\[\sqrt[3]{x + 1} - \sqrt[3]{x}
\]
↓
\[\begin{array}{l}
t_0 := \sqrt[3]{1 + x}\\
t_1 := {t_0}^{2}\\
\frac{1}{t_1 + \sqrt[3]{x} \cdot \frac{x + \left(1 + x\right)}{t_1 + \sqrt[3]{x} \cdot \left(\sqrt[3]{x} - t_0\right)}}
\end{array}
\]
(FPCore (x) :precision binary64 (- (cbrt (+ x 1.0)) (cbrt x)))
↓
(FPCore (x)
:precision binary64
(let* ((t_0 (cbrt (+ 1.0 x))) (t_1 (pow t_0 2.0)))
(/
1.0
(+
t_1
(* (cbrt x) (/ (+ x (+ 1.0 x)) (+ t_1 (* (cbrt x) (- (cbrt x) t_0)))))))))double code(double x) {
return cbrt((x + 1.0)) - cbrt(x);
}
↓
double code(double x) {
double t_0 = cbrt((1.0 + x));
double t_1 = pow(t_0, 2.0);
return 1.0 / (t_1 + (cbrt(x) * ((x + (1.0 + x)) / (t_1 + (cbrt(x) * (cbrt(x) - t_0))))));
}
public static double code(double x) {
return Math.cbrt((x + 1.0)) - Math.cbrt(x);
}
↓
public static double code(double x) {
double t_0 = Math.cbrt((1.0 + x));
double t_1 = Math.pow(t_0, 2.0);
return 1.0 / (t_1 + (Math.cbrt(x) * ((x + (1.0 + x)) / (t_1 + (Math.cbrt(x) * (Math.cbrt(x) - t_0))))));
}
function code(x)
return Float64(cbrt(Float64(x + 1.0)) - cbrt(x))
end
↓
function code(x)
t_0 = cbrt(Float64(1.0 + x))
t_1 = t_0 ^ 2.0
return Float64(1.0 / Float64(t_1 + Float64(cbrt(x) * Float64(Float64(x + Float64(1.0 + x)) / Float64(t_1 + Float64(cbrt(x) * Float64(cbrt(x) - t_0)))))))
end
code[x_] := N[(N[Power[N[(x + 1.0), $MachinePrecision], 1/3], $MachinePrecision] - N[Power[x, 1/3], $MachinePrecision]), $MachinePrecision]
↓
code[x_] := Block[{t$95$0 = N[Power[N[(1.0 + x), $MachinePrecision], 1/3], $MachinePrecision]}, Block[{t$95$1 = N[Power[t$95$0, 2.0], $MachinePrecision]}, N[(1.0 / N[(t$95$1 + N[(N[Power[x, 1/3], $MachinePrecision] * N[(N[(x + N[(1.0 + x), $MachinePrecision]), $MachinePrecision] / N[(t$95$1 + N[(N[Power[x, 1/3], $MachinePrecision] * N[(N[Power[x, 1/3], $MachinePrecision] - t$95$0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]
\sqrt[3]{x + 1} - \sqrt[3]{x}
↓
\begin{array}{l}
t_0 := \sqrt[3]{1 + x}\\
t_1 := {t_0}^{2}\\
\frac{1}{t_1 + \sqrt[3]{x} \cdot \frac{x + \left(1 + x\right)}{t_1 + \sqrt[3]{x} \cdot \left(\sqrt[3]{x} - t_0\right)}}
\end{array}