Average Error: 0.0 → 0.0
Time: 1.8s
Precision: binary64
\[\frac{1 + \frac{2 \cdot t}{1 + t} \cdot \frac{2 \cdot t}{1 + t}}{2 + \frac{2 \cdot t}{1 + t} \cdot \frac{2 \cdot t}{1 + t}}\]
↓
\[\frac{1 + 4 \cdot \frac{t}{2 + \left(t + \frac{1}{t}\right)}}{2 + 4 \cdot \log \left(e^{\frac{t}{2 + \left(t + \frac{1}{t}\right)}}\right)}\]
\frac{1 + \frac{2 \cdot t}{1 + t} \cdot \frac{2 \cdot t}{1 + t}}{2 + \frac{2 \cdot t}{1 + t} \cdot \frac{2 \cdot t}{1 + t}}
↓
\frac{1 + 4 \cdot \frac{t}{2 + \left(t + \frac{1}{t}\right)}}{2 + 4 \cdot \log \left(e^{\frac{t}{2 + \left(t + \frac{1}{t}\right)}}\right)}
(FPCore (t)
 :precision binary64
 (/
  (+ 1.0 (* (/ (* 2.0 t) (+ 1.0 t)) (/ (* 2.0 t) (+ 1.0 t))))
  (+ 2.0 (* (/ (* 2.0 t) (+ 1.0 t)) (/ (* 2.0 t) (+ 1.0 t))))))
↓
(FPCore (t)
 :precision binary64
 (/
  (+ 1.0 (* 4.0 (/ t (+ 2.0 (+ t (/ 1.0 t))))))
  (+ 2.0 (* 4.0 (log (exp (/ t (+ 2.0 (+ t (/ 1.0 t))))))))))
double code(double t) {
	return (((double) (1.0 + ((double) ((((double) (2.0 * t)) / ((double) (1.0 + t))) * (((double) (2.0 * t)) / ((double) (1.0 + t))))))) / ((double) (2.0 + ((double) ((((double) (2.0 * t)) / ((double) (1.0 + t))) * (((double) (2.0 * t)) / ((double) (1.0 + t))))))));
}
↓
double code(double t) {
	return (((double) (1.0 + ((double) (4.0 * (t / ((double) (2.0 + ((double) (t + (1.0 / t)))))))))) / ((double) (2.0 + ((double) (4.0 * ((double) log(((double) exp((t / ((double) (2.0 + ((double) (t + (1.0 / t)))))))))))))));
}

Error

Bits error versus t

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[\frac{1 + \frac{2 \cdot t}{1 + t} \cdot \frac{2 \cdot t}{1 + t}}{2 + \frac{2 \cdot t}{1 + t} \cdot \frac{2 \cdot t}{1 + t}}\]

  2. Simplified0.0

    \[\leadsto \color{blue}{\frac{1 + 4 \cdot \frac{t}{2 + \left(t + \frac{1}{t}\right)}}{2 + 4 \cdot \frac{t}{2 + \left(t + \frac{1}{t}\right)}}}\]
  3. Using strategy rm

  4. Applied add-log-exp_binary640.0

    \[\leadsto \frac{1 + 4 \cdot \frac{t}{2 + \left(t + \frac{1}{t}\right)}}{2 + 4 \cdot \color{blue}{\log \left(e^{\frac{t}{2 + \left(t + \frac{1}{t}\right)}}\right)}}\]

  5. Final simplification0.0

    \[\leadsto \frac{1 + 4 \cdot \frac{t}{2 + \left(t + \frac{1}{t}\right)}}{2 + 4 \cdot \log \left(e^{\frac{t}{2 + \left(t + \frac{1}{t}\right)}}\right)}\]

Reproduce

herbie shell --seed 2020219 
(FPCore (t)
  :name "Kahan p13 Example 1"
  :precision binary64
  (/ (+ 1.0 (* (/ (* 2.0 t) (+ 1.0 t)) (/ (* 2.0 t) (+ 1.0 t)))) (+ 2.0 (* (/ (* 2.0 t) (+ 1.0 t)) (/ (* 2.0 t) (+ 1.0 t))))))