Average Error: 29.7 → 0.9
Time: 17.5s
Precision: binary64
Cost: 46208
\[ \begin{array}{c}[a, b] = \mathsf{sort}([a, b])\\ \end{array} \]
\[\log \left(e^{a} + e^{b}\right) \]
\[\begin{array}{l} t_0 := 1 + e^{a}\\ \frac{b}{t_0} + \mathsf{fma}\left(b \cdot b, \frac{0.5}{t_0} + \frac{-0.5}{{t_0}^{2}}, \mathsf{log1p}\left(e^{a}\right)\right) \end{array} \]
(FPCore (a b) :precision binary64 (log (+ (exp a) (exp b))))
(FPCore (a b)
 :precision binary64
 (let* ((t_0 (+ 1.0 (exp a))))
   (+
    (/ b t_0)
    (fma (* b b) (+ (/ 0.5 t_0) (/ -0.5 (pow t_0 2.0))) (log1p (exp a))))))
double code(double a, double b) {
	return log((exp(a) + exp(b)));
}
double code(double a, double b) {
	double t_0 = 1.0 + exp(a);
	return (b / t_0) + fma((b * b), ((0.5 / t_0) + (-0.5 / pow(t_0, 2.0))), log1p(exp(a)));
}
function code(a, b)
	return log(Float64(exp(a) + exp(b)))
end
function code(a, b)
	t_0 = Float64(1.0 + exp(a))
	return Float64(Float64(b / t_0) + fma(Float64(b * b), Float64(Float64(0.5 / t_0) + Float64(-0.5 / (t_0 ^ 2.0))), log1p(exp(a))))
end
code[a_, b_] := N[Log[N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
code[a_, b_] := Block[{t$95$0 = N[(1.0 + N[Exp[a], $MachinePrecision]), $MachinePrecision]}, N[(N[(b / t$95$0), $MachinePrecision] + N[(N[(b * b), $MachinePrecision] * N[(N[(0.5 / t$95$0), $MachinePrecision] + N[(-0.5 / N[Power[t$95$0, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[Log[1 + N[Exp[a], $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\log \left(e^{a} + e^{b}\right)
\begin{array}{l}
t_0 := 1 + e^{a}\\
\frac{b}{t_0} + \mathsf{fma}\left(b \cdot b, \frac{0.5}{t_0} + \frac{-0.5}{{t_0}^{2}}, \mathsf{log1p}\left(e^{a}\right)\right)
\end{array}

Error

Derivation

  1. Initial program 29.7

    \[\log \left(e^{a} + e^{b}\right) \]
  2. Taylor expanded in b around 0 1.0

    \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \left(0.5 \cdot \left(\left(\frac{1}{1 + e^{a}} - \frac{1}{{\left(1 + e^{a}\right)}^{2}}\right) \cdot {b}^{2}\right) + \frac{b}{1 + e^{a}}\right)} \]
  3. Simplified0.9

    \[\leadsto \color{blue}{\frac{b}{1 + e^{a}} + \mathsf{fma}\left(b \cdot b, \frac{0.5}{1 + e^{a}} + \frac{-0.5}{{\left(1 + e^{a}\right)}^{2}}, \mathsf{log1p}\left(e^{a}\right)\right)} \]
    Proof

    [Start]1.0

    \[ \log \left(1 + e^{a}\right) + \left(0.5 \cdot \left(\left(\frac{1}{1 + e^{a}} - \frac{1}{{\left(1 + e^{a}\right)}^{2}}\right) \cdot {b}^{2}\right) + \frac{b}{1 + e^{a}}\right) \]

    associate-+r+ [=>]1.0

    \[ \color{blue}{\left(\log \left(1 + e^{a}\right) + 0.5 \cdot \left(\left(\frac{1}{1 + e^{a}} - \frac{1}{{\left(1 + e^{a}\right)}^{2}}\right) \cdot {b}^{2}\right)\right) + \frac{b}{1 + e^{a}}} \]

    +-commutative [=>]1.0

    \[ \color{blue}{\frac{b}{1 + e^{a}} + \left(\log \left(1 + e^{a}\right) + 0.5 \cdot \left(\left(\frac{1}{1 + e^{a}} - \frac{1}{{\left(1 + e^{a}\right)}^{2}}\right) \cdot {b}^{2}\right)\right)} \]

    +-commutative [=>]1.0

    \[ \frac{b}{1 + e^{a}} + \color{blue}{\left(0.5 \cdot \left(\left(\frac{1}{1 + e^{a}} - \frac{1}{{\left(1 + e^{a}\right)}^{2}}\right) \cdot {b}^{2}\right) + \log \left(1 + e^{a}\right)\right)} \]

    associate-*r* [=>]1.0

    \[ \frac{b}{1 + e^{a}} + \left(\color{blue}{\left(0.5 \cdot \left(\frac{1}{1 + e^{a}} - \frac{1}{{\left(1 + e^{a}\right)}^{2}}\right)\right) \cdot {b}^{2}} + \log \left(1 + e^{a}\right)\right) \]

    *-commutative [=>]1.0

    \[ \frac{b}{1 + e^{a}} + \left(\color{blue}{{b}^{2} \cdot \left(0.5 \cdot \left(\frac{1}{1 + e^{a}} - \frac{1}{{\left(1 + e^{a}\right)}^{2}}\right)\right)} + \log \left(1 + e^{a}\right)\right) \]

    fma-def [=>]1.0

    \[ \frac{b}{1 + e^{a}} + \color{blue}{\mathsf{fma}\left({b}^{2}, 0.5 \cdot \left(\frac{1}{1 + e^{a}} - \frac{1}{{\left(1 + e^{a}\right)}^{2}}\right), \log \left(1 + e^{a}\right)\right)} \]
  4. Final simplification0.9

    \[\leadsto \frac{b}{1 + e^{a}} + \mathsf{fma}\left(b \cdot b, \frac{0.5}{1 + e^{a}} + \frac{-0.5}{{\left(1 + e^{a}\right)}^{2}}, \mathsf{log1p}\left(e^{a}\right)\right) \]

Alternatives

Alternative 1
Error1.0
Cost19648
\[\frac{b}{1 + e^{a}} + \mathsf{log1p}\left(e^{a}\right) \]
Alternative 2
Error1.4
Cost19392
\[\mathsf{log1p}\left(e^{a} + \mathsf{expm1}\left(b\right)\right) \]
Alternative 3
Error2.6
Cost12992
\[\mathsf{log1p}\left(b + e^{a}\right) \]
Alternative 4
Error31.6
Cost12864
\[\mathsf{log1p}\left(e^{a}\right) \]
Alternative 5
Error32.4
Cost6720
\[b \cdot 0.5 + \log 2 \]
Alternative 6
Error32.5
Cost6592
\[\log \left(b + 2\right) \]
Alternative 7
Error32.9
Cost6464
\[\log 2 \]
Alternative 8
Error62.3
Cost192
\[a \cdot 0.5 \]
Alternative 9
Error61.2
Cost192
\[\frac{2}{b} \]

Error

Reproduce

herbie shell --seed 2023016 
(FPCore (a b)
  :name "symmetry log of sum of exp"
  :precision binary64
  (log (+ (exp a) (exp b))))