?

Average Error: 0.0 → 0.0
Time: 18.1s
Precision: binary64
Cost: 6720

?

\[x \cdot y + z \cdot t \]
\[\mathsf{fma}\left(x, y, z \cdot t\right) \]
(FPCore (x y z t) :precision binary64 (+ (* x y) (* z t)))
(FPCore (x y z t) :precision binary64 (fma x y (* z t)))
double code(double x, double y, double z, double t) {
	return (x * y) + (z * t);
}
double code(double x, double y, double z, double t) {
	return fma(x, y, (z * t));
}
function code(x, y, z, t)
	return Float64(Float64(x * y) + Float64(z * t))
end
function code(x, y, z, t)
	return fma(x, y, Float64(z * t))
end
code[x_, y_, z_, t_] := N[(N[(x * y), $MachinePrecision] + N[(z * t), $MachinePrecision]), $MachinePrecision]
code[x_, y_, z_, t_] := N[(x * y + N[(z * t), $MachinePrecision]), $MachinePrecision]
x \cdot y + z \cdot t
\mathsf{fma}\left(x, y, z \cdot t\right)

Error?

Derivation?

  1. Initial program 0.0

    \[x \cdot y + z \cdot t \]
  2. Simplified0.0

    \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, z \cdot t\right)} \]
    Proof

Alternatives

Alternative 1
Error15.5
Cost712
\[\begin{array}{l} \mathbf{if}\;z \cdot t \leq -2.05 \cdot 10^{-78}:\\ \;\;\;\;z \cdot t\\ \mathbf{elif}\;z \cdot t \leq 30500000:\\ \;\;\;\;y \cdot x\\ \mathbf{else}:\\ \;\;\;\;z \cdot t\\ \end{array} \]
Alternative 2
Error0.0
Cost448
\[x \cdot y + z \cdot t \]
Alternative 3
Error30.8
Cost192
\[y \cdot x \]

Error

Reproduce?

herbie shell --seed 2023033 
(FPCore (x y z t)
  :name "Linear.V2:$cdot from linear-1.19.1.3, A"
  :precision binary64
  (+ (* x y) (* z t)))