Average Error: 5.5 → 0.1
Time: 6.0s
Precision: binary64
Cost: 712
\[x \cdot \left(1 + y \cdot y\right) \]
\[\begin{array}{l} t_0 := y \cdot \left(y \cdot x\right)\\ \mathbf{if}\;y \leq -50554366478291380:\\ \;\;\;\;t_0\\ \mathbf{elif}\;y \leq 10^{+63}:\\ \;\;\;\;x + x \cdot \left(y \cdot y\right)\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \]
(FPCore (x y) :precision binary64 (* x (+ 1.0 (* y y))))
(FPCore (x y)
 :precision binary64
 (let* ((t_0 (* y (* y x))))
   (if (<= y -50554366478291380.0)
     t_0
     (if (<= y 1e+63) (+ x (* x (* y y))) t_0))))
double code(double x, double y) {
	return x * (1.0 + (y * y));
}
double code(double x, double y) {
	double t_0 = y * (y * x);
	double tmp;
	if (y <= -50554366478291380.0) {
		tmp = t_0;
	} else if (y <= 1e+63) {
		tmp = x + (x * (y * y));
	} else {
		tmp = t_0;
	}
	return tmp;
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = x * (1.0d0 + (y * y))
end function
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8) :: t_0
    real(8) :: tmp
    t_0 = y * (y * x)
    if (y <= (-50554366478291380.0d0)) then
        tmp = t_0
    else if (y <= 1d+63) then
        tmp = x + (x * (y * y))
    else
        tmp = t_0
    end if
    code = tmp
end function
public static double code(double x, double y) {
	return x * (1.0 + (y * y));
}
public static double code(double x, double y) {
	double t_0 = y * (y * x);
	double tmp;
	if (y <= -50554366478291380.0) {
		tmp = t_0;
	} else if (y <= 1e+63) {
		tmp = x + (x * (y * y));
	} else {
		tmp = t_0;
	}
	return tmp;
}
def code(x, y):
	return x * (1.0 + (y * y))
def code(x, y):
	t_0 = y * (y * x)
	tmp = 0
	if y <= -50554366478291380.0:
		tmp = t_0
	elif y <= 1e+63:
		tmp = x + (x * (y * y))
	else:
		tmp = t_0
	return tmp
function code(x, y)
	return Float64(x * Float64(1.0 + Float64(y * y)))
end
function code(x, y)
	t_0 = Float64(y * Float64(y * x))
	tmp = 0.0
	if (y <= -50554366478291380.0)
		tmp = t_0;
	elseif (y <= 1e+63)
		tmp = Float64(x + Float64(x * Float64(y * y)));
	else
		tmp = t_0;
	end
	return tmp
end
function tmp = code(x, y)
	tmp = x * (1.0 + (y * y));
end
function tmp_2 = code(x, y)
	t_0 = y * (y * x);
	tmp = 0.0;
	if (y <= -50554366478291380.0)
		tmp = t_0;
	elseif (y <= 1e+63)
		tmp = x + (x * (y * y));
	else
		tmp = t_0;
	end
	tmp_2 = tmp;
end
code[x_, y_] := N[(x * N[(1.0 + N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
code[x_, y_] := Block[{t$95$0 = N[(y * N[(y * x), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[y, -50554366478291380.0], t$95$0, If[LessEqual[y, 1e+63], N[(x + N[(x * N[(y * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], t$95$0]]]
x \cdot \left(1 + y \cdot y\right)
\begin{array}{l}
t_0 := y \cdot \left(y \cdot x\right)\\
\mathbf{if}\;y \leq -50554366478291380:\\
\;\;\;\;t_0\\

\mathbf{elif}\;y \leq 10^{+63}:\\
\;\;\;\;x + x \cdot \left(y \cdot y\right)\\

\mathbf{else}:\\
\;\;\;\;t_0\\


\end{array}

Error

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original5.5
Target0.1
Herbie0.1
\[x + \left(x \cdot y\right) \cdot y \]

Derivation

  1. Split input into 2 regimes
  2. if y < -50554366478291376 or 1.00000000000000006e63 < y

    1. Initial program 21.6

      \[x \cdot \left(1 + y \cdot y\right) \]
    2. Taylor expanded in y around inf 21.6

      \[\leadsto \color{blue}{{y}^{2} \cdot x} \]
    3. Simplified0.3

      \[\leadsto \color{blue}{y \cdot \left(y \cdot x\right)} \]
      Proof
      (*.f64 y (*.f64 y x)): 0 points increase in error, 0 points decrease in error
      (Rewrite<= associate-*l*_binary64 (*.f64 (*.f64 y y) x)): 72 points increase in error, 28 points decrease in error
      (*.f64 (Rewrite<= unpow2_binary64 (pow.f64 y 2)) x): 0 points increase in error, 0 points decrease in error

    if -50554366478291376 < y < 1.00000000000000006e63

    1. Initial program 0.0

      \[x \cdot \left(1 + y \cdot y\right) \]
    2. Applied egg-rr0.0

      \[\leadsto \color{blue}{x \cdot \left(y \cdot y\right) + x} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification0.1

    \[\leadsto \begin{array}{l} \mathbf{if}\;y \leq -50554366478291380:\\ \;\;\;\;y \cdot \left(y \cdot x\right)\\ \mathbf{elif}\;y \leq 10^{+63}:\\ \;\;\;\;x + x \cdot \left(y \cdot y\right)\\ \mathbf{else}:\\ \;\;\;\;y \cdot \left(y \cdot x\right)\\ \end{array} \]

Alternatives

Alternative 1
Error6.4
Cost580
\[\begin{array}{l} \mathbf{if}\;y \cdot y \leq 0.004941075491279822:\\ \;\;\;\;x\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(y \cdot y\right)\\ \end{array} \]
Alternative 2
Error1.0
Cost580
\[\begin{array}{l} \mathbf{if}\;y \cdot y \leq 0.005:\\ \;\;\;\;x\\ \mathbf{else}:\\ \;\;\;\;y \cdot \left(y \cdot x\right)\\ \end{array} \]
Alternative 3
Error20.7
Cost64
\[x \]

Error

Reproduce

herbie shell --seed 2022291 
(FPCore (x y)
  :name "Numeric.Integration.TanhSinh:everywhere from integration-0.2.1"
  :precision binary64

  :herbie-target
  (+ x (* (* x y) y))

  (* x (+ 1.0 (* y y))))