Average Error: 0.2 → 0.2
Time: 10.9s
Precision: binary64
Cost: 13248
\[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \]
\[\frac{1}{\sin B} - \frac{x}{\tan B} \]
(FPCore (B x)
 :precision binary64
 (+ (- (* x (/ 1.0 (tan B)))) (/ 1.0 (sin B))))
(FPCore (B x) :precision binary64 (- (/ 1.0 (sin B)) (/ x (tan B))))
double code(double B, double x) {
	return -(x * (1.0 / tan(B))) + (1.0 / sin(B));
}
double code(double B, double x) {
	return (1.0 / sin(B)) - (x / tan(B));
}
real(8) function code(b, x)
    real(8), intent (in) :: b
    real(8), intent (in) :: x
    code = -(x * (1.0d0 / tan(b))) + (1.0d0 / sin(b))
end function
real(8) function code(b, x)
    real(8), intent (in) :: b
    real(8), intent (in) :: x
    code = (1.0d0 / sin(b)) - (x / tan(b))
end function
public static double code(double B, double x) {
	return -(x * (1.0 / Math.tan(B))) + (1.0 / Math.sin(B));
}
public static double code(double B, double x) {
	return (1.0 / Math.sin(B)) - (x / Math.tan(B));
}
def code(B, x):
	return -(x * (1.0 / math.tan(B))) + (1.0 / math.sin(B))
def code(B, x):
	return (1.0 / math.sin(B)) - (x / math.tan(B))
function code(B, x)
	return Float64(Float64(-Float64(x * Float64(1.0 / tan(B)))) + Float64(1.0 / sin(B)))
end
function code(B, x)
	return Float64(Float64(1.0 / sin(B)) - Float64(x / tan(B)))
end
function tmp = code(B, x)
	tmp = -(x * (1.0 / tan(B))) + (1.0 / sin(B));
end
function tmp = code(B, x)
	tmp = (1.0 / sin(B)) - (x / tan(B));
end
code[B_, x_] := N[((-N[(x * N[(1.0 / N[Tan[B], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]) + N[(1.0 / N[Sin[B], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
code[B_, x_] := N[(N[(1.0 / N[Sin[B], $MachinePrecision]), $MachinePrecision] - N[(x / N[Tan[B], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B}
\frac{1}{\sin B} - \frac{x}{\tan B}

Error

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.2

    \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B} \]
  2. Simplified0.2

    \[\leadsto \color{blue}{\frac{1}{\sin B} - \frac{x}{\tan B}} \]
    Proof
    (-.f64 (/.f64 1 (sin.f64 B)) (/.f64 x (tan.f64 B))): 0 points increase in error, 0 points decrease in error
    (-.f64 (/.f64 1 (sin.f64 B)) (/.f64 (Rewrite<= *-rgt-identity_binary64 (*.f64 x 1)) (tan.f64 B))): 0 points increase in error, 0 points decrease in error
    (-.f64 (/.f64 1 (sin.f64 B)) (Rewrite<= associate-*r/_binary64 (*.f64 x (/.f64 1 (tan.f64 B))))): 24 points increase in error, 5 points decrease in error
    (Rewrite<= unsub-neg_binary64 (+.f64 (/.f64 1 (sin.f64 B)) (neg.f64 (*.f64 x (/.f64 1 (tan.f64 B)))))): 0 points increase in error, 0 points decrease in error
    (Rewrite<= +-commutative_binary64 (+.f64 (neg.f64 (*.f64 x (/.f64 1 (tan.f64 B)))) (/.f64 1 (sin.f64 B)))): 0 points increase in error, 0 points decrease in error
  3. Final simplification0.2

    \[\leadsto \frac{1}{\sin B} - \frac{x}{\tan B} \]

Alternatives

Alternative 1
Error0.2
Cost13248
\[\frac{\frac{1}{\cos B} - x}{\tan B} \]
Alternative 2
Error1.3
Cost6984
\[\begin{array}{l} t_0 := \frac{1 - x}{\tan B}\\ \mathbf{if}\;x \leq -3.399333577260198 \cdot 10^{-15}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;x \leq 12.628945606870845:\\ \;\;\;\;\frac{1}{\sin B}\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \]
Alternative 3
Error1.0
Cost6984
\[\begin{array}{l} \mathbf{if}\;x \leq -6728321324895.881:\\ \;\;\;\;\frac{-x}{\tan B}\\ \mathbf{elif}\;x \leq 0.014842649333539487:\\ \;\;\;\;\frac{1 - x}{\sin B}\\ \mathbf{else}:\\ \;\;\;\;\frac{1 - x}{\tan B}\\ \end{array} \]
Alternative 4
Error0.9
Cost6984
\[\begin{array}{l} \mathbf{if}\;x \leq -0.19540990672173197:\\ \;\;\;\;\frac{1}{B} - \frac{x}{\tan B}\\ \mathbf{elif}\;x \leq 0.014842649333539487:\\ \;\;\;\;\frac{1 - x}{\sin B}\\ \mathbf{else}:\\ \;\;\;\;\frac{1 - x}{\tan B}\\ \end{array} \]
Alternative 5
Error1.9
Cost6920
\[\begin{array}{l} t_0 := \frac{-x}{\tan B}\\ \mathbf{if}\;x \leq -6728321324895.881:\\ \;\;\;\;t_0\\ \mathbf{elif}\;x \leq 12.628945606870845:\\ \;\;\;\;\frac{1}{\sin B}\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \]
Alternative 6
Error18.7
Cost6856
\[\begin{array}{l} t_0 := \frac{1 - x}{B}\\ \mathbf{if}\;x \leq -3.399333577260198 \cdot 10^{-15}:\\ \;\;\;\;\left(1 + t_0\right) + -1\\ \mathbf{elif}\;x \leq 12.628945606870845:\\ \;\;\;\;\frac{1}{\sin B}\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \]
Alternative 7
Error36.1
Cost520
\[\begin{array}{l} t_0 := \frac{-x}{B}\\ \mathbf{if}\;x \leq -6728321324895.881:\\ \;\;\;\;t_0\\ \mathbf{elif}\;x \leq 12.628945606870845:\\ \;\;\;\;\frac{1}{B}\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \]
Alternative 8
Error35.3
Cost320
\[\frac{1 - x}{B} \]
Alternative 9
Error44.7
Cost192
\[\frac{1}{B} \]

Error

Reproduce

herbie shell --seed 2022291 
(FPCore (B x)
  :name "VandenBroeck and Keller, Equation (24)"
  :precision binary64
  (+ (- (* x (/ 1.0 (tan B)))) (/ 1.0 (sin B))))