Average Error: 11.6 → 2.4
Time: 5.8s
Precision: binary64
[a1 a2]: =sort([a1 a2])
[b1 b2]: =sort([b1 b2])
\[\frac{a1 \cdot a2}{b1 \cdot b2}\]
↓
\[\begin{array}{l} \mathbf{if}\;\frac{a1 \cdot a2}{b1 \cdot b2} \leq -1.525827891617212 \cdot 10^{+281}:\\ \;\;\;\;\frac{1}{\sqrt[3]{b1} \cdot \sqrt[3]{b1}} \cdot \left(\frac{a2}{b2} \cdot \frac{a1}{\sqrt[3]{b1}}\right)\\ \mathbf{elif}\;\frac{a1 \cdot a2}{b1 \cdot b2} \leq -2.7274658798653095 \cdot 10^{-301}:\\ \;\;\;\;\frac{a1 \cdot a2}{b1 \cdot b2}\\ \mathbf{elif}\;\frac{a1 \cdot a2}{b1 \cdot b2} \leq 0:\\ \;\;\;\;\frac{\sqrt[3]{a1} \cdot \sqrt[3]{a1}}{\sqrt[3]{b1} \cdot \sqrt[3]{b1}} \cdot \left(\frac{a2}{b2} \cdot \frac{\sqrt[3]{a1}}{\sqrt[3]{b1}}\right)\\ \mathbf{elif}\;\frac{a1 \cdot a2}{b1 \cdot b2} \leq 1.1524808445941616 \cdot 10^{+274}:\\ \;\;\;\;\frac{a1 \cdot a2}{b1 \cdot b2}\\ \mathbf{else}:\\ \;\;\;\;\frac{a2}{b2} \cdot \frac{a1}{b1}\\ \end{array}\]
\frac{a1 \cdot a2}{b1 \cdot b2}
↓
\begin{array}{l}
\mathbf{if}\;\frac{a1 \cdot a2}{b1 \cdot b2} \leq -1.525827891617212 \cdot 10^{+281}:\\
\;\;\;\;\frac{1}{\sqrt[3]{b1} \cdot \sqrt[3]{b1}} \cdot \left(\frac{a2}{b2} \cdot \frac{a1}{\sqrt[3]{b1}}\right)\\

\mathbf{elif}\;\frac{a1 \cdot a2}{b1 \cdot b2} \leq -2.7274658798653095 \cdot 10^{-301}:\\
\;\;\;\;\frac{a1 \cdot a2}{b1 \cdot b2}\\

\mathbf{elif}\;\frac{a1 \cdot a2}{b1 \cdot b2} \leq 0:\\
\;\;\;\;\frac{\sqrt[3]{a1} \cdot \sqrt[3]{a1}}{\sqrt[3]{b1} \cdot \sqrt[3]{b1}} \cdot \left(\frac{a2}{b2} \cdot \frac{\sqrt[3]{a1}}{\sqrt[3]{b1}}\right)\\

\mathbf{elif}\;\frac{a1 \cdot a2}{b1 \cdot b2} \leq 1.1524808445941616 \cdot 10^{+274}:\\
\;\;\;\;\frac{a1 \cdot a2}{b1 \cdot b2}\\

\mathbf{else}:\\
\;\;\;\;\frac{a2}{b2} \cdot \frac{a1}{b1}\\

\end{array}
(FPCore (a1 a2 b1 b2) :precision binary64 (/ (* a1 a2) (* b1 b2)))
↓
(FPCore (a1 a2 b1 b2)
 :precision binary64
 (if (<= (/ (* a1 a2) (* b1 b2)) -1.525827891617212e+281)
   (* (/ 1.0 (* (cbrt b1) (cbrt b1))) (* (/ a2 b2) (/ a1 (cbrt b1))))
   (if (<= (/ (* a1 a2) (* b1 b2)) -2.7274658798653095e-301)
     (/ (* a1 a2) (* b1 b2))
     (if (<= (/ (* a1 a2) (* b1 b2)) 0.0)
       (*
        (/ (* (cbrt a1) (cbrt a1)) (* (cbrt b1) (cbrt b1)))
        (* (/ a2 b2) (/ (cbrt a1) (cbrt b1))))
       (if (<= (/ (* a1 a2) (* b1 b2)) 1.1524808445941616e+274)
         (/ (* a1 a2) (* b1 b2))
         (* (/ a2 b2) (/ a1 b1)))))))
double code(double a1, double a2, double b1, double b2) {
	return (a1 * a2) / (b1 * b2);
}
↓
double code(double a1, double a2, double b1, double b2) {
	double tmp;
	if (((a1 * a2) / (b1 * b2)) <= -1.525827891617212e+281) {
		tmp = (1.0 / (cbrt(b1) * cbrt(b1))) * ((a2 / b2) * (a1 / cbrt(b1)));
	} else if (((a1 * a2) / (b1 * b2)) <= -2.7274658798653095e-301) {
		tmp = (a1 * a2) / (b1 * b2);
	} else if (((a1 * a2) / (b1 * b2)) <= 0.0) {
		tmp = ((cbrt(a1) * cbrt(a1)) / (cbrt(b1) * cbrt(b1))) * ((a2 / b2) * (cbrt(a1) / cbrt(b1)));
	} else if (((a1 * a2) / (b1 * b2)) <= 1.1524808445941616e+274) {
		tmp = (a1 * a2) / (b1 * b2);
	} else {
		tmp = (a2 / b2) * (a1 / b1);
	}
	return tmp;
}

Error

Bits error versus a1

Bits error versus a2

Bits error versus b1

Bits error versus b2

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original11.6
Target11.5
Herbie2.4
\[\frac{a1}{b1} \cdot \frac{a2}{b2}\]

Derivation

  1. Split input into 4 regimes

  2. if (/.f64 (*.f64 a1 a2) (*.f64 b1 b2)) < -1.52582789161721215e281

    1. Initial program 52.0

      \[\frac{a1 \cdot a2}{b1 \cdot b2}\]
    2. Using strategy rm

    3. Applied times-frac_binary64_281214.4

      \[\leadsto \color{blue}{\frac{a1}{b1} \cdot \frac{a2}{b2}}\]
    4. Using strategy rm

    5. Applied add-cube-cbrt_binary64_284115.2

      \[\leadsto \frac{a1}{\color{blue}{\left(\sqrt[3]{b1} \cdot \sqrt[3]{b1}\right) \cdot \sqrt[3]{b1}}} \cdot \frac{a2}{b2}\]

    6. Applied *-un-lft-identity_binary64_280615.2

      \[\leadsto \frac{\color{blue}{1 \cdot a1}}{\left(\sqrt[3]{b1} \cdot \sqrt[3]{b1}\right) \cdot \sqrt[3]{b1}} \cdot \frac{a2}{b2}\]

    7. Applied times-frac_binary64_281215.2

      \[\leadsto \color{blue}{\left(\frac{1}{\sqrt[3]{b1} \cdot \sqrt[3]{b1}} \cdot \frac{a1}{\sqrt[3]{b1}}\right)} \cdot \frac{a2}{b2}\]

    8. Applied associate-*l*_binary64_274716.9

      \[\leadsto \color{blue}{\frac{1}{\sqrt[3]{b1} \cdot \sqrt[3]{b1}} \cdot \left(\frac{a1}{\sqrt[3]{b1}} \cdot \frac{a2}{b2}\right)}\]

    9. Simplified16.9

      \[\leadsto \frac{1}{\sqrt[3]{b1} \cdot \sqrt[3]{b1}} \cdot \color{blue}{\left(\frac{a2}{b2} \cdot \frac{a1}{\sqrt[3]{b1}}\right)}\]

    if -1.52582789161721215e281 < (/.f64 (*.f64 a1 a2) (*.f64 b1 b2)) < -2.7274658798653095e-301 or 0.0 < (/.f64 (*.f64 a1 a2) (*.f64 b1 b2)) < 1.15248084459416157e274

    1. Initial program 0.7

      \[\frac{a1 \cdot a2}{b1 \cdot b2}\]

    if -2.7274658798653095e-301 < (/.f64 (*.f64 a1 a2) (*.f64 b1 b2)) < 0.0

    1. Initial program 14.3

      \[\frac{a1 \cdot a2}{b1 \cdot b2}\]
    2. Using strategy rm

    3. Applied times-frac_binary64_28122.7

      \[\leadsto \color{blue}{\frac{a1}{b1} \cdot \frac{a2}{b2}}\]
    4. Using strategy rm

    5. Applied add-cube-cbrt_binary64_28412.9

      \[\leadsto \frac{a1}{\color{blue}{\left(\sqrt[3]{b1} \cdot \sqrt[3]{b1}\right) \cdot \sqrt[3]{b1}}} \cdot \frac{a2}{b2}\]

    6. Applied add-cube-cbrt_binary64_28413.0

      \[\leadsto \frac{\color{blue}{\left(\sqrt[3]{a1} \cdot \sqrt[3]{a1}\right) \cdot \sqrt[3]{a1}}}{\left(\sqrt[3]{b1} \cdot \sqrt[3]{b1}\right) \cdot \sqrt[3]{b1}} \cdot \frac{a2}{b2}\]

    7. Applied times-frac_binary64_28123.0

      \[\leadsto \color{blue}{\left(\frac{\sqrt[3]{a1} \cdot \sqrt[3]{a1}}{\sqrt[3]{b1} \cdot \sqrt[3]{b1}} \cdot \frac{\sqrt[3]{a1}}{\sqrt[3]{b1}}\right)} \cdot \frac{a2}{b2}\]

    8. Applied associate-*l*_binary64_27471.9

      \[\leadsto \color{blue}{\frac{\sqrt[3]{a1} \cdot \sqrt[3]{a1}}{\sqrt[3]{b1} \cdot \sqrt[3]{b1}} \cdot \left(\frac{\sqrt[3]{a1}}{\sqrt[3]{b1}} \cdot \frac{a2}{b2}\right)}\]

    9. Simplified1.9

      \[\leadsto \frac{\sqrt[3]{a1} \cdot \sqrt[3]{a1}}{\sqrt[3]{b1} \cdot \sqrt[3]{b1}} \cdot \color{blue}{\left(\frac{a2}{b2} \cdot \frac{\sqrt[3]{a1}}{\sqrt[3]{b1}}\right)}\]

    if 1.15248084459416157e274 < (/.f64 (*.f64 a1 a2) (*.f64 b1 b2))

    1. Initial program 56.4

      \[\frac{a1 \cdot a2}{b1 \cdot b2}\]
    2. Using strategy rm

    3. Applied times-frac_binary64_28128.3

      \[\leadsto \color{blue}{\frac{a1}{b1} \cdot \frac{a2}{b2}}\]
  3. Recombined 4 regimes into one program.

  4. Final simplification2.4

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{a1 \cdot a2}{b1 \cdot b2} \leq -1.525827891617212 \cdot 10^{+281}:\\ \;\;\;\;\frac{1}{\sqrt[3]{b1} \cdot \sqrt[3]{b1}} \cdot \left(\frac{a2}{b2} \cdot \frac{a1}{\sqrt[3]{b1}}\right)\\ \mathbf{elif}\;\frac{a1 \cdot a2}{b1 \cdot b2} \leq -2.7274658798653095 \cdot 10^{-301}:\\ \;\;\;\;\frac{a1 \cdot a2}{b1 \cdot b2}\\ \mathbf{elif}\;\frac{a1 \cdot a2}{b1 \cdot b2} \leq 0:\\ \;\;\;\;\frac{\sqrt[3]{a1} \cdot \sqrt[3]{a1}}{\sqrt[3]{b1} \cdot \sqrt[3]{b1}} \cdot \left(\frac{a2}{b2} \cdot \frac{\sqrt[3]{a1}}{\sqrt[3]{b1}}\right)\\ \mathbf{elif}\;\frac{a1 \cdot a2}{b1 \cdot b2} \leq 1.1524808445941616 \cdot 10^{+274}:\\ \;\;\;\;\frac{a1 \cdot a2}{b1 \cdot b2}\\ \mathbf{else}:\\ \;\;\;\;\frac{a2}{b2} \cdot \frac{a1}{b1}\\ \end{array}\]

Reproduce

herbie shell --seed 2021015 
(FPCore (a1 a2 b1 b2)
  :name "Quotient of products"
  :precision binary64

  :herbie-target
  (* (/ a1 b1) (/ a2 b2))

  (/ (* a1 a2) (* b1 b2)))