?

Average Error: 14.9 → 0.4
Time: 9.1s
Precision: binary64
Cost: 6912

?

\[\tan^{-1} \left(N + 1\right) - \tan^{-1} N \]
\[\tan^{-1}_* \frac{1}{N + \left(1 + N \cdot N\right)} \]
(FPCore (N) :precision binary64 (- (atan (+ N 1.0)) (atan N)))
(FPCore (N) :precision binary64 (atan2 1.0 (+ N (+ 1.0 (* N N)))))
double code(double N) {
	return atan((N + 1.0)) - atan(N);
}
double code(double N) {
	return atan2(1.0, (N + (1.0 + (N * N))));
}
real(8) function code(n)
    real(8), intent (in) :: n
    code = atan((n + 1.0d0)) - atan(n)
end function
real(8) function code(n)
    real(8), intent (in) :: n
    code = atan2(1.0d0, (n + (1.0d0 + (n * n))))
end function
public static double code(double N) {
	return Math.atan((N + 1.0)) - Math.atan(N);
}
public static double code(double N) {
	return Math.atan2(1.0, (N + (1.0 + (N * N))));
}
def code(N):
	return math.atan((N + 1.0)) - math.atan(N)
def code(N):
	return math.atan2(1.0, (N + (1.0 + (N * N))))
function code(N)
	return Float64(atan(Float64(N + 1.0)) - atan(N))
end
function code(N)
	return atan(1.0, Float64(N + Float64(1.0 + Float64(N * N))))
end
function tmp = code(N)
	tmp = atan((N + 1.0)) - atan(N);
end
function tmp = code(N)
	tmp = atan2(1.0, (N + (1.0 + (N * N))));
end
code[N_] := N[(N[ArcTan[N[(N + 1.0), $MachinePrecision]], $MachinePrecision] - N[ArcTan[N], $MachinePrecision]), $MachinePrecision]
code[N_] := N[ArcTan[1.0 / N[(N + N[(1.0 + N[(N * N), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\tan^{-1} \left(N + 1\right) - \tan^{-1} N
\tan^{-1}_* \frac{1}{N + \left(1 + N \cdot N\right)}

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original14.9
Target0.4
Herbie0.4
\[\tan^{-1} \left(\frac{1}{1 + N \cdot \left(N + 1\right)}\right) \]

Derivation?

  1. Initial program 14.9

    \[\tan^{-1} \left(N + 1\right) - \tan^{-1} N \]
  2. Applied egg-rr13.8

    \[\leadsto \color{blue}{\tan^{-1}_* \frac{N + \left(1 - N\right)}{\left(N + 1\right) + N \cdot N}} \]
  3. Taylor expanded in N around 0 0.4

    \[\leadsto \tan^{-1}_* \frac{\color{blue}{1}}{\left(N + 1\right) + N \cdot N} \]
  4. Taylor expanded in N around 0 0.4

    \[\leadsto \color{blue}{\tan^{-1}_* \frac{1}{N + \left(1 + {N}^{2}\right)}} \]
  5. Simplified0.4

    \[\leadsto \color{blue}{\tan^{-1}_* \frac{1}{N + \left(1 + N \cdot N\right)}} \]
    Proof

    [Start]0.4

    \[ \tan^{-1}_* \frac{1}{N + \left(1 + {N}^{2}\right)} \]

    unpow2 [=>]0.4

    \[ \tan^{-1}_* \frac{1}{N + \left(1 + \color{blue}{N \cdot N}\right)} \]
  6. Final simplification0.4

    \[\leadsto \tan^{-1}_* \frac{1}{N + \left(1 + N \cdot N\right)} \]

Alternatives

Alternative 1
Error1.0
Cost7049
\[\begin{array}{l} \mathbf{if}\;N \leq -1 \lor \neg \left(N \leq 1\right):\\ \;\;\;\;\tan^{-1}_* \frac{1}{N + N \cdot N}\\ \mathbf{else}:\\ \;\;\;\;\tan^{-1}_* \frac{1}{1 + N}\\ \end{array} \]
Alternative 2
Error1.6
Cost6921
\[\begin{array}{l} \mathbf{if}\;N \leq -1 \lor \neg \left(N \leq 1\right):\\ \;\;\;\;\tan^{-1}_* \frac{1}{N \cdot N}\\ \mathbf{else}:\\ \;\;\;\;\tan^{-1}_* \frac{1}{1}\\ \end{array} \]
Alternative 3
Error1.3
Cost6921
\[\begin{array}{l} \mathbf{if}\;N \leq -0.62 \lor \neg \left(N \leq 1.65\right):\\ \;\;\;\;\tan^{-1}_* \frac{1}{N \cdot N}\\ \mathbf{else}:\\ \;\;\;\;\tan^{-1}_* \frac{1}{1 + N}\\ \end{array} \]
Alternative 4
Error0.4
Cost6912
\[\tan^{-1}_* \frac{1}{1 + N \cdot \left(1 + N\right)} \]
Alternative 5
Error30.9
Cost6528
\[\tan^{-1}_* \frac{1}{1} \]

Error

Reproduce?

herbie shell --seed 2023031 
(FPCore (N)
  :name "2atan (example 3.5)"
  :precision binary64

  :herbie-target
  (atan (/ 1.0 (+ 1.0 (* N (+ N 1.0)))))

  (- (atan (+ N 1.0)) (atan N)))