Average Error: 10.7 → 0.3
Time: 11.4s
Precision: binary64
Cost: 60688
\[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
\[\begin{array}{l} t_0 := \frac{\frac{1}{x}}{e^{y}}\\ t_1 := \frac{x}{x + y}\\ t_2 := \log t_1\\ t_3 := \frac{e^{x \cdot t_2}}{x}\\ t_4 := \frac{{\left(e^{x}\right)}^{t_2}}{x}\\ \mathbf{if}\;t_3 \leq -20000:\\ \;\;\;\;t_4\\ \mathbf{elif}\;t_3 \leq -1 \cdot 10^{-298}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;t_3 \leq 0:\\ \;\;\;\;t_4\\ \mathbf{elif}\;t_3 \leq 10^{-18}:\\ \;\;\;\;t_0\\ \mathbf{else}:\\ \;\;\;\;\frac{{t_1}^{x}}{x}\\ \end{array} \]
(FPCore (x y) :precision binary64 (/ (exp (* x (log (/ x (+ x y))))) x))
(FPCore (x y)
 :precision binary64
 (let* ((t_0 (/ (/ 1.0 x) (exp y)))
        (t_1 (/ x (+ x y)))
        (t_2 (log t_1))
        (t_3 (/ (exp (* x t_2)) x))
        (t_4 (/ (pow (exp x) t_2) x)))
   (if (<= t_3 -20000.0)
     t_4
     (if (<= t_3 -1e-298)
       t_0
       (if (<= t_3 0.0) t_4 (if (<= t_3 1e-18) t_0 (/ (pow t_1 x) x)))))))
double code(double x, double y) {
	return exp((x * log((x / (x + y))))) / x;
}
double code(double x, double y) {
	double t_0 = (1.0 / x) / exp(y);
	double t_1 = x / (x + y);
	double t_2 = log(t_1);
	double t_3 = exp((x * t_2)) / x;
	double t_4 = pow(exp(x), t_2) / x;
	double tmp;
	if (t_3 <= -20000.0) {
		tmp = t_4;
	} else if (t_3 <= -1e-298) {
		tmp = t_0;
	} else if (t_3 <= 0.0) {
		tmp = t_4;
	} else if (t_3 <= 1e-18) {
		tmp = t_0;
	} else {
		tmp = pow(t_1, x) / x;
	}
	return tmp;
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp((x * log((x / (x + y))))) / x
end function
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8) :: t_0
    real(8) :: t_1
    real(8) :: t_2
    real(8) :: t_3
    real(8) :: t_4
    real(8) :: tmp
    t_0 = (1.0d0 / x) / exp(y)
    t_1 = x / (x + y)
    t_2 = log(t_1)
    t_3 = exp((x * t_2)) / x
    t_4 = (exp(x) ** t_2) / x
    if (t_3 <= (-20000.0d0)) then
        tmp = t_4
    else if (t_3 <= (-1d-298)) then
        tmp = t_0
    else if (t_3 <= 0.0d0) then
        tmp = t_4
    else if (t_3 <= 1d-18) then
        tmp = t_0
    else
        tmp = (t_1 ** x) / x
    end if
    code = tmp
end function
public static double code(double x, double y) {
	return Math.exp((x * Math.log((x / (x + y))))) / x;
}
public static double code(double x, double y) {
	double t_0 = (1.0 / x) / Math.exp(y);
	double t_1 = x / (x + y);
	double t_2 = Math.log(t_1);
	double t_3 = Math.exp((x * t_2)) / x;
	double t_4 = Math.pow(Math.exp(x), t_2) / x;
	double tmp;
	if (t_3 <= -20000.0) {
		tmp = t_4;
	} else if (t_3 <= -1e-298) {
		tmp = t_0;
	} else if (t_3 <= 0.0) {
		tmp = t_4;
	} else if (t_3 <= 1e-18) {
		tmp = t_0;
	} else {
		tmp = Math.pow(t_1, x) / x;
	}
	return tmp;
}
def code(x, y):
	return math.exp((x * math.log((x / (x + y))))) / x
def code(x, y):
	t_0 = (1.0 / x) / math.exp(y)
	t_1 = x / (x + y)
	t_2 = math.log(t_1)
	t_3 = math.exp((x * t_2)) / x
	t_4 = math.pow(math.exp(x), t_2) / x
	tmp = 0
	if t_3 <= -20000.0:
		tmp = t_4
	elif t_3 <= -1e-298:
		tmp = t_0
	elif t_3 <= 0.0:
		tmp = t_4
	elif t_3 <= 1e-18:
		tmp = t_0
	else:
		tmp = math.pow(t_1, x) / x
	return tmp
function code(x, y)
	return Float64(exp(Float64(x * log(Float64(x / Float64(x + y))))) / x)
end
function code(x, y)
	t_0 = Float64(Float64(1.0 / x) / exp(y))
	t_1 = Float64(x / Float64(x + y))
	t_2 = log(t_1)
	t_3 = Float64(exp(Float64(x * t_2)) / x)
	t_4 = Float64((exp(x) ^ t_2) / x)
	tmp = 0.0
	if (t_3 <= -20000.0)
		tmp = t_4;
	elseif (t_3 <= -1e-298)
		tmp = t_0;
	elseif (t_3 <= 0.0)
		tmp = t_4;
	elseif (t_3 <= 1e-18)
		tmp = t_0;
	else
		tmp = Float64((t_1 ^ x) / x);
	end
	return tmp
end
function tmp = code(x, y)
	tmp = exp((x * log((x / (x + y))))) / x;
end
function tmp_2 = code(x, y)
	t_0 = (1.0 / x) / exp(y);
	t_1 = x / (x + y);
	t_2 = log(t_1);
	t_3 = exp((x * t_2)) / x;
	t_4 = (exp(x) ^ t_2) / x;
	tmp = 0.0;
	if (t_3 <= -20000.0)
		tmp = t_4;
	elseif (t_3 <= -1e-298)
		tmp = t_0;
	elseif (t_3 <= 0.0)
		tmp = t_4;
	elseif (t_3 <= 1e-18)
		tmp = t_0;
	else
		tmp = (t_1 ^ x) / x;
	end
	tmp_2 = tmp;
end
code[x_, y_] := N[(N[Exp[N[(x * N[Log[N[(x / N[(x + y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / x), $MachinePrecision]
code[x_, y_] := Block[{t$95$0 = N[(N[(1.0 / x), $MachinePrecision] / N[Exp[y], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(x / N[(x + y), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[Log[t$95$1], $MachinePrecision]}, Block[{t$95$3 = N[(N[Exp[N[(x * t$95$2), $MachinePrecision]], $MachinePrecision] / x), $MachinePrecision]}, Block[{t$95$4 = N[(N[Power[N[Exp[x], $MachinePrecision], t$95$2], $MachinePrecision] / x), $MachinePrecision]}, If[LessEqual[t$95$3, -20000.0], t$95$4, If[LessEqual[t$95$3, -1e-298], t$95$0, If[LessEqual[t$95$3, 0.0], t$95$4, If[LessEqual[t$95$3, 1e-18], t$95$0, N[(N[Power[t$95$1, x], $MachinePrecision] / x), $MachinePrecision]]]]]]]]]]
\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x}
\begin{array}{l}
t_0 := \frac{\frac{1}{x}}{e^{y}}\\
t_1 := \frac{x}{x + y}\\
t_2 := \log t_1\\
t_3 := \frac{e^{x \cdot t_2}}{x}\\
t_4 := \frac{{\left(e^{x}\right)}^{t_2}}{x}\\
\mathbf{if}\;t_3 \leq -20000:\\
\;\;\;\;t_4\\

\mathbf{elif}\;t_3 \leq -1 \cdot 10^{-298}:\\
\;\;\;\;t_0\\

\mathbf{elif}\;t_3 \leq 0:\\
\;\;\;\;t_4\\

\mathbf{elif}\;t_3 \leq 10^{-18}:\\
\;\;\;\;t_0\\

\mathbf{else}:\\
\;\;\;\;\frac{{t_1}^{x}}{x}\\


\end{array}

Error

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original10.7
Target8.0
Herbie0.3
\[\begin{array}{l} \mathbf{if}\;y < -3.7311844206647956 \cdot 10^{+94}:\\ \;\;\;\;\frac{e^{\frac{-1}{y}}}{x}\\ \mathbf{elif}\;y < 2.817959242728288 \cdot 10^{+37}:\\ \;\;\;\;\frac{{\left(\frac{x}{y + x}\right)}^{x}}{x}\\ \mathbf{elif}\;y < 2.347387415166998 \cdot 10^{+178}:\\ \;\;\;\;\log \left(e^{\frac{{\left(\frac{x}{y + x}\right)}^{x}}{x}}\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{e^{\frac{-1}{y}}}{x}\\ \end{array} \]

Derivation

  1. Split input into 3 regimes
  2. if (/.f64 (exp.f64 (*.f64 x (log.f64 (/.f64 x (+.f64 x y))))) x) < -2e4 or -9.99999999999999912e-299 < (/.f64 (exp.f64 (*.f64 x (log.f64 (/.f64 x (+.f64 x y))))) x) < 0.0

    1. Initial program 16.1

      \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
    2. Simplified0.7

      \[\leadsto \color{blue}{\frac{{\left(e^{x}\right)}^{\log \left(\frac{x}{x + y}\right)}}{x}} \]
      Proof

      [Start]16.1

      \[ \frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]

      exp-prod [=>]0.7

      \[ \frac{\color{blue}{{\left(e^{x}\right)}^{\log \left(\frac{x}{x + y}\right)}}}{x} \]

    if -2e4 < (/.f64 (exp.f64 (*.f64 x (log.f64 (/.f64 x (+.f64 x y))))) x) < -9.99999999999999912e-299 or 0.0 < (/.f64 (exp.f64 (*.f64 x (log.f64 (/.f64 x (+.f64 x y))))) x) < 1.0000000000000001e-18

    1. Initial program 11.5

      \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
    2. Simplified11.5

      \[\leadsto \color{blue}{\frac{{\left(\frac{x}{x + y}\right)}^{x}}{x}} \]
      Proof

      [Start]11.5

      \[ \frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]

      *-commutative [=>]11.5

      \[ \frac{e^{\color{blue}{\log \left(\frac{x}{x + y}\right) \cdot x}}}{x} \]

      exp-to-pow [=>]11.5

      \[ \frac{\color{blue}{{\left(\frac{x}{x + y}\right)}^{x}}}{x} \]
    3. Taylor expanded in x around inf 0.2

      \[\leadsto \frac{\color{blue}{e^{-1 \cdot y}}}{x} \]
    4. Simplified0.2

      \[\leadsto \frac{\color{blue}{e^{-y}}}{x} \]
      Proof

      [Start]0.2

      \[ \frac{e^{-1 \cdot y}}{x} \]

      mul-1-neg [=>]0.2

      \[ \frac{e^{\color{blue}{-y}}}{x} \]
    5. Applied egg-rr0.2

      \[\leadsto \color{blue}{{\left(x \cdot e^{y}\right)}^{-1}} \]
    6. Applied egg-rr0.2

      \[\leadsto \color{blue}{\frac{\frac{1}{x}}{e^{y}}} \]

    if 1.0000000000000001e-18 < (/.f64 (exp.f64 (*.f64 x (log.f64 (/.f64 x (+.f64 x y))))) x)

    1. Initial program 0.0

      \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
    2. Simplified0.0

      \[\leadsto \color{blue}{\frac{{\left(\frac{x}{x + y}\right)}^{x}}{x}} \]
      Proof

      [Start]0.0

      \[ \frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]

      *-commutative [=>]0.0

      \[ \frac{e^{\color{blue}{\log \left(\frac{x}{x + y}\right) \cdot x}}}{x} \]

      exp-to-pow [=>]0.0

      \[ \frac{\color{blue}{{\left(\frac{x}{x + y}\right)}^{x}}}{x} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification0.3

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \leq -20000:\\ \;\;\;\;\frac{{\left(e^{x}\right)}^{\log \left(\frac{x}{x + y}\right)}}{x}\\ \mathbf{elif}\;\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \leq -1 \cdot 10^{-298}:\\ \;\;\;\;\frac{\frac{1}{x}}{e^{y}}\\ \mathbf{elif}\;\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \leq 0:\\ \;\;\;\;\frac{{\left(e^{x}\right)}^{\log \left(\frac{x}{x + y}\right)}}{x}\\ \mathbf{elif}\;\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \leq 10^{-18}:\\ \;\;\;\;\frac{\frac{1}{x}}{e^{y}}\\ \mathbf{else}:\\ \;\;\;\;\frac{{\left(\frac{x}{x + y}\right)}^{x}}{x}\\ \end{array} \]

Alternatives

Alternative 1
Error0.5
Cost6985
\[\begin{array}{l} \mathbf{if}\;x \leq -6.5 \cdot 10^{+59} \lor \neg \left(x \leq 0.9\right):\\ \;\;\;\;\frac{\frac{1}{x}}{e^{y}}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x}\\ \end{array} \]
Alternative 2
Error0.5
Cost6921
\[\begin{array}{l} \mathbf{if}\;x \leq -7 \cdot 10^{+59} \lor \neg \left(x \leq 1.1\right):\\ \;\;\;\;\frac{e^{-y}}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x}\\ \end{array} \]
Alternative 3
Error5.1
Cost584
\[\begin{array}{l} \mathbf{if}\;y \leq 3600000000:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{elif}\;y \leq 5.8 \cdot 10^{+107}:\\ \;\;\;\;\frac{x}{x \cdot x}\\ \mathbf{else}:\\ \;\;\;\;\frac{y}{x \cdot y}\\ \end{array} \]
Alternative 4
Error1.7
Cost580
\[\begin{array}{l} \mathbf{if}\;y \leq 3.8 \cdot 10^{-17}:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{else}:\\ \;\;\;\;\left(1 + \frac{1}{x}\right) + -1\\ \end{array} \]
Alternative 5
Error7.7
Cost452
\[\begin{array}{l} \mathbf{if}\;y \leq 1.9 \cdot 10^{-13}:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{x \cdot x}\\ \end{array} \]
Alternative 6
Error9.6
Cost192
\[\frac{1}{x} \]

Error

Reproduce

herbie shell --seed 2023016 
(FPCore (x y)
  :name "Numeric.SpecFunctions:invIncompleteBetaWorker from math-functions-0.1.5.2, F"
  :precision binary64

  :herbie-target
  (if (< y -3.7311844206647956e+94) (/ (exp (/ -1.0 y)) x) (if (< y 2.817959242728288e+37) (/ (pow (/ x (+ y x)) x) x) (if (< y 2.347387415166998e+178) (log (exp (/ (pow (/ x (+ y x)) x) x))) (/ (exp (/ -1.0 y)) x))))

  (/ (exp (* x (log (/ x (+ x y))))) x))