Average Error: 0.3 → 0.3
Time: 3.7s
Precision: binary64
Cost: 320
\[\left(x \cdot 27\right) \cdot y \]
\[27 \cdot \left(y \cdot x\right) \]
(FPCore (x y) :precision binary64 (* (* x 27.0) y))
(FPCore (x y) :precision binary64 (* 27.0 (* y x)))
double code(double x, double y) {
	return (x * 27.0) * y;
}
double code(double x, double y) {
	return 27.0 * (y * x);
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = (x * 27.0d0) * y
end function
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = 27.0d0 * (y * x)
end function
public static double code(double x, double y) {
	return (x * 27.0) * y;
}
public static double code(double x, double y) {
	return 27.0 * (y * x);
}
def code(x, y):
	return (x * 27.0) * y
def code(x, y):
	return 27.0 * (y * x)
function code(x, y)
	return Float64(Float64(x * 27.0) * y)
end
function code(x, y)
	return Float64(27.0 * Float64(y * x))
end
function tmp = code(x, y)
	tmp = (x * 27.0) * y;
end
function tmp = code(x, y)
	tmp = 27.0 * (y * x);
end
code[x_, y_] := N[(N[(x * 27.0), $MachinePrecision] * y), $MachinePrecision]
code[x_, y_] := N[(27.0 * N[(y * x), $MachinePrecision]), $MachinePrecision]
\left(x \cdot 27\right) \cdot y
27 \cdot \left(y \cdot x\right)

Error

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.3

    \[\left(x \cdot 27\right) \cdot y \]
  2. Taylor expanded in x around 0 0.3

    \[\leadsto \color{blue}{27 \cdot \left(y \cdot x\right)} \]
  3. Final simplification0.3

    \[\leadsto 27 \cdot \left(y \cdot x\right) \]

Reproduce

herbie shell --seed 2022291 
(FPCore (x y)
  :name "Diagrams.Solve.Polynomial:cubForm  from diagrams-solve-0.1, F"
  :precision binary64
  (* (* x 27.0) y))