Average Error: 0.2 → 0.2
Time: 28.4s
Precision: binary64
Cost: 13248
\[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \]
\[\frac{1}{\sin B} - \frac{x}{\tan B} \]
(FPCore (B x)
 :precision binary64
 (+ (- (* x (/ 1.0 (tan B)))) (/ 1.0 (sin B))))
(FPCore (B x) :precision binary64 (- (/ 1.0 (sin B)) (/ x (tan B))))
double code(double B, double x) {
	return -(x * (1.0 / tan(B))) + (1.0 / sin(B));
}
double code(double B, double x) {
	return (1.0 / sin(B)) - (x / tan(B));
}
real(8) function code(b, x)
    real(8), intent (in) :: b
    real(8), intent (in) :: x
    code = -(x * (1.0d0 / tan(b))) + (1.0d0 / sin(b))
end function
real(8) function code(b, x)
    real(8), intent (in) :: b
    real(8), intent (in) :: x
    code = (1.0d0 / sin(b)) - (x / tan(b))
end function
public static double code(double B, double x) {
	return -(x * (1.0 / Math.tan(B))) + (1.0 / Math.sin(B));
}
public static double code(double B, double x) {
	return (1.0 / Math.sin(B)) - (x / Math.tan(B));
}
def code(B, x):
	return -(x * (1.0 / math.tan(B))) + (1.0 / math.sin(B))
def code(B, x):
	return (1.0 / math.sin(B)) - (x / math.tan(B))
function code(B, x)
	return Float64(Float64(-Float64(x * Float64(1.0 / tan(B)))) + Float64(1.0 / sin(B)))
end
function code(B, x)
	return Float64(Float64(1.0 / sin(B)) - Float64(x / tan(B)))
end
function tmp = code(B, x)
	tmp = -(x * (1.0 / tan(B))) + (1.0 / sin(B));
end
function tmp = code(B, x)
	tmp = (1.0 / sin(B)) - (x / tan(B));
end
code[B_, x_] := N[((-N[(x * N[(1.0 / N[Tan[B], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]) + N[(1.0 / N[Sin[B], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
code[B_, x_] := N[(N[(1.0 / N[Sin[B], $MachinePrecision]), $MachinePrecision] - N[(x / N[Tan[B], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B}
\frac{1}{\sin B} - \frac{x}{\tan B}

Error

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.2

    \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \]
  2. Simplified0.2

    \[\leadsto \color{blue}{\frac{1}{\sin B} - \frac{x}{\tan B}} \]
    Proof

Alternatives

Alternative 1
Error0.9
Cost7240
\[\begin{array}{l} t_0 := \frac{x}{\tan B}\\ \mathbf{if}\;x \leq -1.75:\\ \;\;\;\;\frac{1}{B} - t_0\\ \mathbf{elif}\;x \leq 4.5:\\ \;\;\;\;\frac{1}{\sin B} - \frac{x}{B}\\ \mathbf{else}:\\ \;\;\;\;\left(0.3333333333333333 - \frac{-1}{B}\right) - t_0\\ \end{array} \]
Alternative 2
Error0.9
Cost7112
\[\begin{array}{l} t_0 := \frac{1}{B} - \frac{x}{\tan B}\\ \mathbf{if}\;x \leq -1.1:\\ \;\;\;\;t_0\\ \mathbf{elif}\;x \leq 1.36:\\ \;\;\;\;\frac{1}{\sin B} - \frac{x}{B}\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \]
Alternative 3
Error19.2
Cost6848
\[\frac{1}{B} - \frac{x}{\tan B} \]
Alternative 4
Error37.4
Cost520
\[\begin{array}{l} t_0 := -\frac{x}{B}\\ \mathbf{if}\;x \leq -3.2 \cdot 10^{-9}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;x \leq 420000:\\ \;\;\;\;\frac{1}{B}\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \]
Alternative 5
Error36.5
Cost320
\[\frac{1 - x}{B} \]
Alternative 6
Error45.2
Cost192
\[\frac{1}{B} \]

Error

Reproduce

herbie shell --seed 2023010 
(FPCore (B x)
  :name "VandenBroeck and Keller, Equation (24)"
  :precision binary64
  (+ (- (* x (/ 1.0 (tan B)))) (/ 1.0 (sin B))))