Average Error: 10.9 → 2.6
Time: 3.8s
Precision: binary64
Cost: 2513
\[\frac{a1 \cdot a2}{b1 \cdot b2} \]
\[\begin{array}{l} t_0 := \frac{a1 \cdot a2}{b1 \cdot b2}\\ \mathbf{if}\;t_0 \leq -\infty:\\ \;\;\;\;\frac{a1 \cdot \frac{a2}{b2}}{b1}\\ \mathbf{elif}\;t_0 \leq -2 \cdot 10^{-300} \lor \neg \left(t_0 \leq 0\right) \land t_0 \leq 5 \cdot 10^{+278}:\\ \;\;\;\;t_0\\ \mathbf{else}:\\ \;\;\;\;\frac{a2}{b2} \cdot \frac{a1}{b1}\\ \end{array} \]
(FPCore (a1 a2 b1 b2) :precision binary64 (/ (* a1 a2) (* b1 b2)))
(FPCore (a1 a2 b1 b2)
 :precision binary64
 (let* ((t_0 (/ (* a1 a2) (* b1 b2))))
   (if (<= t_0 (- INFINITY))
     (/ (* a1 (/ a2 b2)) b1)
     (if (or (<= t_0 -2e-300) (and (not (<= t_0 0.0)) (<= t_0 5e+278)))
       t_0
       (* (/ a2 b2) (/ a1 b1))))))
double code(double a1, double a2, double b1, double b2) {
	return (a1 * a2) / (b1 * b2);
}
double code(double a1, double a2, double b1, double b2) {
	double t_0 = (a1 * a2) / (b1 * b2);
	double tmp;
	if (t_0 <= -((double) INFINITY)) {
		tmp = (a1 * (a2 / b2)) / b1;
	} else if ((t_0 <= -2e-300) || (!(t_0 <= 0.0) && (t_0 <= 5e+278))) {
		tmp = t_0;
	} else {
		tmp = (a2 / b2) * (a1 / b1);
	}
	return tmp;
}
public static double code(double a1, double a2, double b1, double b2) {
	return (a1 * a2) / (b1 * b2);
}
public static double code(double a1, double a2, double b1, double b2) {
	double t_0 = (a1 * a2) / (b1 * b2);
	double tmp;
	if (t_0 <= -Double.POSITIVE_INFINITY) {
		tmp = (a1 * (a2 / b2)) / b1;
	} else if ((t_0 <= -2e-300) || (!(t_0 <= 0.0) && (t_0 <= 5e+278))) {
		tmp = t_0;
	} else {
		tmp = (a2 / b2) * (a1 / b1);
	}
	return tmp;
}
def code(a1, a2, b1, b2):
	return (a1 * a2) / (b1 * b2)
def code(a1, a2, b1, b2):
	t_0 = (a1 * a2) / (b1 * b2)
	tmp = 0
	if t_0 <= -math.inf:
		tmp = (a1 * (a2 / b2)) / b1
	elif (t_0 <= -2e-300) or (not (t_0 <= 0.0) and (t_0 <= 5e+278)):
		tmp = t_0
	else:
		tmp = (a2 / b2) * (a1 / b1)
	return tmp
function code(a1, a2, b1, b2)
	return Float64(Float64(a1 * a2) / Float64(b1 * b2))
end
function code(a1, a2, b1, b2)
	t_0 = Float64(Float64(a1 * a2) / Float64(b1 * b2))
	tmp = 0.0
	if (t_0 <= Float64(-Inf))
		tmp = Float64(Float64(a1 * Float64(a2 / b2)) / b1);
	elseif ((t_0 <= -2e-300) || (!(t_0 <= 0.0) && (t_0 <= 5e+278)))
		tmp = t_0;
	else
		tmp = Float64(Float64(a2 / b2) * Float64(a1 / b1));
	end
	return tmp
end
function tmp = code(a1, a2, b1, b2)
	tmp = (a1 * a2) / (b1 * b2);
end
function tmp_2 = code(a1, a2, b1, b2)
	t_0 = (a1 * a2) / (b1 * b2);
	tmp = 0.0;
	if (t_0 <= -Inf)
		tmp = (a1 * (a2 / b2)) / b1;
	elseif ((t_0 <= -2e-300) || (~((t_0 <= 0.0)) && (t_0 <= 5e+278)))
		tmp = t_0;
	else
		tmp = (a2 / b2) * (a1 / b1);
	end
	tmp_2 = tmp;
end
code[a1_, a2_, b1_, b2_] := N[(N[(a1 * a2), $MachinePrecision] / N[(b1 * b2), $MachinePrecision]), $MachinePrecision]
code[a1_, a2_, b1_, b2_] := Block[{t$95$0 = N[(N[(a1 * a2), $MachinePrecision] / N[(b1 * b2), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, (-Infinity)], N[(N[(a1 * N[(a2 / b2), $MachinePrecision]), $MachinePrecision] / b1), $MachinePrecision], If[Or[LessEqual[t$95$0, -2e-300], And[N[Not[LessEqual[t$95$0, 0.0]], $MachinePrecision], LessEqual[t$95$0, 5e+278]]], t$95$0, N[(N[(a2 / b2), $MachinePrecision] * N[(a1 / b1), $MachinePrecision]), $MachinePrecision]]]]
\frac{a1 \cdot a2}{b1 \cdot b2}
\begin{array}{l}
t_0 := \frac{a1 \cdot a2}{b1 \cdot b2}\\
\mathbf{if}\;t_0 \leq -\infty:\\
\;\;\;\;\frac{a1 \cdot \frac{a2}{b2}}{b1}\\

\mathbf{elif}\;t_0 \leq -2 \cdot 10^{-300} \lor \neg \left(t_0 \leq 0\right) \land t_0 \leq 5 \cdot 10^{+278}:\\
\;\;\;\;t_0\\

\mathbf{else}:\\
\;\;\;\;\frac{a2}{b2} \cdot \frac{a1}{b1}\\


\end{array}

Error

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original10.9
Target12.0
Herbie2.6
\[\frac{a1}{b1} \cdot \frac{a2}{b2} \]

Derivation

  1. Split input into 3 regimes
  2. if (/.f64 (*.f64 a1 a2) (*.f64 b1 b2)) < -inf.0

    1. Initial program 64.0

      \[\frac{a1 \cdot a2}{b1 \cdot b2} \]
    2. Simplified26.8

      \[\leadsto \color{blue}{a2 \cdot \frac{a1}{b1 \cdot b2}} \]
      Proof

      [Start]64.0

      \[ \frac{a1 \cdot a2}{b1 \cdot b2} \]

      associate-*l/ [<=]26.8

      \[ \color{blue}{\frac{a1}{b1 \cdot b2} \cdot a2} \]

      *-commutative [=>]26.8

      \[ \color{blue}{a2 \cdot \frac{a1}{b1 \cdot b2}} \]
    3. Applied egg-rr19.8

      \[\leadsto \color{blue}{\frac{\frac{a2}{b2} \cdot a1}{b1}} \]

    if -inf.0 < (/.f64 (*.f64 a1 a2) (*.f64 b1 b2)) < -2.00000000000000005e-300 or 0.0 < (/.f64 (*.f64 a1 a2) (*.f64 b1 b2)) < 5.00000000000000029e278

    1. Initial program 0.8

      \[\frac{a1 \cdot a2}{b1 \cdot b2} \]

    if -2.00000000000000005e-300 < (/.f64 (*.f64 a1 a2) (*.f64 b1 b2)) < 0.0 or 5.00000000000000029e278 < (/.f64 (*.f64 a1 a2) (*.f64 b1 b2))

    1. Initial program 21.4

      \[\frac{a1 \cdot a2}{b1 \cdot b2} \]
    2. Simplified3.7

      \[\leadsto \color{blue}{\frac{a1}{b1} \cdot \frac{a2}{b2}} \]
      Proof

      [Start]21.4

      \[ \frac{a1 \cdot a2}{b1 \cdot b2} \]

      times-frac [=>]3.7

      \[ \color{blue}{\frac{a1}{b1} \cdot \frac{a2}{b2}} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification2.6

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{a1 \cdot a2}{b1 \cdot b2} \leq -\infty:\\ \;\;\;\;\frac{a1 \cdot \frac{a2}{b2}}{b1}\\ \mathbf{elif}\;\frac{a1 \cdot a2}{b1 \cdot b2} \leq -2 \cdot 10^{-300} \lor \neg \left(\frac{a1 \cdot a2}{b1 \cdot b2} \leq 0\right) \land \frac{a1 \cdot a2}{b1 \cdot b2} \leq 5 \cdot 10^{+278}:\\ \;\;\;\;\frac{a1 \cdot a2}{b1 \cdot b2}\\ \mathbf{else}:\\ \;\;\;\;\frac{a2}{b2} \cdot \frac{a1}{b1}\\ \end{array} \]

Alternatives

Alternative 1
Error2.4
Cost2514
\[\begin{array}{l} t_0 := \frac{a1 \cdot a2}{b1 \cdot b2}\\ \mathbf{if}\;t_0 \leq -\infty \lor \neg \left(t_0 \leq -2 \cdot 10^{-300} \lor \neg \left(t_0 \leq 0\right) \land t_0 \leq 5 \cdot 10^{+278}\right):\\ \;\;\;\;\frac{a2}{b2} \cdot \frac{a1}{b1}\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \]
Alternative 2
Error5.3
Cost1490
\[\begin{array}{l} \mathbf{if}\;b1 \cdot b2 \leq -\infty \lor \neg \left(b1 \cdot b2 \leq -1 \cdot 10^{-271} \lor \neg \left(b1 \cdot b2 \leq 10^{-309}\right) \land b1 \cdot b2 \leq 2 \cdot 10^{+203}\right):\\ \;\;\;\;\frac{a2}{b2} \cdot \frac{a1}{b1}\\ \mathbf{else}:\\ \;\;\;\;a2 \cdot \frac{a1}{b1 \cdot b2}\\ \end{array} \]
Alternative 3
Error10.8
Cost448
\[a2 \cdot \frac{a1}{b1 \cdot b2} \]

Error

Reproduce

herbie shell --seed 2023011 
(FPCore (a1 a2 b1 b2)
  :name "Quotient of products"
  :precision binary64

  :herbie-target
  (* (/ a1 b1) (/ a2 b2))

  (/ (* a1 a2) (* b1 b2)))