?

Average Error: 0.0 → 0.0
Time: 9.6s
Precision: binary64
Cost: 320

?

\[\frac{x \cdot y}{2} \]
\[\left(0.5 \cdot y\right) \cdot x \]
(FPCore (x y) :precision binary64 (/ (* x y) 2.0))
(FPCore (x y) :precision binary64 (* (* 0.5 y) x))
double code(double x, double y) {
	return (x * y) / 2.0;
}
double code(double x, double y) {
	return (0.5 * y) * x;
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = (x * y) / 2.0d0
end function
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = (0.5d0 * y) * x
end function
public static double code(double x, double y) {
	return (x * y) / 2.0;
}
public static double code(double x, double y) {
	return (0.5 * y) * x;
}
def code(x, y):
	return (x * y) / 2.0
def code(x, y):
	return (0.5 * y) * x
function code(x, y)
	return Float64(Float64(x * y) / 2.0)
end
function code(x, y)
	return Float64(Float64(0.5 * y) * x)
end
function tmp = code(x, y)
	tmp = (x * y) / 2.0;
end
function tmp = code(x, y)
	tmp = (0.5 * y) * x;
end
code[x_, y_] := N[(N[(x * y), $MachinePrecision] / 2.0), $MachinePrecision]
code[x_, y_] := N[(N[(0.5 * y), $MachinePrecision] * x), $MachinePrecision]
\frac{x \cdot y}{2}
\left(0.5 \cdot y\right) \cdot x

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation?

  1. Initial program 0.0

    \[\frac{x \cdot y}{2} \]
  2. Taylor expanded in x around 0 0.0

    \[\leadsto \color{blue}{0.5 \cdot \left(y \cdot x\right)} \]
  3. Simplified0.0

    \[\leadsto \color{blue}{\left(0.5 \cdot y\right) \cdot x} \]
    Proof

Reproduce?

herbie shell --seed 2023033 
(FPCore (x y)
  :name "Numeric.Interval.Internal:scale from intervals-0.7.1, B"
  :precision binary64
  (/ (* x y) 2.0))