Average Error: 2.1 → 0.1
Time: 5.2s
Precision: binary64
\[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}\]
\[\begin{array}{l} \mathbf{if}\;k \leq 5.2465810226145275 \cdot 10^{+23}:\\ \;\;\;\;a \cdot \left({\left(\sqrt[3]{k} \cdot \sqrt[3]{k}\right)}^{m} \cdot \frac{{\left(\sqrt[3]{k}\right)}^{m}}{1 + k \cdot \left(k + 10\right)}\right)\\ \mathbf{else}:\\ \;\;\;\;99 \cdot \left(a \cdot \frac{{k}^{m}}{{k}^{4}}\right) + \left(\frac{{k}^{m}}{k} \cdot \frac{a}{k} - 10 \cdot \left(a \cdot \frac{{k}^{m}}{{k}^{3}}\right)\right)\\ \end{array}\]
\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}
\begin{array}{l}
\mathbf{if}\;k \leq 5.2465810226145275 \cdot 10^{+23}:\\
\;\;\;\;a \cdot \left({\left(\sqrt[3]{k} \cdot \sqrt[3]{k}\right)}^{m} \cdot \frac{{\left(\sqrt[3]{k}\right)}^{m}}{1 + k \cdot \left(k + 10\right)}\right)\\

\mathbf{else}:\\
\;\;\;\;99 \cdot \left(a \cdot \frac{{k}^{m}}{{k}^{4}}\right) + \left(\frac{{k}^{m}}{k} \cdot \frac{a}{k} - 10 \cdot \left(a \cdot \frac{{k}^{m}}{{k}^{3}}\right)\right)\\

\end{array}
(FPCore (a k m)
 :precision binary64
 (/ (* a (pow k m)) (+ (+ 1.0 (* 10.0 k)) (* k k))))
(FPCore (a k m)
 :precision binary64
 (if (<= k 5.2465810226145275e+23)
   (*
    a
    (*
     (pow (* (cbrt k) (cbrt k)) m)
     (/ (pow (cbrt k) m) (+ 1.0 (* k (+ k 10.0))))))
   (+
    (* 99.0 (* a (/ (pow k m) (pow k 4.0))))
    (- (* (/ (pow k m) k) (/ a k)) (* 10.0 (* a (/ (pow k m) (pow k 3.0))))))))
double code(double a, double k, double m) {
	return (((double) (a * ((double) pow(k, m)))) / ((double) (((double) (1.0 + ((double) (10.0 * k)))) + ((double) (k * k)))));
}
double code(double a, double k, double m) {
	double VAR;
	if ((k <= 5.2465810226145275e+23)) {
		VAR = ((double) (a * ((double) (((double) pow(((double) (((double) cbrt(k)) * ((double) cbrt(k)))), m)) * (((double) pow(((double) cbrt(k)), m)) / ((double) (1.0 + ((double) (k * ((double) (k + 10.0)))))))))));
	} else {
		VAR = ((double) (((double) (99.0 * ((double) (a * (((double) pow(k, m)) / ((double) pow(k, 4.0))))))) + ((double) (((double) ((((double) pow(k, m)) / k) * (a / k))) - ((double) (10.0 * ((double) (a * (((double) pow(k, m)) / ((double) pow(k, 3.0)))))))))));
	}
	return VAR;
}

Error

Bits error versus a

Bits error versus k

Bits error versus m

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Split input into 2 regimes
  2. if k < 5.24658102261452752e23

    1. Initial program 0.0

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}\]
    2. Simplified0.0

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{1 + k \cdot \left(k + 10\right)}}\]
    3. Using strategy rm
    4. Applied *-un-lft-identity0.0

      \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 \cdot \left(1 + k \cdot \left(k + 10\right)\right)}}\]
    5. Applied add-cube-cbrt0.0

      \[\leadsto a \cdot \frac{{\color{blue}{\left(\left(\sqrt[3]{k} \cdot \sqrt[3]{k}\right) \cdot \sqrt[3]{k}\right)}}^{m}}{1 \cdot \left(1 + k \cdot \left(k + 10\right)\right)}\]
    6. Applied unpow-prod-down0.0

      \[\leadsto a \cdot \frac{\color{blue}{{\left(\sqrt[3]{k} \cdot \sqrt[3]{k}\right)}^{m} \cdot {\left(\sqrt[3]{k}\right)}^{m}}}{1 \cdot \left(1 + k \cdot \left(k + 10\right)\right)}\]
    7. Applied times-frac0.0

      \[\leadsto a \cdot \color{blue}{\left(\frac{{\left(\sqrt[3]{k} \cdot \sqrt[3]{k}\right)}^{m}}{1} \cdot \frac{{\left(\sqrt[3]{k}\right)}^{m}}{1 + k \cdot \left(k + 10\right)}\right)}\]
    8. Simplified0.0

      \[\leadsto a \cdot \left(\color{blue}{{\left(\sqrt[3]{k} \cdot \sqrt[3]{k}\right)}^{m}} \cdot \frac{{\left(\sqrt[3]{k}\right)}^{m}}{1 + k \cdot \left(k + 10\right)}\right)\]

    if 5.24658102261452752e23 < k

    1. Initial program 5.7

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}\]
    2. Simplified5.8

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{1 + k \cdot \left(k + 10\right)}}\]
    3. Using strategy rm
    4. Applied add-sqr-sqrt5.8

      \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\sqrt{1 + k \cdot \left(k + 10\right)} \cdot \sqrt{1 + k \cdot \left(k + 10\right)}}}\]
    5. Applied *-un-lft-identity5.8

      \[\leadsto a \cdot \frac{{\color{blue}{\left(1 \cdot k\right)}}^{m}}{\sqrt{1 + k \cdot \left(k + 10\right)} \cdot \sqrt{1 + k \cdot \left(k + 10\right)}}\]
    6. Applied unpow-prod-down5.8

      \[\leadsto a \cdot \frac{\color{blue}{{1}^{m} \cdot {k}^{m}}}{\sqrt{1 + k \cdot \left(k + 10\right)} \cdot \sqrt{1 + k \cdot \left(k + 10\right)}}\]
    7. Applied times-frac5.8

      \[\leadsto a \cdot \color{blue}{\left(\frac{{1}^{m}}{\sqrt{1 + k \cdot \left(k + 10\right)}} \cdot \frac{{k}^{m}}{\sqrt{1 + k \cdot \left(k + 10\right)}}\right)}\]
    8. Applied associate-*r*5.8

      \[\leadsto \color{blue}{\left(a \cdot \frac{{1}^{m}}{\sqrt{1 + k \cdot \left(k + 10\right)}}\right) \cdot \frac{{k}^{m}}{\sqrt{1 + k \cdot \left(k + 10\right)}}}\]
    9. Simplified5.8

      \[\leadsto \color{blue}{\frac{a}{\sqrt{1 + k \cdot \left(k + 10\right)}}} \cdot \frac{{k}^{m}}{\sqrt{1 + k \cdot \left(k + 10\right)}}\]
    10. Taylor expanded around inf 5.7

      \[\leadsto \color{blue}{\left(99 \cdot \frac{e^{m \cdot \left(\log 1 - \log \left(\frac{1}{k}\right)\right)} \cdot a}{{k}^{4}} + \frac{e^{m \cdot \left(\log 1 - \log \left(\frac{1}{k}\right)\right)} \cdot a}{{k}^{2}}\right) - 10 \cdot \frac{e^{m \cdot \left(\log 1 - \log \left(\frac{1}{k}\right)\right)} \cdot a}{{k}^{3}}}\]
    11. Simplified0.1

      \[\leadsto \color{blue}{99 \cdot \left(\frac{{k}^{m}}{{k}^{4}} \cdot a\right) + \left(\frac{{k}^{m}}{k} \cdot \frac{a}{k} - 10 \cdot \left(\frac{{k}^{m}}{{k}^{3}} \cdot a\right)\right)}\]
  3. Recombined 2 regimes into one program.
  4. Final simplification0.1

    \[\leadsto \begin{array}{l} \mathbf{if}\;k \leq 5.2465810226145275 \cdot 10^{+23}:\\ \;\;\;\;a \cdot \left({\left(\sqrt[3]{k} \cdot \sqrt[3]{k}\right)}^{m} \cdot \frac{{\left(\sqrt[3]{k}\right)}^{m}}{1 + k \cdot \left(k + 10\right)}\right)\\ \mathbf{else}:\\ \;\;\;\;99 \cdot \left(a \cdot \frac{{k}^{m}}{{k}^{4}}\right) + \left(\frac{{k}^{m}}{k} \cdot \frac{a}{k} - 10 \cdot \left(a \cdot \frac{{k}^{m}}{{k}^{3}}\right)\right)\\ \end{array}\]

Reproduce

herbie shell --seed 2020198 
(FPCore (a k m)
  :name "Falkner and Boettcher, Appendix A"
  :precision binary64
  (/ (* a (pow k m)) (+ (+ 1.0 (* 10.0 k)) (* k k))))