqrt(2.0) / cos(th)) / hypot(a1, a2));
end
code[a1_, a2_, th_] := N[(N[(N[(N[Cos[th], $MachinePrecision] / N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision] * N[(a1 * a1), $MachinePrecision]), $MachinePrecision] + N[(N[(N[Cos[th], $MachinePrecision] / N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision] * N[(a2 * a2), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[a1_, a2_, th_] := N[(N[Sqrt[a1 ^ 2 + a2 ^ 2], $MachinePrecision] / N[(N[(N[Sqrt[2.0], $MachinePrecision] / N[Cos[th], $MachinePrecision]), $MachinePrecision] / N[Sqrt[a1 ^ 2 + a2 ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\frac{\cos th}{\sqrt{2}} \cdot \left(a1 \cdot a1\right) + \frac{\cos th}{\sqrt{2}} \cdot \left(a2 \cdot a2\right)
↓
\frac{\mathsf{hypot}\left(a1, a2\right)}{\frac{\frac{\sqrt{2}}{\cos th}}{\mathsf{hypot}\left(a1, a2\right)}}
Alternatives
| Alternative 1 |
|---|
| Error | 0.4 |
|---|
| Cost | 26176 |
|---|
\[\frac{\mathsf{hypot}\left(a1, a2\right) \cdot \cos th}{\frac{\sqrt{2}}{\mathsf{hypot}\left(a1, a2\right)}}
\]
| Alternative 2 |
|---|
| Error | 0.5 |
|---|
| Cost | 19840 |
|---|
\[\cos th \cdot \left(\mathsf{fma}\left(a2, a2, a1 \cdot a1\right) \cdot {2}^{-0.5}\right)
\]
| Alternative 3 |
|---|
| Error | 14.5 |
|---|
| Cost | 13513 |
|---|
\[\begin{array}{l}
\mathbf{if}\;th \leq -0.011 \lor \neg \left(th \leq 1.05 \cdot 10^{-11}\right):\\
\;\;\;\;a2 \cdot \left(a2 \cdot \frac{\cos th}{\sqrt{2}}\right)\\
\mathbf{else}:\\
\;\;\;\;\left(a1 \cdot a1 + a2 \cdot a2\right) \cdot \frac{1 + -0.5 \cdot \left(th \cdot th\right)}{\sqrt{2}}\\
\end{array}
\]
| Alternative 4 |
|---|
| Error | 14.5 |
|---|
| Cost | 13512 |
|---|
\[\begin{array}{l}
\mathbf{if}\;th \leq -0.011:\\
\;\;\;\;a2 \cdot \left(a2 \cdot \frac{\cos th}{\sqrt{2}}\right)\\
\mathbf{elif}\;th \leq 1.05 \cdot 10^{-11}:\\
\;\;\;\;\left(a1 \cdot a1 + a2 \cdot a2\right) \cdot \frac{1 + -0.5 \cdot \left(th \cdot th\right)}{\sqrt{2}}\\
\mathbf{else}:\\
\;\;\;\;\cos th \cdot \frac{a2}{\frac{\sqrt{2}}{a2}}\\
\end{array}
\]
| Alternative 5 |
|---|
| Error | 0.5 |
|---|
| Cost | 13504 |
|---|
\[\cos th \cdot \frac{a1 \cdot a1 + a2 \cdot a2}{\sqrt{2}}
\]
| Alternative 6 |
|---|
| Error | 0.5 |
|---|
| Cost | 13504 |
|---|
\[\frac{a1 \cdot a1 + a2 \cdot a2}{\frac{\sqrt{2}}{\cos th}}
\]
| Alternative 7 |
|---|
| Error | 20.6 |
|---|
| Cost | 13380 |
|---|
\[\begin{array}{l}
\mathbf{if}\;a2 \leq 6.5 \cdot 10^{-125}:\\
\;\;\;\;\cos th \cdot \frac{a1 \cdot a1}{\sqrt{2}}\\
\mathbf{else}:\\
\;\;\;\;\cos th \cdot \frac{a2}{\frac{\sqrt{2}}{a2}}\\
\end{array}
\]
| Alternative 8 |
|---|
| Error | 20.5 |
|---|
| Cost | 13380 |
|---|
\[\begin{array}{l}
\mathbf{if}\;a2 \leq 9.5 \cdot 10^{-123}:\\
\;\;\;\;a1 \cdot \frac{\cos th}{\frac{\sqrt{2}}{a1}}\\
\mathbf{else}:\\
\;\;\;\;\cos th \cdot \frac{a2}{\frac{\sqrt{2}}{a2}}\\
\end{array}
\]
| Alternative 9 |
|---|
| Error | 20.6 |
|---|
| Cost | 13380 |
|---|
\[\begin{array}{l}
\mathbf{if}\;a2 \leq 1.65 \cdot 10^{-127}:\\
\;\;\;\;\frac{a1}{\frac{\sqrt{2}}{a1 \cdot \cos th}}\\
\mathbf{else}:\\
\;\;\;\;\cos th \cdot \frac{a2}{\frac{\sqrt{2}}{a2}}\\
\end{array}
\]
| Alternative 10 |
|---|
| Error | 20.6 |
|---|
| Cost | 13380 |
|---|
\[\begin{array}{l}
\mathbf{if}\;a2 \leq 1.3 \cdot 10^{-124}:\\
\;\;\;\;\frac{a1}{\frac{\sqrt{2}}{a1 \cdot \cos th}}\\
\mathbf{else}:\\
\;\;\;\;\frac{a2}{\frac{\frac{\sqrt{2}}{a2}}{\cos th}}\\
\end{array}
\]
| Alternative 11 |
|---|
| Error | 20.5 |
|---|
| Cost | 13380 |
|---|
\[\begin{array}{l}
\mathbf{if}\;a2 \leq 9 \cdot 10^{-121}:\\
\;\;\;\;\frac{a1}{\frac{\sqrt{2}}{a1 \cdot \cos th}}\\
\mathbf{else}:\\
\;\;\;\;\frac{a2 \cdot \cos th}{\frac{\sqrt{2}}{a2}}\\
\end{array}
\]
| Alternative 12 |
|---|
| Error | 36.8 |
|---|
| Cost | 6980 |
|---|
\[\begin{array}{l}
\mathbf{if}\;a2 \leq 4.4 \cdot 10^{-154}:\\
\;\;\;\;\frac{1}{\frac{\sqrt{2}}{a1 \cdot a1}}\\
\mathbf{else}:\\
\;\;\;\;\frac{a2}{\frac{\sqrt{2}}{a2}}\\
\end{array}
\]
| Alternative 13 |
|---|
| Error | 25.6 |
|---|
| Cost | 6976 |
|---|
\[\left(a1 \cdot a1 + a2 \cdot a2\right) \cdot \sqrt{0.5}
\]
| Alternative 14 |
|---|
| Error | 36.7 |
|---|
| Cost | 6852 |
|---|
\[\begin{array}{l}
\mathbf{if}\;a2 \leq 4.4 \cdot 10^{-154}:\\
\;\;\;\;a1 \cdot \frac{a1}{\sqrt{2}}\\
\mathbf{else}:\\
\;\;\;\;\left(a2 \cdot a2\right) \cdot \sqrt{0.5}\\
\end{array}
\]
| Alternative 15 |
|---|
| Error | 36.7 |
|---|
| Cost | 6852 |
|---|
\[\begin{array}{l}
\mathbf{if}\;a2 \leq 3.4 \cdot 10^{-154}:\\
\;\;\;\;a1 \cdot \frac{a1}{\sqrt{2}}\\
\mathbf{else}:\\
\;\;\;\;a2 \cdot \frac{a2}{\sqrt{2}}\\
\end{array}
\]
| Alternative 16 |
|---|
| Error | 36.7 |
|---|
| Cost | 6852 |
|---|
\[\begin{array}{l}
\mathbf{if}\;a2 \leq 3.7 \cdot 10^{-154}:\\
\;\;\;\;a1 \cdot \frac{a1}{\sqrt{2}}\\
\mathbf{else}:\\
\;\;\;\;\frac{a2}{\frac{\sqrt{2}}{a2}}\\
\end{array}
\]
| Alternative 17 |
|---|
| Error | 40.5 |
|---|
| Cost | 6720 |
|---|
\[a1 \cdot \left(a1 \cdot \sqrt{0.5}\right)
\]
| Alternative 18 |
|---|
| Error | 40.4 |
|---|
| Cost | 6720 |
|---|
\[a1 \cdot \frac{a1}{\sqrt{2}}
\]
| Alternative 19 |
|---|
| Error | 40.5 |
|---|
| Cost | 6720 |
|---|
\[\left(a1 \cdot a1\right) \cdot \sqrt{0.5}
\]