Average Error: 11.8 → 5.9
Time: 3.2s
Precision: binary64
\[\frac{a1 \cdot a2}{b1 \cdot b2}\]
\[\begin{array}{l} \mathbf{if}\;a1 \cdot a2 \leq -6.389965488148195 \cdot 10^{+119}:\\ \;\;\;\;\frac{a2}{b1} \cdot \frac{a1}{b2}\\ \mathbf{elif}\;a1 \cdot a2 \leq -3.313835999822937 \cdot 10^{-202}:\\ \;\;\;\;\left(a1 \cdot a2\right) \cdot \frac{1}{b1 \cdot b2}\\ \mathbf{elif}\;a1 \cdot a2 \leq 5.581682978566765 \cdot 10^{-265}:\\ \;\;\;\;a2 \cdot \frac{\frac{a1}{b1}}{b2}\\ \mathbf{elif}\;a1 \cdot a2 \leq 4.762500496650808 \cdot 10^{+291}:\\ \;\;\;\;\left(a1 \cdot a2\right) \cdot \frac{1}{b1 \cdot b2}\\ \mathbf{else}:\\ \;\;\;\;\frac{a2}{b1} \cdot \frac{a1}{b2}\\ \end{array}\]
\frac{a1 \cdot a2}{b1 \cdot b2}
\begin{array}{l}
\mathbf{if}\;a1 \cdot a2 \leq -6.389965488148195 \cdot 10^{+119}:\\
\;\;\;\;\frac{a2}{b1} \cdot \frac{a1}{b2}\\

\mathbf{elif}\;a1 \cdot a2 \leq -3.313835999822937 \cdot 10^{-202}:\\
\;\;\;\;\left(a1 \cdot a2\right) \cdot \frac{1}{b1 \cdot b2}\\

\mathbf{elif}\;a1 \cdot a2 \leq 5.581682978566765 \cdot 10^{-265}:\\
\;\;\;\;a2 \cdot \frac{\frac{a1}{b1}}{b2}\\

\mathbf{elif}\;a1 \cdot a2 \leq 4.762500496650808 \cdot 10^{+291}:\\
\;\;\;\;\left(a1 \cdot a2\right) \cdot \frac{1}{b1 \cdot b2}\\

\mathbf{else}:\\
\;\;\;\;\frac{a2}{b1} \cdot \frac{a1}{b2}\\

\end{array}
(FPCore (a1 a2 b1 b2) :precision binary64 (/ (* a1 a2) (* b1 b2)))
(FPCore (a1 a2 b1 b2)
 :precision binary64
 (if (<= (* a1 a2) -6.389965488148195e+119)
   (* (/ a2 b1) (/ a1 b2))
   (if (<= (* a1 a2) -3.313835999822937e-202)
     (* (* a1 a2) (/ 1.0 (* b1 b2)))
     (if (<= (* a1 a2) 5.581682978566765e-265)
       (* a2 (/ (/ a1 b1) b2))
       (if (<= (* a1 a2) 4.762500496650808e+291)
         (* (* a1 a2) (/ 1.0 (* b1 b2)))
         (* (/ a2 b1) (/ a1 b2)))))))
double code(double a1, double a2, double b1, double b2) {
	return (((double) (a1 * a2)) / ((double) (b1 * b2)));
}
double code(double a1, double a2, double b1, double b2) {
	double VAR;
	if ((((double) (a1 * a2)) <= -6.389965488148195e+119)) {
		VAR = ((double) ((a2 / b1) * (a1 / b2)));
	} else {
		double VAR_1;
		if ((((double) (a1 * a2)) <= -3.313835999822937e-202)) {
			VAR_1 = ((double) (((double) (a1 * a2)) * (1.0 / ((double) (b1 * b2)))));
		} else {
			double VAR_2;
			if ((((double) (a1 * a2)) <= 5.581682978566765e-265)) {
				VAR_2 = ((double) (a2 * ((a1 / b1) / b2)));
			} else {
				double VAR_3;
				if ((((double) (a1 * a2)) <= 4.762500496650808e+291)) {
					VAR_3 = ((double) (((double) (a1 * a2)) * (1.0 / ((double) (b1 * b2)))));
				} else {
					VAR_3 = ((double) ((a2 / b1) * (a1 / b2)));
				}
				VAR_2 = VAR_3;
			}
			VAR_1 = VAR_2;
		}
		VAR = VAR_1;
	}
	return VAR;
}

Error

Bits error versus a1

Bits error versus a2

Bits error versus b1

Bits error versus b2

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original11.8
Target11.1
Herbie5.9
\[\frac{a1}{b1} \cdot \frac{a2}{b2}\]

Derivation

  1. Split input into 3 regimes
  2. if (* a1 a2) < -6.3899654881481949e119 or 4.7625004966508079e291 < (* a1 a2)

    1. Initial program 33.2

      \[\frac{a1 \cdot a2}{b1 \cdot b2}\]
    2. Taylor expanded around 0 33.2

      \[\leadsto \color{blue}{\frac{a1 \cdot a2}{b1 \cdot b2}}\]
    3. Simplified17.7

      \[\leadsto \color{blue}{a2 \cdot \frac{a1}{b1 \cdot b2}}\]
    4. Using strategy rm
    5. Applied *-un-lft-identity17.7

      \[\leadsto a2 \cdot \frac{\color{blue}{1 \cdot a1}}{b1 \cdot b2}\]
    6. Applied times-frac10.2

      \[\leadsto a2 \cdot \color{blue}{\left(\frac{1}{b1} \cdot \frac{a1}{b2}\right)}\]
    7. Applied associate-*r*11.5

      \[\leadsto \color{blue}{\left(a2 \cdot \frac{1}{b1}\right) \cdot \frac{a1}{b2}}\]
    8. Simplified11.4

      \[\leadsto \color{blue}{\frac{a2}{b1}} \cdot \frac{a1}{b2}\]

    if -6.3899654881481949e119 < (* a1 a2) < -3.3138359998229371e-202 or 5.5816829785667653e-265 < (* a1 a2) < 4.7625004966508079e291

    1. Initial program 4.9

      \[\frac{a1 \cdot a2}{b1 \cdot b2}\]
    2. Using strategy rm
    3. Applied div-inv5.2

      \[\leadsto \color{blue}{\left(a1 \cdot a2\right) \cdot \frac{1}{b1 \cdot b2}}\]

    if -3.3138359998229371e-202 < (* a1 a2) < 5.5816829785667653e-265

    1. Initial program 16.4

      \[\frac{a1 \cdot a2}{b1 \cdot b2}\]
    2. Taylor expanded around 0 16.4

      \[\leadsto \color{blue}{\frac{a1 \cdot a2}{b1 \cdot b2}}\]
    3. Simplified8.1

      \[\leadsto \color{blue}{a2 \cdot \frac{a1}{b1 \cdot b2}}\]
    4. Using strategy rm
    5. Applied associate-/r*4.2

      \[\leadsto a2 \cdot \color{blue}{\frac{\frac{a1}{b1}}{b2}}\]
  3. Recombined 3 regimes into one program.
  4. Final simplification5.9

    \[\leadsto \begin{array}{l} \mathbf{if}\;a1 \cdot a2 \leq -6.389965488148195 \cdot 10^{+119}:\\ \;\;\;\;\frac{a2}{b1} \cdot \frac{a1}{b2}\\ \mathbf{elif}\;a1 \cdot a2 \leq -3.313835999822937 \cdot 10^{-202}:\\ \;\;\;\;\left(a1 \cdot a2\right) \cdot \frac{1}{b1 \cdot b2}\\ \mathbf{elif}\;a1 \cdot a2 \leq 5.581682978566765 \cdot 10^{-265}:\\ \;\;\;\;a2 \cdot \frac{\frac{a1}{b1}}{b2}\\ \mathbf{elif}\;a1 \cdot a2 \leq 4.762500496650808 \cdot 10^{+291}:\\ \;\;\;\;\left(a1 \cdot a2\right) \cdot \frac{1}{b1 \cdot b2}\\ \mathbf{else}:\\ \;\;\;\;\frac{a2}{b1} \cdot \frac{a1}{b2}\\ \end{array}\]

Reproduce

herbie shell --seed 2020198 
(FPCore (a1 a2 b1 b2)
  :name "Quotient of products"
  :precision binary64

  :herbie-target
  (* (/ a1 b1) (/ a2 b2))

  (/ (* a1 a2) (* b1 b2)))