\[\frac{x + \frac{y \cdot z}{t}}{\left(a + 1\right) + \frac{y \cdot b}{t}}
\]
↓
\[\begin{array}{l}
t_1 := \frac{z + x \cdot \frac{t}{y}}{b}\\
t_2 := \frac{x + \frac{y \cdot z}{t}}{\frac{y \cdot b}{t} + \left(a + 1\right)}\\
t_3 := 1 + \left(a + \frac{y}{\frac{t}{b}}\right)\\
\mathbf{if}\;t_2 \leq -5 \cdot 10^{+223}:\\
\;\;\;\;\mathsf{fma}\left(\frac{y}{t}, \frac{z}{t_3}, \frac{x}{t_3}\right)\\
\mathbf{elif}\;t_2 \leq -5 \cdot 10^{-298}:\\
\;\;\;\;t_2\\
\mathbf{elif}\;t_2 \leq 0:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t_2 \leq 10^{+301}:\\
\;\;\;\;t_2\\
\mathbf{else}:\\
\;\;\;\;t_1\\
\end{array}
\]
double code(double x, double y, double z, double t, double a, double b) {
return (x + ((y * z) / t)) / ((a + 1.0) + ((y * b) / t));
}
↓
double code(double x, double y, double z, double t, double a, double b) {
double t_1 = (z + (x * (t / y))) / b;
double t_2 = (x + ((y * z) / t)) / (((y * b) / t) + (a + 1.0));
double t_3 = 1.0 + (a + (y / (t / b)));
double tmp;
if (t_2 <= -5e+223) {
tmp = fma((y / t), (z / t_3), (x / t_3));
} else if (t_2 <= -5e-298) {
tmp = t_2;
} else if (t_2 <= 0.0) {
tmp = t_1;
} else if (t_2 <= 1e+301) {
tmp = t_2;
} else {
tmp = t_1;
}
return tmp;
}
function code(x, y, z, t, a, b)
return Float64(Float64(x + Float64(Float64(y * z) / t)) / Float64(Float64(a + 1.0) + Float64(Float64(y * b) / t)))
end
↓
function code(x, y, z, t, a, b)
t_1 = Float64(Float64(z + Float64(x * Float64(t / y))) / b)
t_2 = Float64(Float64(x + Float64(Float64(y * z) / t)) / Float64(Float64(Float64(y * b) / t) + Float64(a + 1.0)))
t_3 = Float64(1.0 + Float64(a + Float64(y / Float64(t / b))))
tmp = 0.0
if (t_2 <= -5e+223)
tmp = fma(Float64(y / t), Float64(z / t_3), Float64(x / t_3));
elseif (t_2 <= -5e-298)
tmp = t_2;
elseif (t_2 <= 0.0)
tmp = t_1;
elseif (t_2 <= 1e+301)
tmp = t_2;
else
tmp = t_1;
end
return tmp
end
code[x_, y_, z_, t_, a_, b_] := N[(N[(x + N[(N[(y * z), $MachinePrecision] / t), $MachinePrecision]), $MachinePrecision] / N[(N[(a + 1.0), $MachinePrecision] + N[(N[(y * b), $MachinePrecision] / t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_, z_, t_, a_, b_] := Block[{t$95$1 = N[(N[(z + N[(x * N[(t / y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / b), $MachinePrecision]}, Block[{t$95$2 = N[(N[(x + N[(N[(y * z), $MachinePrecision] / t), $MachinePrecision]), $MachinePrecision] / N[(N[(N[(y * b), $MachinePrecision] / t), $MachinePrecision] + N[(a + 1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(1.0 + N[(a + N[(y / N[(t / b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, -5e+223], N[(N[(y / t), $MachinePrecision] * N[(z / t$95$3), $MachinePrecision] + N[(x / t$95$3), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$2, -5e-298], t$95$2, If[LessEqual[t$95$2, 0.0], t$95$1, If[LessEqual[t$95$2, 1e+301], t$95$2, t$95$1]]]]]]]
\frac{x + \frac{y \cdot z}{t}}{\left(a + 1\right) + \frac{y \cdot b}{t}}
↓
\begin{array}{l}
t_1 := \frac{z + x \cdot \frac{t}{y}}{b}\\
t_2 := \frac{x + \frac{y \cdot z}{t}}{\frac{y \cdot b}{t} + \left(a + 1\right)}\\
t_3 := 1 + \left(a + \frac{y}{\frac{t}{b}}\right)\\
\mathbf{if}\;t_2 \leq -5 \cdot 10^{+223}:\\
\;\;\;\;\mathsf{fma}\left(\frac{y}{t}, \frac{z}{t_3}, \frac{x}{t_3}\right)\\
\mathbf{elif}\;t_2 \leq -5 \cdot 10^{-298}:\\
\;\;\;\;t_2\\
\mathbf{elif}\;t_2 \leq 0:\\
\;\;\;\;t_1\\
\mathbf{elif}\;t_2 \leq 10^{+301}:\\
\;\;\;\;t_2\\
\mathbf{else}:\\
\;\;\;\;t_1\\
\end{array}
