Average Error: 13.9 → 0.4
Time: 28.9s
Precision: binary64
\[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{F}{\sin B} \cdot {\left(\left(F \cdot F + 2\right) + 2 \cdot x\right)}^{\left(-\frac{1}{2}\right)}\]
↓
\[\begin{array}{l} \mathbf{if}\;F \leq -16872814.748516325:\\ \;\;\;\;\frac{-1}{\sin B} - \frac{x}{\tan B}\\ \mathbf{elif}\;F \leq 0.003263911912299716:\\ \;\;\;\;\frac{F}{\sin B} \cdot {\left({\left(x \cdot 2 + \left(2 + F \cdot F\right)\right)}^{\left(\sqrt[3]{-0.5} \cdot \sqrt[3]{-0.5}\right)}\right)}^{\left(\sqrt[3]{-0.5}\right)} - \frac{x}{\tan B}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{\sin B} - \frac{x}{\tan B}\\ \end{array}\]
\left(-x \cdot \frac{1}{\tan B}\right) + \frac{F}{\sin B} \cdot {\left(\left(F \cdot F + 2\right) + 2 \cdot x\right)}^{\left(-\frac{1}{2}\right)}
↓
\begin{array}{l}
\mathbf{if}\;F \leq -16872814.748516325:\\
\;\;\;\;\frac{-1}{\sin B} - \frac{x}{\tan B}\\

\mathbf{elif}\;F \leq 0.003263911912299716:\\
\;\;\;\;\frac{F}{\sin B} \cdot {\left({\left(x \cdot 2 + \left(2 + F \cdot F\right)\right)}^{\left(\sqrt[3]{-0.5} \cdot \sqrt[3]{-0.5}\right)}\right)}^{\left(\sqrt[3]{-0.5}\right)} - \frac{x}{\tan B}\\

\mathbf{else}:\\
\;\;\;\;\frac{1}{\sin B} - \frac{x}{\tan B}\\

\end{array}
(FPCore (F B x)
 :precision binary64
 (+
  (- (* x (/ 1.0 (tan B))))
  (* (/ F (sin B)) (pow (+ (+ (* F F) 2.0) (* 2.0 x)) (- (/ 1.0 2.0))))))
↓
(FPCore (F B x)
 :precision binary64
 (if (<= F -16872814.748516325)
   (- (/ -1.0 (sin B)) (/ x (tan B)))
   (if (<= F 0.003263911912299716)
     (-
      (*
       (/ F (sin B))
       (pow
        (pow (+ (* x 2.0) (+ 2.0 (* F F))) (* (cbrt -0.5) (cbrt -0.5)))
        (cbrt -0.5)))
      (/ x (tan B)))
     (- (/ 1.0 (sin B)) (/ x (tan B))))))
double code(double F, double B, double x) {
	return -(x * (1.0 / tan(B))) + ((F / sin(B)) * pow((((F * F) + 2.0) + (2.0 * x)), -(1.0 / 2.0)));
}
↓
double code(double F, double B, double x) {
	double tmp;
	if (F <= -16872814.748516325) {
		tmp = (-1.0 / sin(B)) - (x / tan(B));
	} else if (F <= 0.003263911912299716) {
		tmp = ((F / sin(B)) * pow(pow(((x * 2.0) + (2.0 + (F * F))), (cbrt(-0.5) * cbrt(-0.5))), cbrt(-0.5))) - (x / tan(B));
	} else {
		tmp = (1.0 / sin(B)) - (x / tan(B));
	}
	return tmp;
}

Error

Bits error versus F

Bits error versus B

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Split input into 3 regimes

  2. if F < -16872814.7485163249

    1. Initial program 24.7

      \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{F}{\sin B} \cdot {\left(\left(F \cdot F + 2\right) + 2 \cdot x\right)}^{\left(-\frac{1}{2}\right)}\]

    2. Simplified24.6

      \[\leadsto \color{blue}{\frac{F}{\sin B} \cdot {\left(\left(F \cdot F + 2\right) + x \cdot 2\right)}^{-0.5} - \frac{x}{\tan B}}\]

    3. Taylor expanded around -inf 0.2

      \[\leadsto \color{blue}{\frac{-1}{\sin B}} - \frac{x}{\tan B}\]

    if -16872814.7485163249 < F < 0.00326391191229971579

    1. Initial program 0.4

      \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{F}{\sin B} \cdot {\left(\left(F \cdot F + 2\right) + 2 \cdot x\right)}^{\left(-\frac{1}{2}\right)}\]

    2. Simplified0.3

      \[\leadsto \color{blue}{\frac{F}{\sin B} \cdot {\left(\left(F \cdot F + 2\right) + x \cdot 2\right)}^{-0.5} - \frac{x}{\tan B}}\]
    3. Using strategy rm

    4. Applied add-cube-cbrt_binary640.3

      \[\leadsto \frac{F}{\sin B} \cdot {\left(\left(F \cdot F + 2\right) + x \cdot 2\right)}^{\color{blue}{\left(\left(\sqrt[3]{-0.5} \cdot \sqrt[3]{-0.5}\right) \cdot \sqrt[3]{-0.5}\right)}} - \frac{x}{\tan B}\]

    5. Applied pow-unpow_binary640.3

      \[\leadsto \frac{F}{\sin B} \cdot \color{blue}{{\left({\left(\left(F \cdot F + 2\right) + x \cdot 2\right)}^{\left(\sqrt[3]{-0.5} \cdot \sqrt[3]{-0.5}\right)}\right)}^{\left(\sqrt[3]{-0.5}\right)}} - \frac{x}{\tan B}\]

    6. Simplified0.3

      \[\leadsto \frac{F}{\sin B} \cdot {\color{blue}{\left({\left(2 \cdot x + \left(2 + F \cdot F\right)\right)}^{\left(\sqrt[3]{-0.5} \cdot \sqrt[3]{-0.5}\right)}\right)}}^{\left(\sqrt[3]{-0.5}\right)} - \frac{x}{\tan B}\]

    if 0.00326391191229971579 < F

    1. Initial program 25.1

      \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{F}{\sin B} \cdot {\left(\left(F \cdot F + 2\right) + 2 \cdot x\right)}^{\left(-\frac{1}{2}\right)}\]

    2. Simplified25.0

      \[\leadsto \color{blue}{\frac{F}{\sin B} \cdot {\left(\left(F \cdot F + 2\right) + x \cdot 2\right)}^{-0.5} - \frac{x}{\tan B}}\]

    3. Taylor expanded around inf 0.8

      \[\leadsto \color{blue}{\frac{1}{\sin B}} - \frac{x}{\tan B}\]
  3. Recombined 3 regimes into one program.

  4. Final simplification0.4

    \[\leadsto \begin{array}{l} \mathbf{if}\;F \leq -16872814.748516325:\\ \;\;\;\;\frac{-1}{\sin B} - \frac{x}{\tan B}\\ \mathbf{elif}\;F \leq 0.003263911912299716:\\ \;\;\;\;\frac{F}{\sin B} \cdot {\left({\left(x \cdot 2 + \left(2 + F \cdot F\right)\right)}^{\left(\sqrt[3]{-0.5} \cdot \sqrt[3]{-0.5}\right)}\right)}^{\left(\sqrt[3]{-0.5}\right)} - \frac{x}{\tan B}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{\sin B} - \frac{x}{\tan B}\\ \end{array}\]

Reproduce

herbie shell --seed 2021023 
(FPCore (F B x)
  :name "VandenBroeck and Keller, Equation (23)"
  :precision binary64
  (+ (- (* x (/ 1.0 (tan B)))) (* (/ F (sin B)) (pow (+ (+ (* F F) 2.0) (* 2.0 x)) (- (/ 1.0 2.0))))))