\[\frac{\cos th}{\sqrt{2}} \cdot \left(a1 \cdot a1\right) + \frac{\cos th}{\sqrt{2}} \cdot \left(a2 \cdot a2\right)
\]
↓
\[\left(\sqrt{0.5} \cdot \cos th\right) \cdot \left(a1 \cdot a1 + a2 \cdot a2\right)
\]
(FPCore (a1 a2 th)
:precision binary64
(+
(* (/ (cos th) (sqrt 2.0)) (* a1 a1))
(* (/ (cos th) (sqrt 2.0)) (* a2 a2))))
↓
(FPCore (a1 a2 th)
:precision binary64
(* (* (sqrt 0.5) (cos th)) (+ (* a1 a1) (* a2 a2))))
double code(double a1, double a2, double th) {
return ((cos(th) / sqrt(2.0)) * (a1 * a1)) + ((cos(th) / sqrt(2.0)) * (a2 * a2));
}
↓
double code(double a1, double a2, double th) {
return (sqrt(0.5) * cos(th)) * ((a1 * a1) + (a2 * a2));
}
real(8) function code(a1, a2, th)
real(8), intent (in) :: a1
real(8), intent (in) :: a2
real(8), intent (in) :: th
code = ((cos(th) / sqrt(2.0d0)) * (a1 * a1)) + ((cos(th) / sqrt(2.0d0)) * (a2 * a2))
end function
↓
real(8) function code(a1, a2, th)
real(8), intent (in) :: a1
real(8), intent (in) :: a2
real(8), intent (in) :: th
code = (sqrt(0.5d0) * cos(th)) * ((a1 * a1) + (a2 * a2))
end function
public static double code(double a1, double a2, double th) {
return ((Math.cos(th) / Math.sqrt(2.0)) * (a1 * a1)) + ((Math.cos(th) / Math.sqrt(2.0)) * (a2 * a2));
}
↓
public static double code(double a1, double a2, double th) {
return (Math.sqrt(0.5) * Math.cos(th)) * ((a1 * a1) + (a2 * a2));
}
def code(a1, a2, th):
return ((math.cos(th) / math.sqrt(2.0)) * (a1 * a1)) + ((math.cos(th) / math.sqrt(2.0)) * (a2 * a2))
↓
def code(a1, a2, th):
return (math.sqrt(0.5) * math.cos(th)) * ((a1 * a1) + (a2 * a2))
function code(a1, a2, th)
return Float64(Float64(Float64(cos(th) / sqrt(2.0)) * Float64(a1 * a1)) + Float64(Float64(cos(th) / sqrt(2.0)) * Float64(a2 * a2)))
end
↓
function code(a1, a2, th)
return Float64(Float64(sqrt(0.5) * cos(th)) * Float64(Float64(a1 * a1) + Float64(a2 * a2)))
end
function tmp = code(a1, a2, th)
tmp = ((cos(th) / sqrt(2.0)) * (a1 * a1)) + ((cos(th) / sqrt(2.0)) * (a2 * a2));
end
↓
function tmp = code(a1, a2, th)
tmp = (sqrt(0.5) * cos(th)) * ((a1 * a1) + (a2 * a2));
end
code[a1_, a2_, th_] := N[(N[(N[(N[Cos[th], $MachinePrecision] / N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision] * N[(a1 * a1), $MachinePrecision]), $MachinePrecision] + N[(N[(N[Cos[th], $MachinePrecision] / N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision] * N[(a2 * a2), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[a1_, a2_, th_] := N[(N[(N[Sqrt[0.5], $MachinePrecision] * N[Cos[th], $MachinePrecision]), $MachinePrecision] * N[(N[(a1 * a1), $MachinePrecision] + N[(a2 * a2), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\frac{\cos th}{\sqrt{2}} \cdot \left(a1 \cdot a1\right) + \frac{\cos th}{\sqrt{2}} \cdot \left(a2 \cdot a2\right)
↓
\left(\sqrt{0.5} \cdot \cos th\right) \cdot \left(a1 \cdot a1 + a2 \cdot a2\right)
Alternatives
| Alternative 1 |
|---|
| Error | 14.8 |
|---|
| Cost | 19780 |
|---|
\[\begin{array}{l}
\mathbf{if}\;\cos th \leq 0.996:\\
\;\;\;\;a1 \cdot \left(\cos th \cdot \left(\sqrt{0.5} \cdot a1\right)\right)\\
\mathbf{else}:\\
\;\;\;\;\sqrt{0.5} \cdot \left(a1 \cdot a1 + a2 \cdot a2\right)\\
\end{array}
\]
| Alternative 2 |
|---|
| Error | 14.8 |
|---|
| Cost | 19780 |
|---|
\[\begin{array}{l}
\mathbf{if}\;\cos th \leq 0.996:\\
\;\;\;\;a1 \cdot \frac{\cos th}{\frac{\sqrt{2}}{a1}}\\
\mathbf{else}:\\
\;\;\;\;\sqrt{0.5} \cdot \left(a1 \cdot a1 + a2 \cdot a2\right)\\
\end{array}
\]
| Alternative 3 |
|---|
| Error | 20.7 |
|---|
| Cost | 13380 |
|---|
\[\begin{array}{l}
\mathbf{if}\;a2 \leq 2.35 \cdot 10^{-138}:\\
\;\;\;\;a1 \cdot \frac{\cos th \cdot a1}{\sqrt{2}}\\
\mathbf{else}:\\
\;\;\;\;a2 \cdot \left(a2 \cdot \frac{\cos th}{\sqrt{2}}\right)\\
\end{array}
\]
| Alternative 4 |
|---|
| Error | 20.7 |
|---|
| Cost | 13380 |
|---|
\[\begin{array}{l}
\mathbf{if}\;a2 \leq 4.2 \cdot 10^{-139}:\\
\;\;\;\;a1 \cdot \frac{\cos th \cdot a1}{\sqrt{2}}\\
\mathbf{else}:\\
\;\;\;\;a2 \cdot \frac{\cos th}{\frac{\sqrt{2}}{a2}}\\
\end{array}
\]
| Alternative 5 |
|---|
| Error | 20.6 |
|---|
| Cost | 13380 |
|---|
\[\begin{array}{l}
\mathbf{if}\;a2 \leq 2.7 \cdot 10^{-138}:\\
\;\;\;\;a1 \cdot \frac{\cos th \cdot a1}{\sqrt{2}}\\
\mathbf{else}:\\
\;\;\;\;\frac{a2}{\sqrt{2}} \cdot \left(\cos th \cdot a2\right)\\
\end{array}
\]
| Alternative 6 |
|---|
| Error | 26.1 |
|---|
| Cost | 6976 |
|---|
\[\sqrt{0.5} \cdot \left(a1 \cdot a1 + a2 \cdot a2\right)
\]
| Alternative 7 |
|---|
| Error | 37.1 |
|---|
| Cost | 6852 |
|---|
\[\begin{array}{l}
\mathbf{if}\;a1 \leq -8.2 \cdot 10^{-162}:\\
\;\;\;\;\sqrt{0.5} \cdot \left(a1 \cdot a1\right)\\
\mathbf{else}:\\
\;\;\;\;\sqrt{0.5} \cdot \left(a2 \cdot a2\right)\\
\end{array}
\]
| Alternative 8 |
|---|
| Error | 37.1 |
|---|
| Cost | 6852 |
|---|
\[\begin{array}{l}
\mathbf{if}\;a1 \leq -8.2 \cdot 10^{-162}:\\
\;\;\;\;\sqrt{0.5} \cdot \left(a1 \cdot a1\right)\\
\mathbf{else}:\\
\;\;\;\;a2 \cdot \frac{a2}{\sqrt{2}}\\
\end{array}
\]
| Alternative 9 |
|---|
| Error | 40.8 |
|---|
| Cost | 6720 |
|---|
\[a1 \cdot \left(\sqrt{0.5} \cdot a1\right)
\]
| Alternative 10 |
|---|
| Error | 40.8 |
|---|
| Cost | 6720 |
|---|
\[\sqrt{0.5} \cdot \left(a1 \cdot a1\right)
\]