Average Error: 0.4 → 0.5
Time: 3.2s
Precision: binary64
Cost: 448
\[\frac{x \cdot 100}{x + y} \]
\[\frac{100}{\frac{y}{x} + 1} \]
(FPCore (x y) :precision binary64 (/ (* x 100.0) (+ x y)))
(FPCore (x y) :precision binary64 (/ 100.0 (+ (/ y x) 1.0)))
double code(double x, double y) {
	return (x * 100.0) / (x + y);
}
double code(double x, double y) {
	return 100.0 / ((y / x) + 1.0);
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = (x * 100.0d0) / (x + y)
end function
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = 100.0d0 / ((y / x) + 1.0d0)
end function
public static double code(double x, double y) {
	return (x * 100.0) / (x + y);
}
public static double code(double x, double y) {
	return 100.0 / ((y / x) + 1.0);
}
def code(x, y):
	return (x * 100.0) / (x + y)
def code(x, y):
	return 100.0 / ((y / x) + 1.0)
function code(x, y)
	return Float64(Float64(x * 100.0) / Float64(x + y))
end
function code(x, y)
	return Float64(100.0 / Float64(Float64(y / x) + 1.0))
end
function tmp = code(x, y)
	tmp = (x * 100.0) / (x + y);
end
function tmp = code(x, y)
	tmp = 100.0 / ((y / x) + 1.0);
end
code[x_, y_] := N[(N[(x * 100.0), $MachinePrecision] / N[(x + y), $MachinePrecision]), $MachinePrecision]
code[x_, y_] := N[(100.0 / N[(N[(y / x), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision]
\frac{x \cdot 100}{x + y}
\frac{100}{\frac{y}{x} + 1}

Error

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.4
Target0.2
Herbie0.5
\[\frac{x}{1} \cdot \frac{100}{x + y} \]

Derivation

  1. Initial program 0.4

    \[\frac{x \cdot 100}{x + y} \]
  2. Simplified0.2

    \[\leadsto \color{blue}{\frac{x}{\frac{x + y}{100}}} \]
    Proof

    [Start]0.4

    \[ \frac{x \cdot 100}{x + y} \]

    associate-/l* [=>]0.2

    \[ \color{blue}{\frac{x}{\frac{x + y}{100}}} \]
  3. Applied egg-rr23.0

    \[\leadsto \color{blue}{e^{\mathsf{log1p}\left(x \cdot \frac{100}{x + y}\right)} - 1} \]
  4. Simplified0.5

    \[\leadsto \color{blue}{\frac{100}{\frac{x + y}{x}}} \]
    Proof

    [Start]23.0

    \[ e^{\mathsf{log1p}\left(x \cdot \frac{100}{x + y}\right)} - 1 \]

    expm1-def [=>]1.0

    \[ \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left(x \cdot \frac{100}{x + y}\right)\right)} \]

    expm1-log1p [=>]0.2

    \[ \color{blue}{x \cdot \frac{100}{x + y}} \]

    *-commutative [=>]0.2

    \[ \color{blue}{\frac{100}{x + y} \cdot x} \]

    associate-/r/ [<=]0.5

    \[ \color{blue}{\frac{100}{\frac{x + y}{x}}} \]
  5. Taylor expanded in x around 0 0.5

    \[\leadsto \frac{100}{\color{blue}{1 + \frac{y}{x}}} \]
  6. Simplified0.5

    \[\leadsto \frac{100}{\color{blue}{\frac{y}{x} + 1}} \]
    Proof

    [Start]0.5

    \[ \frac{100}{1 + \frac{y}{x}} \]

    +-commutative [<=]0.5

    \[ \frac{100}{\color{blue}{\frac{y}{x} + 1}} \]
  7. Final simplification0.5

    \[\leadsto \frac{100}{\frac{y}{x} + 1} \]

Alternatives

Alternative 1
Error16.8
Cost585
\[\begin{array}{l} \mathbf{if}\;y \leq -5.5 \cdot 10^{-87} \lor \neg \left(y \leq 3 \cdot 10^{-63}\right):\\ \;\;\;\;100 \cdot \frac{x}{y}\\ \mathbf{else}:\\ \;\;\;\;100\\ \end{array} \]
Alternative 2
Error0.2
Cost448
\[x \cdot \frac{100}{y + x} \]
Alternative 3
Error31.7
Cost64
\[100 \]

Error

Reproduce

herbie shell --seed 2023010 
(FPCore (x y)
  :name "Development.Shake.Progress:message from shake-0.15.5"
  :precision binary64

  :herbie-target
  (* (/ x 1.0) (/ 100.0 (+ x y)))

  (/ (* x 100.0) (+ x y)))