Math FPCore C Java Julia Wolfram TeX \[\frac{\tan \left(\frac{x}{y \cdot 2}\right)}{\sin \left(\frac{x}{y \cdot 2}\right)}
\]
↓
\[\begin{array}{l}
t_0 := \frac{x}{y \cdot 2}\\
\mathbf{if}\;\frac{\tan t_0}{\sin t_0} \leq 9.5:\\
\;\;\;\;\sqrt[3]{{\cos \left(\left({\left(\sqrt[3]{\frac{x \cdot 0.5}{y}}\right)}^{2} \cdot \sqrt[3]{x}\right) \cdot \sqrt[3]{\frac{0.5}{y}}\right)}^{-3}}\\
\mathbf{else}:\\
\;\;\;\;1\\
\end{array}
\]
(FPCore (x y)
:precision binary64
(/ (tan (/ x (* y 2.0))) (sin (/ x (* y 2.0))))) ↓
(FPCore (x y)
:precision binary64
(let* ((t_0 (/ x (* y 2.0))))
(if (<= (/ (tan t_0) (sin t_0)) 9.5)
(cbrt
(pow
(cos (* (* (pow (cbrt (/ (* x 0.5) y)) 2.0) (cbrt x)) (cbrt (/ 0.5 y))))
-3.0))
1.0))) double code(double x, double y) {
return tan((x / (y * 2.0))) / sin((x / (y * 2.0)));
}
↓
double code(double x, double y) {
double t_0 = x / (y * 2.0);
double tmp;
if ((tan(t_0) / sin(t_0)) <= 9.5) {
tmp = cbrt(pow(cos(((pow(cbrt(((x * 0.5) / y)), 2.0) * cbrt(x)) * cbrt((0.5 / y)))), -3.0));
} else {
tmp = 1.0;
}
return tmp;
}
public static double code(double x, double y) {
return Math.tan((x / (y * 2.0))) / Math.sin((x / (y * 2.0)));
}
↓
public static double code(double x, double y) {
double t_0 = x / (y * 2.0);
double tmp;
if ((Math.tan(t_0) / Math.sin(t_0)) <= 9.5) {
tmp = Math.cbrt(Math.pow(Math.cos(((Math.pow(Math.cbrt(((x * 0.5) / y)), 2.0) * Math.cbrt(x)) * Math.cbrt((0.5 / y)))), -3.0));
} else {
tmp = 1.0;
}
return tmp;
}
function code(x, y)
return Float64(tan(Float64(x / Float64(y * 2.0))) / sin(Float64(x / Float64(y * 2.0))))
end
↓
function code(x, y)
t_0 = Float64(x / Float64(y * 2.0))
tmp = 0.0
if (Float64(tan(t_0) / sin(t_0)) <= 9.5)
tmp = cbrt((cos(Float64(Float64((cbrt(Float64(Float64(x * 0.5) / y)) ^ 2.0) * cbrt(x)) * cbrt(Float64(0.5 / y)))) ^ -3.0));
else
tmp = 1.0;
end
return tmp
end
code[x_, y_] := N[(N[Tan[N[(x / N[(y * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[Sin[N[(x / N[(y * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_] := Block[{t$95$0 = N[(x / N[(y * 2.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[(N[Tan[t$95$0], $MachinePrecision] / N[Sin[t$95$0], $MachinePrecision]), $MachinePrecision], 9.5], N[Power[N[Power[N[Cos[N[(N[(N[Power[N[Power[N[(N[(x * 0.5), $MachinePrecision] / y), $MachinePrecision], 1/3], $MachinePrecision], 2.0], $MachinePrecision] * N[Power[x, 1/3], $MachinePrecision]), $MachinePrecision] * N[Power[N[(0.5 / y), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]], $MachinePrecision], -3.0], $MachinePrecision], 1/3], $MachinePrecision], 1.0]]
\frac{\tan \left(\frac{x}{y \cdot 2}\right)}{\sin \left(\frac{x}{y \cdot 2}\right)}
↓
\begin{array}{l}
t_0 := \frac{x}{y \cdot 2}\\
\mathbf{if}\;\frac{\tan t_0}{\sin t_0} \leq 9.5:\\
\;\;\;\;\sqrt[3]{{\cos \left(\left({\left(\sqrt[3]{\frac{x \cdot 0.5}{y}}\right)}^{2} \cdot \sqrt[3]{x}\right) \cdot \sqrt[3]{\frac{0.5}{y}}\right)}^{-3}}\\
\mathbf{else}:\\
\;\;\;\;1\\
\end{array}