Average Error: 14.4 → 0.0
Time: 757.0ms
Precision: binary64
\[\frac{x}{x \cdot x + 1} \]
\[\begin{array}{l} \mathbf{if}\;x \leq -7.882522709010398 \cdot 10^{+38} \lor \neg \left(x \leq 237841878.36433893\right):\\ \;\;\;\;\frac{1}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{1 + x \cdot x}\\ \end{array} \]
\frac{x}{x \cdot x + 1}
\begin{array}{l}
\mathbf{if}\;x \leq -7.882522709010398 \cdot 10^{+38} \lor \neg \left(x \leq 237841878.36433893\right):\\
\;\;\;\;\frac{1}{x}\\

\mathbf{else}:\\
\;\;\;\;\frac{x}{1 + x \cdot x}\\


\end{array}
(FPCore (x) :precision binary64 (/ x (+ (* x x) 1.0)))
(FPCore (x)
 :precision binary64
 (if (or (<= x -7.882522709010398e+38) (not (<= x 237841878.36433893)))
   (/ 1.0 x)
   (/ x (+ 1.0 (* x x)))))
double code(double x) {
	return x / ((x * x) + 1.0);
}
double code(double x) {
	double tmp;
	if ((x <= -7.882522709010398e+38) || !(x <= 237841878.36433893)) {
		tmp = 1.0 / x;
	} else {
		tmp = x / (1.0 + (x * x));
	}
	return tmp;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original14.4
Target0.1
Herbie0.0
\[\frac{1}{x + \frac{1}{x}} \]

Derivation

  1. Split input into 2 regimes
  2. if x < -7.8825227090103984e38 or 237841878.36433893 < x

    1. Initial program 31.8

      \[\frac{x}{x \cdot x + 1} \]
    2. Simplified31.8

      \[\leadsto \color{blue}{\frac{x}{\mathsf{fma}\left(x, x, 1\right)}} \]
    3. Taylor expanded in x around inf 0

      \[\leadsto \color{blue}{\frac{1}{x}} \]

    if -7.8825227090103984e38 < x < 237841878.36433893

    1. Initial program 0.0

      \[\frac{x}{x \cdot x + 1} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification0.0

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -7.882522709010398 \cdot 10^{+38} \lor \neg \left(x \leq 237841878.36433893\right):\\ \;\;\;\;\frac{1}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{x}{1 + x \cdot x}\\ \end{array} \]

Reproduce

herbie shell --seed 2021332 
(FPCore (x)
  :name "x / (x^2 + 1)"
  :precision binary64

  :herbie-target
  (/ 1.0 (+ x (/ 1.0 x)))

  (/ x (+ (* x x) 1.0)))