Math FPCore C Java Python Julia MATLAB Wolfram TeX \[\frac{x \cdot \left(y + z\right)}{z}
\]
↓
\[\begin{array}{l}
t_0 := \frac{x \cdot \left(y + z\right)}{z}\\
t_1 := \begin{array}{l}
\mathbf{if}\;y + z \ne 0:\\
\;\;\;\;\frac{x}{\frac{z}{y + z}}\\
\mathbf{else}:\\
\;\;\;\;\frac{\left(y + z\right) \cdot x}{z}\\
\end{array}\\
\mathbf{if}\;t_0 \leq -\infty:\\
\;\;\;\;\left(1 + \frac{y}{z}\right) \cdot x\\
\mathbf{elif}\;t_0 \leq -5 \cdot 10^{-105}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;t_0 \leq 10^{-153}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t_0 \leq 5 \cdot 10^{+270}:\\
\;\;\;\;t_0\\
\mathbf{else}:\\
\;\;\;\;t_1\\
\end{array}
\]
(FPCore (x y z) :precision binary64 (/ (* x (+ y z)) z)) ↓
(FPCore (x y z)
:precision binary64
(let* ((t_0 (/ (* x (+ y z)) z))
(t_1 (if (!= (+ y z) 0.0) (/ x (/ z (+ y z))) (/ (* (+ y z) x) z))))
(if (<= t_0 (- INFINITY))
(* (+ 1.0 (/ y z)) x)
(if (<= t_0 -5e-105)
t_0
(if (<= t_0 1e-153) t_1 (if (<= t_0 5e+270) t_0 t_1)))))) double code(double x, double y, double z) {
return (x * (y + z)) / z;
}
↓
double code(double x, double y, double z) {
double t_0 = (x * (y + z)) / z;
double tmp;
if ((y + z) != 0.0) {
tmp = x / (z / (y + z));
} else {
tmp = ((y + z) * x) / z;
}
double t_1 = tmp;
double tmp_1;
if (t_0 <= -((double) INFINITY)) {
tmp_1 = (1.0 + (y / z)) * x;
} else if (t_0 <= -5e-105) {
tmp_1 = t_0;
} else if (t_0 <= 1e-153) {
tmp_1 = t_1;
} else if (t_0 <= 5e+270) {
tmp_1 = t_0;
} else {
tmp_1 = t_1;
}
return tmp_1;
}
public static double code(double x, double y, double z) {
return (x * (y + z)) / z;
}
↓
public static double code(double x, double y, double z) {
double t_0 = (x * (y + z)) / z;
double tmp;
if ((y + z) != 0.0) {
tmp = x / (z / (y + z));
} else {
tmp = ((y + z) * x) / z;
}
double t_1 = tmp;
double tmp_1;
if (t_0 <= -Double.POSITIVE_INFINITY) {
tmp_1 = (1.0 + (y / z)) * x;
} else if (t_0 <= -5e-105) {
tmp_1 = t_0;
} else if (t_0 <= 1e-153) {
tmp_1 = t_1;
} else if (t_0 <= 5e+270) {
tmp_1 = t_0;
} else {
tmp_1 = t_1;
}
return tmp_1;
}
def code(x, y, z):
return (x * (y + z)) / z
↓
def code(x, y, z):
t_0 = (x * (y + z)) / z
tmp = 0
if (y + z) != 0.0:
tmp = x / (z / (y + z))
else:
tmp = ((y + z) * x) / z
t_1 = tmp
tmp_1 = 0
if t_0 <= -math.inf:
tmp_1 = (1.0 + (y / z)) * x
elif t_0 <= -5e-105:
tmp_1 = t_0
elif t_0 <= 1e-153:
tmp_1 = t_1
elif t_0 <= 5e+270:
tmp_1 = t_0
else:
tmp_1 = t_1
return tmp_1
function code(x, y, z)
return Float64(Float64(x * Float64(y + z)) / z)
end
↓
function code(x, y, z)
t_0 = Float64(Float64(x * Float64(y + z)) / z)
tmp = 0.0
if (Float64(y + z) != 0.0)
tmp = Float64(x / Float64(z / Float64(y + z)));
else
tmp = Float64(Float64(Float64(y + z) * x) / z);
end
t_1 = tmp
tmp_1 = 0.0
if (t_0 <= Float64(-Inf))
tmp_1 = Float64(Float64(1.0 + Float64(y / z)) * x);
elseif (t_0 <= -5e-105)
tmp_1 = t_0;
elseif (t_0 <= 1e-153)
tmp_1 = t_1;
elseif (t_0 <= 5e+270)
tmp_1 = t_0;
else
tmp_1 = t_1;
end
return tmp_1
end
function tmp = code(x, y, z)
tmp = (x * (y + z)) / z;
end
↓
function tmp_3 = code(x, y, z)
t_0 = (x * (y + z)) / z;
tmp = 0.0;
if ((y + z) ~= 0.0)
tmp = x / (z / (y + z));
else
tmp = ((y + z) * x) / z;
end
t_1 = tmp;
tmp_2 = 0.0;
if (t_0 <= -Inf)
tmp_2 = (1.0 + (y / z)) * x;
elseif (t_0 <= -5e-105)
tmp_2 = t_0;
elseif (t_0 <= 1e-153)
tmp_2 = t_1;
elseif (t_0 <= 5e+270)
tmp_2 = t_0;
else
tmp_2 = t_1;
end
tmp_3 = tmp_2;
end
code[x_, y_, z_] := N[(N[(x * N[(y + z), $MachinePrecision]), $MachinePrecision] / z), $MachinePrecision]
↓
code[x_, y_, z_] := Block[{t$95$0 = N[(N[(x * N[(y + z), $MachinePrecision]), $MachinePrecision] / z), $MachinePrecision]}, Block[{t$95$1 = If[Unequal[N[(y + z), $MachinePrecision], 0.0], N[(x / N[(z / N[(y + z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(N[(y + z), $MachinePrecision] * x), $MachinePrecision] / z), $MachinePrecision]]}, If[LessEqual[t$95$0, (-Infinity)], N[(N[(1.0 + N[(y / z), $MachinePrecision]), $MachinePrecision] * x), $MachinePrecision], If[LessEqual[t$95$0, -5e-105], t$95$0, If[LessEqual[t$95$0, 1e-153], t$95$1, If[LessEqual[t$95$0, 5e+270], t$95$0, t$95$1]]]]]]
\frac{x \cdot \left(y + z\right)}{z}
↓
\begin{array}{l}
t_0 := \frac{x \cdot \left(y + z\right)}{z}\\
t_1 := \begin{array}{l}
\mathbf{if}\;y + z \ne 0:\\
\;\;\;\;\frac{x}{\frac{z}{y + z}}\\
\mathbf{else}:\\
\;\;\;\;\frac{\left(y + z\right) \cdot x}{z}\\
\end{array}\\
\mathbf{if}\;t_0 \leq -\infty:\\
\;\;\;\;\left(1 + \frac{y}{z}\right) \cdot x\\
\mathbf{elif}\;t_0 \leq -5 \cdot 10^{-105}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;t_0 \leq 10^{-153}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t_0 \leq 5 \cdot 10^{+270}:\\
\;\;\;\;t_0\\
\mathbf{else}:\\
\;\;\;\;t_1\\
\end{array}