Average Error: 9.7 → 0.2
Time: 6.2s
Precision: binary64
\[x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y} \]
↓
\[\begin{array}{l} \mathbf{if}\;y \leq -1.295847362417144 \lor \neg \left(y \leq 0.0005143489626409994\right):\\ \;\;\;\;x + \frac{1}{y \cdot e^{z}}\\ \mathbf{else}:\\ \;\;\;\;x + \frac{1}{y}\\ \end{array} \]
x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y}
↓
\begin{array}{l}
\mathbf{if}\;y \leq -1.295847362417144 \lor \neg \left(y \leq 0.0005143489626409994\right):\\
\;\;\;\;x + \frac{1}{y \cdot e^{z}}\\

\mathbf{else}:\\
\;\;\;\;x + \frac{1}{y}\\


\end{array}

(FPCore (x y z)
 :precision binary64
 (+ x (/ (exp (* y (log (/ y (+ z y))))) y)))
↓
(FPCore (x y z)
 :precision binary64
 (if (or (<= y -1.295847362417144) (not (<= y 0.0005143489626409994)))
   (+ x (/ 1.0 (* y (exp z))))
   (+ x (/ 1.0 y))))
double code(double x, double y, double z) {
	return x + (exp(y * log(y / (z + y))) / y);
}
↓
double code(double x, double y, double z) {
	double tmp;
	if ((y <= -1.295847362417144) || !(y <= 0.0005143489626409994)) {
		tmp = x + (1.0 / (y * exp(z)));
	} else {
		tmp = x + (1.0 / y);
	}
	return tmp;
}

Error

Bits error versus x

Bits error versus y

Bits error versus z

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original9.7
Target5.5
Herbie0.2
\[\begin{array}{l} \mathbf{if}\;\frac{y}{z + y} < 7.11541576 \cdot 10^{-315}:\\ \;\;\;\;x + \frac{e^{\frac{-1}{z}}}{y}\\ \mathbf{else}:\\ \;\;\;\;x + \frac{e^{\log \left({\left(\frac{y}{y + z}\right)}^{y}\right)}}{y}\\ \end{array} \]

Derivation

  1. Split input into 2 regimes

  2. if y < -1.295847362417144 or 5.143489626409994e-4 < y

    1. Initial program 9.3

      \[x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y} \]

    2. Simplified9.3

      \[\leadsto \color{blue}{x + \frac{{\left(\frac{y}{y + z}\right)}^{y}}{y}} \]

    3. Taylor expanded in y around inf 0.1

      \[\leadsto x + \frac{\color{blue}{e^{-z}}}{y} \]

    4. Applied clear-num_binary640.1

      \[\leadsto x + \color{blue}{\frac{1}{\frac{y}{e^{-z}}}} \]

    5. Simplified0.1

      \[\leadsto x + \frac{1}{\color{blue}{y \cdot e^{z}}} \]

    if -1.295847362417144 < y < 5.143489626409994e-4

    1. Initial program 10.2

      \[x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y} \]

    2. Simplified10.2

      \[\leadsto \color{blue}{x + \frac{{\left(\frac{y}{y + z}\right)}^{y}}{y}} \]

    3. Taylor expanded in y around 0 0.3

      \[\leadsto x + \frac{\color{blue}{1}}{y} \]
  3. Recombined 2 regimes into one program.

  4. Final simplification0.2

    \[\leadsto \begin{array}{l} \mathbf{if}\;y \leq -1.295847362417144 \lor \neg \left(y \leq 0.0005143489626409994\right):\\ \;\;\;\;x + \frac{1}{y \cdot e^{z}}\\ \mathbf{else}:\\ \;\;\;\;x + \frac{1}{y}\\ \end{array} \]

Reproduce

herbie shell --seed 2022068 
(FPCore (x y z)
  :name "Numeric.SpecFunctions:invIncompleteBetaWorker from math-functions-0.1.5.2, G"
  :precision binary64

  :herbie-target
  (if (< (/ y (+ z y)) 7.11541576e-315) (+ x (/ (exp (/ -1.0 z)) y)) (+ x (/ (exp (log (pow (/ y (+ y z)) y))) y)))

  (+ x (/ (exp (* y (log (/ y (+ z y))))) y)))