\[\frac{1}{\sqrt{x}} - \frac{1}{\sqrt{x + 1}}
\]
↓
\[\begin{array}{l}
t_0 := \sqrt{x} + \sqrt{1 + x}\\
\mathbf{if}\;x \leq 5 \cdot 10^{+40}:\\
\;\;\;\;\frac{1}{\sqrt{x + x \cdot x} \cdot t_0}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{1}{x}}{t_0}\\
\end{array}
\]
(FPCore (x) :precision binary64 (- (/ 1.0 (sqrt x)) (/ 1.0 (sqrt (+ x 1.0)))))
↓
(FPCore (x)
:precision binary64
(let* ((t_0 (+ (sqrt x) (sqrt (+ 1.0 x)))))
(if (<= x 5e+40) (/ 1.0 (* (sqrt (+ x (* x x))) t_0)) (/ (/ 1.0 x) t_0))))
double code(double x) {
return (1.0 / sqrt(x)) - (1.0 / sqrt((x + 1.0)));
}
↓
double code(double x) {
double t_0 = sqrt(x) + sqrt((1.0 + x));
double tmp;
if (x <= 5e+40) {
tmp = 1.0 / (sqrt((x + (x * x))) * t_0);
} else {
tmp = (1.0 / x) / t_0;
}
return tmp;
}
real(8) function code(x)
real(8), intent (in) :: x
code = (1.0d0 / sqrt(x)) - (1.0d0 / sqrt((x + 1.0d0)))
end function
↓
real(8) function code(x)
real(8), intent (in) :: x
real(8) :: t_0
real(8) :: tmp
t_0 = sqrt(x) + sqrt((1.0d0 + x))
if (x <= 5d+40) then
tmp = 1.0d0 / (sqrt((x + (x * x))) * t_0)
else
tmp = (1.0d0 / x) / t_0
end if
code = tmp
end function
public static double code(double x) {
return (1.0 / Math.sqrt(x)) - (1.0 / Math.sqrt((x + 1.0)));
}
↓
public static double code(double x) {
double t_0 = Math.sqrt(x) + Math.sqrt((1.0 + x));
double tmp;
if (x <= 5e+40) {
tmp = 1.0 / (Math.sqrt((x + (x * x))) * t_0);
} else {
tmp = (1.0 / x) / t_0;
}
return tmp;
}
def code(x):
return (1.0 / math.sqrt(x)) - (1.0 / math.sqrt((x + 1.0)))
↓
def code(x):
t_0 = math.sqrt(x) + math.sqrt((1.0 + x))
tmp = 0
if x <= 5e+40:
tmp = 1.0 / (math.sqrt((x + (x * x))) * t_0)
else:
tmp = (1.0 / x) / t_0
return tmp
function code(x)
return Float64(Float64(1.0 / sqrt(x)) - Float64(1.0 / sqrt(Float64(x + 1.0))))
end
↓
function code(x)
t_0 = Float64(sqrt(x) + sqrt(Float64(1.0 + x)))
tmp = 0.0
if (x <= 5e+40)
tmp = Float64(1.0 / Float64(sqrt(Float64(x + Float64(x * x))) * t_0));
else
tmp = Float64(Float64(1.0 / x) / t_0);
end
return tmp
end
function tmp = code(x)
tmp = (1.0 / sqrt(x)) - (1.0 / sqrt((x + 1.0)));
end
↓
function tmp_2 = code(x)
t_0 = sqrt(x) + sqrt((1.0 + x));
tmp = 0.0;
if (x <= 5e+40)
tmp = 1.0 / (sqrt((x + (x * x))) * t_0);
else
tmp = (1.0 / x) / t_0;
end
tmp_2 = tmp;
end
code[x_] := N[(N[(1.0 / N[Sqrt[x], $MachinePrecision]), $MachinePrecision] - N[(1.0 / N[Sqrt[N[(x + 1.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[x_] := Block[{t$95$0 = N[(N[Sqrt[x], $MachinePrecision] + N[Sqrt[N[(1.0 + x), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x, 5e+40], N[(1.0 / N[(N[Sqrt[N[(x + N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision], N[(N[(1.0 / x), $MachinePrecision] / t$95$0), $MachinePrecision]]]
\frac{1}{\sqrt{x}} - \frac{1}{\sqrt{x + 1}}
↓
\begin{array}{l}
t_0 := \sqrt{x} + \sqrt{1 + x}\\
\mathbf{if}\;x \leq 5 \cdot 10^{+40}:\\
\;\;\;\;\frac{1}{\sqrt{x + x \cdot x} \cdot t_0}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{1}{x}}{t_0}\\
\end{array}
Alternatives
| Alternative 1 |
|---|
| Error | 0.9 |
|---|
| Cost | 26820 |
|---|
\[\begin{array}{l}
t_0 := \sqrt{1 + x}\\
\mathbf{if}\;\frac{1}{\sqrt{x}} + \frac{-1}{t_0} \leq 10^{-16}:\\
\;\;\;\;\frac{1}{x \cdot \left(\sqrt{x} + t_0\right)}\\
\mathbf{else}:\\
\;\;\;\;{x}^{-0.5} - {\left(1 + x\right)}^{-0.5}\\
\end{array}
\]
| Alternative 2 |
|---|
| Error | 0.3 |
|---|
| Cost | 26240 |
|---|
\[\frac{\frac{1}{\sqrt{x} + \sqrt{1 + x}}}{\mathsf{hypot}\left(x, \sqrt{x}\right)}
\]
| Alternative 3 |
|---|
| Error | 0.4 |
|---|
| Cost | 13508 |
|---|
\[\begin{array}{l}
\mathbf{if}\;x \leq 85000000:\\
\;\;\;\;{x}^{-0.5} - {\left(1 + x\right)}^{-0.5}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{1}{x}}{\sqrt{x} + \sqrt{1 + x}}\\
\end{array}
\]
| Alternative 4 |
|---|
| Error | 11.0 |
|---|
| Cost | 13380 |
|---|
\[\begin{array}{l}
\mathbf{if}\;x \leq 110000000:\\
\;\;\;\;{x}^{-0.5} - {\left(1 + x\right)}^{-0.5}\\
\mathbf{else}:\\
\;\;\;\;0.5 \cdot \sqrt{\frac{1}{{x}^{3}}}\\
\end{array}
\]
| Alternative 5 |
|---|
| Error | 11.6 |
|---|
| Cost | 13316 |
|---|
\[\begin{array}{l}
\mathbf{if}\;x \leq 1.7:\\
\;\;\;\;{x}^{-0.5} + \frac{-1}{1 + x \cdot 0.5}\\
\mathbf{else}:\\
\;\;\;\;0.5 \cdot \sqrt{\frac{1}{{x}^{3}}}\\
\end{array}
\]
| Alternative 6 |
|---|
| Error | 20.4 |
|---|
| Cost | 7236 |
|---|
\[\begin{array}{l}
t_0 := 1 + x \cdot 0.5\\
\mathbf{if}\;x \leq 1.35:\\
\;\;\;\;{x}^{-0.5} + \frac{-1}{t_0}\\
\mathbf{else}:\\
\;\;\;\;\frac{1}{x \cdot \left(\sqrt{x} + t_0\right)}\\
\end{array}
\]
| Alternative 7 |
|---|
| Error | 20.4 |
|---|
| Cost | 7172 |
|---|
\[\begin{array}{l}
\mathbf{if}\;x \leq 6:\\
\;\;\;\;{x}^{-0.5} + \frac{-1}{1 + x \cdot 0.5}\\
\mathbf{else}:\\
\;\;\;\;\frac{1}{\sqrt{x + x \cdot x}}\\
\end{array}
\]
| Alternative 8 |
|---|
| Error | 20.5 |
|---|
| Cost | 7044 |
|---|
\[\begin{array}{l}
\mathbf{if}\;x \leq 1.4:\\
\;\;\;\;{x}^{-0.5} - \left(1 + x \cdot -0.5\right)\\
\mathbf{else}:\\
\;\;\;\;\frac{1}{\sqrt{x + x \cdot x}}\\
\end{array}
\]
| Alternative 9 |
|---|
| Error | 21.7 |
|---|
| Cost | 6848 |
|---|
\[\frac{1}{\sqrt{x + x \cdot x}}
\]
| Alternative 10 |
|---|
| Error | 29.9 |
|---|
| Cost | 6788 |
|---|
\[\begin{array}{l}
\mathbf{if}\;x \leq 0.8:\\
\;\;\;\;{x}^{-0.5} + -1\\
\mathbf{else}:\\
\;\;\;\;\frac{1}{x}\\
\end{array}
\]
| Alternative 11 |
|---|
| Error | 22.0 |
|---|
| Cost | 6784 |
|---|
\[1 + \left({x}^{-0.5} + -1\right)
\]
| Alternative 12 |
|---|
| Error | 30.3 |
|---|
| Cost | 6720 |
|---|
\[\frac{1}{x + \sqrt{x}}
\]
| Alternative 13 |
|---|
| Error | 31.5 |
|---|
| Cost | 6528 |
|---|
\[{x}^{-0.5}
\]
| Alternative 14 |
|---|
| Error | 59.3 |
|---|
| Cost | 192 |
|---|
\[\frac{1}{x}
\]