?

Average Error: 14.4 → 9.5
Time: 17.9s
Precision: binary64
Cost: 14084

?

\[ \begin{array}{c}[M, D] = \mathsf{sort}([M, D])\\ \end{array} \]
\[w0 \cdot \sqrt{1 - {\left(\frac{M \cdot D}{2 \cdot d}\right)}^{2} \cdot \frac{h}{\ell}} \]
\[\begin{array}{l} \mathbf{if}\;\frac{h}{\ell} \leq -\infty:\\ \;\;\;\;w0 \cdot \sqrt{1 - \frac{h \cdot {\left(\left(M \cdot 0.5\right) \cdot \frac{D}{d}\right)}^{2}}{\ell}}\\ \mathbf{elif}\;\frac{h}{\ell} \leq -5 \cdot 10^{-270}:\\ \;\;\;\;w0 \cdot \sqrt{1 - \frac{\frac{D}{\frac{d}{M}} \cdot \left(D \cdot \frac{M}{d}\right)}{\frac{\ell}{h} \cdot 4}}\\ \mathbf{else}:\\ \;\;\;\;w0\\ \end{array} \]
(FPCore (w0 M D h l d)
 :precision binary64
 (* w0 (sqrt (- 1.0 (* (pow (/ (* M D) (* 2.0 d)) 2.0) (/ h l))))))
(FPCore (w0 M D h l d)
 :precision binary64
 (if (<= (/ h l) (- INFINITY))
   (* w0 (sqrt (- 1.0 (/ (* h (pow (* (* M 0.5) (/ D d)) 2.0)) l))))
   (if (<= (/ h l) -5e-270)
     (* w0 (sqrt (- 1.0 (/ (* (/ D (/ d M)) (* D (/ M d))) (* (/ l h) 4.0)))))
     w0)))
double code(double w0, double M, double D, double h, double l, double d) {
	return w0 * sqrt((1.0 - (pow(((M * D) / (2.0 * d)), 2.0) * (h / l))));
}
double code(double w0, double M, double D, double h, double l, double d) {
	double tmp;
	if ((h / l) <= -((double) INFINITY)) {
		tmp = w0 * sqrt((1.0 - ((h * pow(((M * 0.5) * (D / d)), 2.0)) / l)));
	} else if ((h / l) <= -5e-270) {
		tmp = w0 * sqrt((1.0 - (((D / (d / M)) * (D * (M / d))) / ((l / h) * 4.0))));
	} else {
		tmp = w0;
	}
	return tmp;
}
public static double code(double w0, double M, double D, double h, double l, double d) {
	return w0 * Math.sqrt((1.0 - (Math.pow(((M * D) / (2.0 * d)), 2.0) * (h / l))));
}
public static double code(double w0, double M, double D, double h, double l, double d) {
	double tmp;
	if ((h / l) <= -Double.POSITIVE_INFINITY) {
		tmp = w0 * Math.sqrt((1.0 - ((h * Math.pow(((M * 0.5) * (D / d)), 2.0)) / l)));
	} else if ((h / l) <= -5e-270) {
		tmp = w0 * Math.sqrt((1.0 - (((D / (d / M)) * (D * (M / d))) / ((l / h) * 4.0))));
	} else {
		tmp = w0;
	}
	return tmp;
}
def code(w0, M, D, h, l, d):
	return w0 * math.sqrt((1.0 - (math.pow(((M * D) / (2.0 * d)), 2.0) * (h / l))))
def code(w0, M, D, h, l, d):
	tmp = 0
	if (h / l) <= -math.inf:
		tmp = w0 * math.sqrt((1.0 - ((h * math.pow(((M * 0.5) * (D / d)), 2.0)) / l)))
	elif (h / l) <= -5e-270:
		tmp = w0 * math.sqrt((1.0 - (((D / (d / M)) * (D * (M / d))) / ((l / h) * 4.0))))
	else:
		tmp = w0
	return tmp
function code(w0, M, D, h, l, d)
	return Float64(w0 * sqrt(Float64(1.0 - Float64((Float64(Float64(M * D) / Float64(2.0 * d)) ^ 2.0) * Float64(h / l)))))
end
function code(w0, M, D, h, l, d)
	tmp = 0.0
	if (Float64(h / l) <= Float64(-Inf))
		tmp = Float64(w0 * sqrt(Float64(1.0 - Float64(Float64(h * (Float64(Float64(M * 0.5) * Float64(D / d)) ^ 2.0)) / l))));
	elseif (Float64(h / l) <= -5e-270)
		tmp = Float64(w0 * sqrt(Float64(1.0 - Float64(Float64(Float64(D / Float64(d / M)) * Float64(D * Float64(M / d))) / Float64(Float64(l / h) * 4.0)))));
	else
		tmp = w0;
	end
	return tmp
end
function tmp = code(w0, M, D, h, l, d)
	tmp = w0 * sqrt((1.0 - ((((M * D) / (2.0 * d)) ^ 2.0) * (h / l))));
end
function tmp_2 = code(w0, M, D, h, l, d)
	tmp = 0.0;
	if ((h / l) <= -Inf)
		tmp = w0 * sqrt((1.0 - ((h * (((M * 0.5) * (D / d)) ^ 2.0)) / l)));
	elseif ((h / l) <= -5e-270)
		tmp = w0 * sqrt((1.0 - (((D / (d / M)) * (D * (M / d))) / ((l / h) * 4.0))));
	else
		tmp = w0;
	end
	tmp_2 = tmp;
end
code[w0_, M_, D_, h_, l_, d_] := N[(w0 * N[Sqrt[N[(1.0 - N[(N[Power[N[(N[(M * D), $MachinePrecision] / N[(2.0 * d), $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] * N[(h / l), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
code[w0_, M_, D_, h_, l_, d_] := If[LessEqual[N[(h / l), $MachinePrecision], (-Infinity)], N[(w0 * N[Sqrt[N[(1.0 - N[(N[(h * N[Power[N[(N[(M * 0.5), $MachinePrecision] * N[(D / d), $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] / l), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], If[LessEqual[N[(h / l), $MachinePrecision], -5e-270], N[(w0 * N[Sqrt[N[(1.0 - N[(N[(N[(D / N[(d / M), $MachinePrecision]), $MachinePrecision] * N[(D * N[(M / d), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(N[(l / h), $MachinePrecision] * 4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], w0]]
w0 \cdot \sqrt{1 - {\left(\frac{M \cdot D}{2 \cdot d}\right)}^{2} \cdot \frac{h}{\ell}}
\begin{array}{l}
\mathbf{if}\;\frac{h}{\ell} \leq -\infty:\\
\;\;\;\;w0 \cdot \sqrt{1 - \frac{h \cdot {\left(\left(M \cdot 0.5\right) \cdot \frac{D}{d}\right)}^{2}}{\ell}}\\

\mathbf{elif}\;\frac{h}{\ell} \leq -5 \cdot 10^{-270}:\\
\;\;\;\;w0 \cdot \sqrt{1 - \frac{\frac{D}{\frac{d}{M}} \cdot \left(D \cdot \frac{M}{d}\right)}{\frac{\ell}{h} \cdot 4}}\\

\mathbf{else}:\\
\;\;\;\;w0\\


\end{array}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation?

  1. Split input into 3 regimes
  2. if (/.f64 h l) < -inf.0

    1. Initial program 64.0

      \[w0 \cdot \sqrt{1 - {\left(\frac{M \cdot D}{2 \cdot d}\right)}^{2} \cdot \frac{h}{\ell}} \]
    2. Simplified64.0

      \[\leadsto \color{blue}{w0 \cdot \sqrt{1 - {\left(\frac{M}{2} \cdot \frac{D}{d}\right)}^{2} \cdot \frac{h}{\ell}}} \]
      Proof

      [Start]64.0

      \[ w0 \cdot \sqrt{1 - {\left(\frac{M \cdot D}{2 \cdot d}\right)}^{2} \cdot \frac{h}{\ell}} \]

      times-frac [=>]64.0

      \[ w0 \cdot \sqrt{1 - {\color{blue}{\left(\frac{M}{2} \cdot \frac{D}{d}\right)}}^{2} \cdot \frac{h}{\ell}} \]
    3. Applied egg-rr25.7

      \[\leadsto w0 \cdot \sqrt{1 - \color{blue}{\frac{{\left(\left(M \cdot 0.5\right) \cdot \frac{D}{d}\right)}^{2} \cdot h}{\ell}}} \]

    if -inf.0 < (/.f64 h l) < -4.9999999999999998e-270

    1. Initial program 13.9

      \[w0 \cdot \sqrt{1 - {\left(\frac{M \cdot D}{2 \cdot d}\right)}^{2} \cdot \frac{h}{\ell}} \]
    2. Simplified14.1

      \[\leadsto \color{blue}{w0 \cdot \sqrt{1 - {\left(\frac{M}{2} \cdot \frac{D}{d}\right)}^{2} \cdot \frac{h}{\ell}}} \]
      Proof

      [Start]13.9

      \[ w0 \cdot \sqrt{1 - {\left(\frac{M \cdot D}{2 \cdot d}\right)}^{2} \cdot \frac{h}{\ell}} \]

      times-frac [=>]14.1

      \[ w0 \cdot \sqrt{1 - {\color{blue}{\left(\frac{M}{2} \cdot \frac{D}{d}\right)}}^{2} \cdot \frac{h}{\ell}} \]
    3. Applied egg-rr13.9

      \[\leadsto w0 \cdot \sqrt{1 - \color{blue}{\frac{\left(\frac{M}{d} \cdot D\right) \cdot \left(\frac{M}{d} \cdot D\right)}{\frac{\ell}{h} \cdot 4}}} \]
    4. Applied egg-rr13.9

      \[\leadsto w0 \cdot \sqrt{1 - \frac{\color{blue}{\frac{D}{\frac{d}{M}}} \cdot \left(\frac{M}{d} \cdot D\right)}{\frac{\ell}{h} \cdot 4}} \]

    if -4.9999999999999998e-270 < (/.f64 h l)

    1. Initial program 8.4

      \[w0 \cdot \sqrt{1 - {\left(\frac{M \cdot D}{2 \cdot d}\right)}^{2} \cdot \frac{h}{\ell}} \]
    2. Simplified8.4

      \[\leadsto \color{blue}{w0 \cdot \sqrt{1 - {\left(\frac{M}{2} \cdot \frac{D}{d}\right)}^{2} \cdot \frac{h}{\ell}}} \]
      Proof

      [Start]8.4

      \[ w0 \cdot \sqrt{1 - {\left(\frac{M \cdot D}{2 \cdot d}\right)}^{2} \cdot \frac{h}{\ell}} \]

      times-frac [=>]8.4

      \[ w0 \cdot \sqrt{1 - {\color{blue}{\left(\frac{M}{2} \cdot \frac{D}{d}\right)}}^{2} \cdot \frac{h}{\ell}} \]
    3. Taylor expanded in M around 0 3.4

      \[\leadsto \color{blue}{w0} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification9.5

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{h}{\ell} \leq -\infty:\\ \;\;\;\;w0 \cdot \sqrt{1 - \frac{h \cdot {\left(\left(M \cdot 0.5\right) \cdot \frac{D}{d}\right)}^{2}}{\ell}}\\ \mathbf{elif}\;\frac{h}{\ell} \leq -5 \cdot 10^{-270}:\\ \;\;\;\;w0 \cdot \sqrt{1 - \frac{\frac{D}{\frac{d}{M}} \cdot \left(D \cdot \frac{M}{d}\right)}{\frac{\ell}{h} \cdot 4}}\\ \mathbf{else}:\\ \;\;\;\;w0\\ \end{array} \]

Alternatives

Alternative 1
Error11.3
Cost8264
\[\begin{array}{l} \mathbf{if}\;\frac{h}{\ell} \leq -\infty:\\ \;\;\;\;w0\\ \mathbf{elif}\;\frac{h}{\ell} \leq -5 \cdot 10^{-270}:\\ \;\;\;\;w0 \cdot \sqrt{1 - D \cdot \left(\frac{M}{d} \cdot \left(\left(M \cdot \frac{D}{4}\right) \cdot \frac{\frac{h}{\ell}}{d}\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;w0\\ \end{array} \]
Alternative 2
Error10.0
Cost8264
\[\begin{array}{l} t_0 := D \cdot \frac{M}{d}\\ \mathbf{if}\;\frac{h}{\ell} \leq -\infty:\\ \;\;\;\;w0\\ \mathbf{elif}\;\frac{h}{\ell} \leq -5 \cdot 10^{-270}:\\ \;\;\;\;w0 \cdot \sqrt{1 - \frac{t_0 \cdot t_0}{\frac{\ell}{h} \cdot 4}}\\ \mathbf{else}:\\ \;\;\;\;w0\\ \end{array} \]
Alternative 3
Error10.0
Cost8264
\[\begin{array}{l} \mathbf{if}\;\frac{h}{\ell} \leq -\infty:\\ \;\;\;\;w0\\ \mathbf{elif}\;\frac{h}{\ell} \leq -5 \cdot 10^{-270}:\\ \;\;\;\;w0 \cdot \sqrt{1 - \frac{\frac{D}{\frac{d}{M}} \cdot \left(D \cdot \frac{M}{d}\right)}{\frac{\ell}{h} \cdot 4}}\\ \mathbf{else}:\\ \;\;\;\;w0\\ \end{array} \]
Alternative 4
Error9.7
Cost8264
\[\begin{array}{l} \mathbf{if}\;\frac{h}{\ell} \leq -\infty:\\ \;\;\;\;w0 \cdot \sqrt{1 + h \cdot \frac{\frac{M \cdot \left(M \cdot D\right)}{d} \cdot \left(D \cdot -0.5\right)}{d \cdot \left(\ell \cdot 2\right)}}\\ \mathbf{elif}\;\frac{h}{\ell} \leq -5 \cdot 10^{-270}:\\ \;\;\;\;w0 \cdot \sqrt{1 - \frac{\frac{D}{\frac{d}{M}} \cdot \left(D \cdot \frac{M}{d}\right)}{\frac{\ell}{h} \cdot 4}}\\ \mathbf{else}:\\ \;\;\;\;w0\\ \end{array} \]
Alternative 5
Error14.3
Cost64
\[w0 \]

Error

Reproduce?

herbie shell --seed 2023034 
(FPCore (w0 M D h l d)
  :name "Henrywood and Agarwal, Equation (9a)"
  :precision binary64
  (* w0 (sqrt (- 1.0 (* (pow (/ (* M D) (* 2.0 d)) 2.0) (/ h l))))))