Toniolo and Linder, Equation (10-)

Average Error: 47.8 → 1.7

Time: 25.3s

Precision: binary64

Math

\[\frac{2}{\left(\left(\frac{{t}^{3}}{\ell \cdot \ell} \cdot \sin k\right) \cdot \tan k\right) \cdot \left(\left(1 + {\left(\frac{k}{t}\right)}^{2}\right) - 1\right)} \]

↓

\[\begin{array}{l} t_1 := 2 \cdot \left(\frac{\ell}{k} \cdot \frac{\frac{\ell \cdot \left(\cos k \cdot {\sin k}^{-2}\right)}{k}}{t}\right)\\ \mathbf{if}\;k \leq -1.22 \cdot 10^{-154}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;k \leq 2.6 \cdot 10^{-124}:\\ \;\;\;\;2 \cdot \frac{\frac{\cos k \cdot \frac{{\left(\frac{\ell}{k}\right)}^{2}}{t}}{\sin k}}{\sin k}\\ \mathbf{else}:\\ \;\;\;\;t_1\\ \end{array} \]

FPCore

(FPCore (t l k)
 :precision binary64
 (/
  2.0
  (*
   (* (* (/ (pow t 3.0) (* l l)) (sin k)) (tan k))
   (- (+ 1.0 (pow (/ k t) 2.0)) 1.0))))

↓

(FPCore (t l k)
 :precision binary64
 (let* ((t_1
         (* 2.0 (* (/ l k) (/ (/ (* l (* (cos k) (pow (sin k) -2.0))) k) t)))))
   (if (<= k -1.22e-154)
     t_1
     (if (<= k 2.6e-124)
       (* 2.0 (/ (/ (* (cos k) (/ (pow (/ l k) 2.0) t)) (sin k)) (sin k)))
       t_1))))

C

double code(double t, double l, double k) {
	return 2.0 / ((((pow(t, 3.0) / (l * l)) * sin(k)) * tan(k)) * ((1.0 + pow((k / t), 2.0)) - 1.0));
}

↓

double code(double t, double l, double k) {
	double t_1 = 2.0 * ((l / k) * (((l * (cos(k) * pow(sin(k), -2.0))) / k) / t));
	double tmp;
	if (k <= -1.22e-154) {
		tmp = t_1;
	} else if (k <= 2.6e-124) {
		tmp = 2.0 * (((cos(k) * (pow((l / k), 2.0) / t)) / sin(k)) / sin(k));
	} else {
		tmp = t_1;
	}
	return tmp;
}

Fortran

real(8) function code(t, l, k)
    real(8), intent (in) :: t
    real(8), intent (in) :: l
    real(8), intent (in) :: k
    code = 2.0d0 / (((((t ** 3.0d0) / (l * l)) * sin(k)) * tan(k)) * ((1.0d0 + ((k / t) ** 2.0d0)) - 1.0d0))
end function

↓

real(8) function code(t, l, k)
    real(8), intent (in) :: t
    real(8), intent (in) :: l
    real(8), intent (in) :: k
    real(8) :: t_1
    real(8) :: tmp
    t_1 = 2.0d0 * ((l / k) * (((l * (cos(k) * (sin(k) ** (-2.0d0)))) / k) / t))
    if (k <= (-1.22d-154)) then
        tmp = t_1
    else if (k <= 2.6d-124) then
        tmp = 2.0d0 * (((cos(k) * (((l / k) ** 2.0d0) / t)) / sin(k)) / sin(k))
    else
        tmp = t_1
    end if
    code = tmp
end function

Java

public static double code(double t, double l, double k) {
	return 2.0 / ((((Math.pow(t, 3.0) / (l * l)) * Math.sin(k)) * Math.tan(k)) * ((1.0 + Math.pow((k / t), 2.0)) - 1.0));
}

↓

public static double code(double t, double l, double k) {
	double t_1 = 2.0 * ((l / k) * (((l * (Math.cos(k) * Math.pow(Math.sin(k), -2.0))) / k) / t));
	double tmp;
	if (k <= -1.22e-154) {
		tmp = t_1;
	} else if (k <= 2.6e-124) {
		tmp = 2.0 * (((Math.cos(k) * (Math.pow((l / k), 2.0) / t)) / Math.sin(k)) / Math.sin(k));
	} else {
		tmp = t_1;
	}
	return tmp;
}

Python

def code(t, l, k):
	return 2.0 / ((((math.pow(t, 3.0) / (l * l)) * math.sin(k)) * math.tan(k)) * ((1.0 + math.pow((k / t), 2.0)) - 1.0))

↓

def code(t, l, k):
	t_1 = 2.0 * ((l / k) * (((l * (math.cos(k) * math.pow(math.sin(k), -2.0))) / k) / t))
	tmp = 0
	if k <= -1.22e-154:
		tmp = t_1
	elif k <= 2.6e-124:
		tmp = 2.0 * (((math.cos(k) * (math.pow((l / k), 2.0) / t)) / math.sin(k)) / math.sin(k))
	else:
		tmp = t_1
	return tmp

Julia

function code(t, l, k)
	return Float64(2.0 / Float64(Float64(Float64(Float64((t ^ 3.0) / Float64(l * l)) * sin(k)) * tan(k)) * Float64(Float64(1.0 + (Float64(k / t) ^ 2.0)) - 1.0)))
end

↓

function code(t, l, k)
	t_1 = Float64(2.0 * Float64(Float64(l / k) * Float64(Float64(Float64(l * Float64(cos(k) * (sin(k) ^ -2.0))) / k) / t)))
	tmp = 0.0
	if (k <= -1.22e-154)
		tmp = t_1;
	elseif (k <= 2.6e-124)
		tmp = Float64(2.0 * Float64(Float64(Float64(cos(k) * Float64((Float64(l / k) ^ 2.0) / t)) / sin(k)) / sin(k)));
	else
		tmp = t_1;
	end
	return tmp
end

MATLAB

function tmp = code(t, l, k)
	tmp = 2.0 / (((((t ^ 3.0) / (l * l)) * sin(k)) * tan(k)) * ((1.0 + ((k / t) ^ 2.0)) - 1.0));
end

↓

function tmp_2 = code(t, l, k)
	t_1 = 2.0 * ((l / k) * (((l * (cos(k) * (sin(k) ^ -2.0))) / k) / t));
	tmp = 0.0;
	if (k <= -1.22e-154)
		tmp = t_1;
	elseif (k <= 2.6e-124)
		tmp = 2.0 * (((cos(k) * (((l / k) ^ 2.0) / t)) / sin(k)) / sin(k));
	else
		tmp = t_1;
	end
	tmp_2 = tmp;
end

Wolfram

code[t_, l_, k_] := N[(2.0 / N[(N[(N[(N[(N[Power[t, 3.0], $MachinePrecision] / N[(l * l), $MachinePrecision]), $MachinePrecision] * N[Sin[k], $MachinePrecision]), $MachinePrecision] * N[Tan[k], $MachinePrecision]), $MachinePrecision] * N[(N[(1.0 + N[Power[N[(k / t), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] - 1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]

↓

code[t_, l_, k_] := Block[{t$95$1 = N[(2.0 * N[(N[(l / k), $MachinePrecision] * N[(N[(N[(l * N[(N[Cos[k], $MachinePrecision] * N[Power[N[Sin[k], $MachinePrecision], -2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / k), $MachinePrecision] / t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[k, -1.22e-154], t$95$1, If[LessEqual[k, 2.6e-124], N[(2.0 * N[(N[(N[(N[Cos[k], $MachinePrecision] * N[(N[Power[N[(l / k), $MachinePrecision], 2.0], $MachinePrecision] / t), $MachinePrecision]), $MachinePrecision] / N[Sin[k], $MachinePrecision]), $MachinePrecision] / N[Sin[k], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], t$95$1]]]

Error

Bits error versus t

Bits error versus l

Bits error versus k

Derivation

1. Split input into 2 regimes

2. if k < -1.22000000000000005e-154 or 2.6e-124 < k

   1. Initial program 47.0

      \[\frac{2}{\left(\left(\frac{{t}^{3}}{\ell \cdot \ell} \cdot \sin k\right) \cdot \tan k\right) \cdot \left(\left(1 + {\left(\frac{k}{t}\right)}^{2}\right) - 1\right)} \]

   2. Simplified 38.6

      \[\leadsto \color{blue}{\frac{2}{\left({t}^{3} \cdot \sin k\right) \cdot \left(\tan k \cdot {\left(\frac{k}{t}\right)}^{2}\right)} \cdot \left(\ell \cdot \ell\right)} \]

   3. Taylor expanded in t around 0 21.0

      \[\leadsto \color{blue}{2 \cdot \frac{\cos k \cdot {\ell}^{2}}{{k}^{2} \cdot \left(t \cdot {\sin k}^{2}\right)}} \]

   4. Simplified 5.6

      \[\leadsto \color{blue}{2 \cdot \left(\left(\frac{\ell}{k} \cdot \frac{\ell}{k \cdot t}\right) \cdot \frac{\cos k}{{\sin k}^{2}}\right)} \]

   5. Applied egg-rr 4.7

      \[\leadsto 2 \cdot \color{blue}{\frac{\ell \cdot \left(\frac{\frac{\ell}{k}}{t} \cdot \left(\cos k \cdot {\sin k}^{-2}\right)\right)}{k}} \]

   6. Applied egg-rr 4.7

      \[\leadsto 2 \cdot \color{blue}{\left(\frac{\ell}{k} \cdot \left(\frac{\ell}{k \cdot t} \cdot \left(\cos k \cdot {\sin k}^{-2}\right)\right)\right)} \]

   7. Applied egg-rr 1.1

      \[\leadsto 2 \cdot \left(\frac{\ell}{k} \cdot \color{blue}{\frac{\frac{\ell \cdot \left(\cos k \cdot {\sin k}^{-2}\right)}{k}}{t}}\right) \]

   if -1.22000000000000005e-154 < k < 2.6e-124

   1. Initial program 64.0

      \[\frac{2}{\left(\left(\frac{{t}^{3}}{\ell \cdot \ell} \cdot \sin k\right) \cdot \tan k\right) \cdot \left(\left(1 + {\left(\frac{k}{t}\right)}^{2}\right) - 1\right)} \]

   2. Simplified 64.0

      \[\leadsto \color{blue}{\frac{2}{\left({t}^{3} \cdot \sin k\right) \cdot \left(\tan k \cdot {\left(\frac{k}{t}\right)}^{2}\right)} \cdot \left(\ell \cdot \ell\right)} \]

   3. Taylor expanded in t around 0 62.0

      \[\leadsto \color{blue}{2 \cdot \frac{\cos k \cdot {\ell}^{2}}{{k}^{2} \cdot \left(t \cdot {\sin k}^{2}\right)}} \]

   4. Simplified 52.2

      \[\leadsto \color{blue}{2 \cdot \left(\left(\frac{\ell}{k} \cdot \frac{\ell}{k \cdot t}\right) \cdot \frac{\cos k}{{\sin k}^{2}}\right)} \]

   5. Applied egg-rr 14.7

      \[\leadsto 2 \cdot \color{blue}{\frac{\frac{\frac{{\left(\frac{\ell}{k}\right)}^{2}}{t} \cdot \cos k}{\sin k}}{\sin k}} \]
3. Recombined 2 regimes into one program.

4. Final simplification 1.7

   \[\leadsto \begin{array}{l} \mathbf{if}\;k \leq -1.22 \cdot 10^{-154}:\\ \;\;\;\;2 \cdot \left(\frac{\ell}{k} \cdot \frac{\frac{\ell \cdot \left(\cos k \cdot {\sin k}^{-2}\right)}{k}}{t}\right)\\ \mathbf{elif}\;k \leq 2.6 \cdot 10^{-124}:\\ \;\;\;\;2 \cdot \frac{\frac{\cos k \cdot \frac{{\left(\frac{\ell}{k}\right)}^{2}}{t}}{\sin k}}{\sin k}\\ \mathbf{else}:\\ \;\;\;\;2 \cdot \left(\frac{\ell}{k} \cdot \frac{\frac{\ell \cdot \left(\cos k \cdot {\sin k}^{-2}\right)}{k}}{t}\right)\\ \end{array} \]

Reproduce

herbie shell --seed 2022162 
(FPCore (t l k)
  :name "Toniolo and Linder, Equation (10-)"
  :precision binary64
  (/ 2.0 (* (* (* (/ (pow t 3.0) (* l l)) (sin k)) (tan k)) (- (+ 1.0 (pow (/ k t) 2.0)) 1.0))))