\[ \begin{array}{c}[a1, a2] = \mathsf{sort}([a1, a2])\\ \end{array} \]
\[\frac{\cos th}{\sqrt{2}} \cdot \left(a1 \cdot a1\right) + \frac{\cos th}{\sqrt{2}} \cdot \left(a2 \cdot a2\right)
\]
↓
\[\cos th \cdot \frac{\mathsf{fma}\left(a1, a1, a2 \cdot a2\right)}{\sqrt{2}}
\]
(FPCore (a1 a2 th)
:precision binary64
(+
(* (/ (cos th) (sqrt 2.0)) (* a1 a1))
(* (/ (cos th) (sqrt 2.0)) (* a2 a2))))
↓
(FPCore (a1 a2 th)
:precision binary64
(* (cos th) (/ (fma a1 a1 (* a2 a2)) (sqrt 2.0))))
double code(double a1, double a2, double th) {
return ((cos(th) / sqrt(2.0)) * (a1 * a1)) + ((cos(th) / sqrt(2.0)) * (a2 * a2));
}
↓
double code(double a1, double a2, double th) {
return cos(th) * (fma(a1, a1, (a2 * a2)) / sqrt(2.0));
}
function code(a1, a2, th)
return Float64(Float64(Float64(cos(th) / sqrt(2.0)) * Float64(a1 * a1)) + Float64(Float64(cos(th) / sqrt(2.0)) * Float64(a2 * a2)))
end
↓
function code(a1, a2, th)
return Float64(cos(th) * Float64(fma(a1, a1, Float64(a2 * a2)) / sqrt(2.0)))
end
code[a1_, a2_, th_] := N[(N[(N[(N[Cos[th], $MachinePrecision] / N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision] * N[(a1 * a1), $MachinePrecision]), $MachinePrecision] + N[(N[(N[Cos[th], $MachinePrecision] / N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision] * N[(a2 * a2), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[a1_, a2_, th_] := N[(N[Cos[th], $MachinePrecision] * N[(N[(a1 * a1 + N[(a2 * a2), $MachinePrecision]), $MachinePrecision] / N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\frac{\cos th}{\sqrt{2}} \cdot \left(a1 \cdot a1\right) + \frac{\cos th}{\sqrt{2}} \cdot \left(a2 \cdot a2\right)
↓
\cos th \cdot \frac{\mathsf{fma}\left(a1, a1, a2 \cdot a2\right)}{\sqrt{2}}
Alternatives
| Alternative 1 |
|---|
| Error | 14.5 |
|---|
| Cost | 13513 |
|---|
\[\begin{array}{l}
\mathbf{if}\;th \leq -5.2 \cdot 10^{+14} \lor \neg \left(th \leq 0.018\right):\\
\;\;\;\;a1 \cdot \left(a1 \cdot \frac{\cos th}{\sqrt{2}}\right)\\
\mathbf{else}:\\
\;\;\;\;\left(a2 \cdot a2 + a1 \cdot a1\right) \cdot \left(\sqrt{0.5} \cdot \left(-0.5 \cdot \left(th \cdot th\right) + 1\right)\right)\\
\end{array}
\]
| Alternative 2 |
|---|
| Error | 0.5 |
|---|
| Cost | 13504 |
|---|
\[\left(a2 \cdot a2 + a1 \cdot a1\right) \cdot \left(\cos th \cdot \sqrt{0.5}\right)
\]
| Alternative 3 |
|---|
| Error | 0.5 |
|---|
| Cost | 13504 |
|---|
\[\frac{\cos th}{\sqrt{2}} \cdot \left(a2 \cdot a2 + a1 \cdot a1\right)
\]
| Alternative 4 |
|---|
| Error | 8.0 |
|---|
| Cost | 13380 |
|---|
\[\begin{array}{l}
\mathbf{if}\;a1 \leq -1.55 \cdot 10^{-109}:\\
\;\;\;\;a1 \cdot \left(a1 \cdot \frac{\cos th}{\sqrt{2}}\right)\\
\mathbf{else}:\\
\;\;\;\;\cos th \cdot \left(\left(a2 \cdot a2\right) \cdot \sqrt{0.5}\right)\\
\end{array}
\]
| Alternative 5 |
|---|
| Error | 7.9 |
|---|
| Cost | 13380 |
|---|
\[\begin{array}{l}
\mathbf{if}\;a1 \leq -1.55 \cdot 10^{-109}:\\
\;\;\;\;a1 \cdot \left(a1 \cdot \frac{\cos th}{\sqrt{2}}\right)\\
\mathbf{else}:\\
\;\;\;\;\cos th \cdot \frac{a2}{\frac{\sqrt{2}}{a2}}\\
\end{array}
\]
| Alternative 6 |
|---|
| Error | 7.9 |
|---|
| Cost | 13380 |
|---|
\[\begin{array}{l}
\mathbf{if}\;a1 \leq -1.16 \cdot 10^{-109}:\\
\;\;\;\;a1 \cdot \left(a1 \cdot \frac{\cos th}{\sqrt{2}}\right)\\
\mathbf{else}:\\
\;\;\;\;\frac{a2 \cdot \left(\cos th \cdot a2\right)}{\sqrt{2}}\\
\end{array}
\]
| Alternative 7 |
|---|
| Error | 26.1 |
|---|
| Cost | 6976 |
|---|
\[\left(a2 \cdot a2 + a1 \cdot a1\right) \cdot \sqrt{0.5}
\]
| Alternative 8 |
|---|
| Error | 26.1 |
|---|
| Cost | 6976 |
|---|
\[\frac{a2 \cdot a2 + a1 \cdot a1}{\sqrt{2}}
\]
| Alternative 9 |
|---|
| Error | 30.0 |
|---|
| Cost | 6852 |
|---|
\[\begin{array}{l}
\mathbf{if}\;a1 \leq -1.45 \cdot 10^{-105}:\\
\;\;\;\;a1 \cdot \frac{a1}{\sqrt{2}}\\
\mathbf{else}:\\
\;\;\;\;a2 \cdot \frac{a2}{\sqrt{2}}\\
\end{array}
\]
| Alternative 10 |
|---|
| Error | 30.0 |
|---|
| Cost | 6852 |
|---|
\[\begin{array}{l}
\mathbf{if}\;a1 \leq -1.95 \cdot 10^{-105}:\\
\;\;\;\;a1 \cdot \frac{a1}{\sqrt{2}}\\
\mathbf{else}:\\
\;\;\;\;\frac{a2}{\frac{\sqrt{2}}{a2}}\\
\end{array}
\]
| Alternative 11 |
|---|
| Error | 30.0 |
|---|
| Cost | 6852 |
|---|
\[\begin{array}{l}
\mathbf{if}\;a1 \leq -4.2 \cdot 10^{-106}:\\
\;\;\;\;\frac{a1 \cdot a1}{\sqrt{2}}\\
\mathbf{else}:\\
\;\;\;\;\frac{a2}{\frac{\sqrt{2}}{a2}}\\
\end{array}
\]
| Alternative 12 |
|---|
| Error | 40.9 |
|---|
| Cost | 6720 |
|---|
\[\left(a1 \cdot a1\right) \cdot \sqrt{0.5}
\]
| Alternative 13 |
|---|
| Error | 40.9 |
|---|
| Cost | 6720 |
|---|
\[a1 \cdot \frac{a1}{\sqrt{2}}
\]