\[\left(2 \cdot \sqrt{x}\right) \cdot \cos \left(y - \frac{z \cdot t}{3}\right) - \frac{a}{b \cdot 3}
\]
↓
\[\begin{array}{l}
t_1 := \frac{t}{\frac{3}{z}}\\
t_2 := \cos t_1\\
t_3 := \sin y \cdot \sin t_1\\
t_4 := \cos y \cdot t_2\\
\mathbf{if}\;z \cdot t \leq -2 \cdot 10^{+283}:\\
\;\;\;\;2 \cdot \sqrt{x} - \frac{\frac{a}{b}}{3}\\
\mathbf{elif}\;z \cdot t \leq 5 \cdot 10^{+271}:\\
\;\;\;\;\frac{\sqrt{x} \cdot \left(2 \cdot \left({t_4}^{3} + {t_3}^{3}\right)\right)}{\mathsf{fma}\left(\cos y, t_2 \cdot t_4, t_3 \cdot \left(t_3 - t_4\right)\right)} - \frac{a}{b \cdot 3}\\
\mathbf{else}:\\
\;\;\;\;\mathsf{fma}\left(2, \sqrt{x}, \frac{\frac{a}{-3}}{b}\right)\\
\end{array}
\]
double code(double x, double y, double z, double t, double a, double b) {
return ((2.0 * sqrt(x)) * cos((y - ((z * t) / 3.0)))) - (a / (b * 3.0));
}
↓
double code(double x, double y, double z, double t, double a, double b) {
double t_1 = t / (3.0 / z);
double t_2 = cos(t_1);
double t_3 = sin(y) * sin(t_1);
double t_4 = cos(y) * t_2;
double tmp;
if ((z * t) <= -2e+283) {
tmp = (2.0 * sqrt(x)) - ((a / b) / 3.0);
} else if ((z * t) <= 5e+271) {
tmp = ((sqrt(x) * (2.0 * (pow(t_4, 3.0) + pow(t_3, 3.0)))) / fma(cos(y), (t_2 * t_4), (t_3 * (t_3 - t_4)))) - (a / (b * 3.0));
} else {
tmp = fma(2.0, sqrt(x), ((a / -3.0) / b));
}
return tmp;
}
function code(x, y, z, t, a, b)
return Float64(Float64(Float64(2.0 * sqrt(x)) * cos(Float64(y - Float64(Float64(z * t) / 3.0)))) - Float64(a / Float64(b * 3.0)))
end
↓
function code(x, y, z, t, a, b)
t_1 = Float64(t / Float64(3.0 / z))
t_2 = cos(t_1)
t_3 = Float64(sin(y) * sin(t_1))
t_4 = Float64(cos(y) * t_2)
tmp = 0.0
if (Float64(z * t) <= -2e+283)
tmp = Float64(Float64(2.0 * sqrt(x)) - Float64(Float64(a / b) / 3.0));
elseif (Float64(z * t) <= 5e+271)
tmp = Float64(Float64(Float64(sqrt(x) * Float64(2.0 * Float64((t_4 ^ 3.0) + (t_3 ^ 3.0)))) / fma(cos(y), Float64(t_2 * t_4), Float64(t_3 * Float64(t_3 - t_4)))) - Float64(a / Float64(b * 3.0)));
else
tmp = fma(2.0, sqrt(x), Float64(Float64(a / -3.0) / b));
end
return tmp
end
code[x_, y_, z_, t_, a_, b_] := N[(N[(N[(2.0 * N[Sqrt[x], $MachinePrecision]), $MachinePrecision] * N[Cos[N[(y - N[(N[(z * t), $MachinePrecision] / 3.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] - N[(a / N[(b * 3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_, z_, t_, a_, b_] := Block[{t$95$1 = N[(t / N[(3.0 / z), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[Cos[t$95$1], $MachinePrecision]}, Block[{t$95$3 = N[(N[Sin[y], $MachinePrecision] * N[Sin[t$95$1], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$4 = N[(N[Cos[y], $MachinePrecision] * t$95$2), $MachinePrecision]}, If[LessEqual[N[(z * t), $MachinePrecision], -2e+283], N[(N[(2.0 * N[Sqrt[x], $MachinePrecision]), $MachinePrecision] - N[(N[(a / b), $MachinePrecision] / 3.0), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[(z * t), $MachinePrecision], 5e+271], N[(N[(N[(N[Sqrt[x], $MachinePrecision] * N[(2.0 * N[(N[Power[t$95$4, 3.0], $MachinePrecision] + N[Power[t$95$3, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(N[Cos[y], $MachinePrecision] * N[(t$95$2 * t$95$4), $MachinePrecision] + N[(t$95$3 * N[(t$95$3 - t$95$4), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(a / N[(b * 3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(2.0 * N[Sqrt[x], $MachinePrecision] + N[(N[(a / -3.0), $MachinePrecision] / b), $MachinePrecision]), $MachinePrecision]]]]]]]
\left(2 \cdot \sqrt{x}\right) \cdot \cos \left(y - \frac{z \cdot t}{3}\right) - \frac{a}{b \cdot 3}
↓
\begin{array}{l}
t_1 := \frac{t}{\frac{3}{z}}\\
t_2 := \cos t_1\\
t_3 := \sin y \cdot \sin t_1\\
t_4 := \cos y \cdot t_2\\
\mathbf{if}\;z \cdot t \leq -2 \cdot 10^{+283}:\\
\;\;\;\;2 \cdot \sqrt{x} - \frac{\frac{a}{b}}{3}\\
\mathbf{elif}\;z \cdot t \leq 5 \cdot 10^{+271}:\\
\;\;\;\;\frac{\sqrt{x} \cdot \left(2 \cdot \left({t_4}^{3} + {t_3}^{3}\right)\right)}{\mathsf{fma}\left(\cos y, t_2 \cdot t_4, t_3 \cdot \left(t_3 - t_4\right)\right)} - \frac{a}{b \cdot 3}\\
\mathbf{else}:\\
\;\;\;\;\mathsf{fma}\left(2, \sqrt{x}, \frac{\frac{a}{-3}}{b}\right)\\
\end{array}