- Split input into 2 regimes
if (+ (- (exp x) 2.0) (exp (neg x))) < 1.4521224485864e-5
Initial program 30.6
\[\left(e^{x} - 2\right) + e^{-x}\]
Taylor expanded around 0 0.0
\[\leadsto \color{blue}{{x}^{2} + \left(\frac{1}{360} \cdot {x}^{6} + \frac{1}{12} \cdot {x}^{4}\right)}\]
Simplified0.0
\[\leadsto \color{blue}{x \cdot x + \left(\frac{1}{360} \cdot {x}^{6} + \frac{1}{12} \cdot {x}^{4}\right)}\]
if 1.4521224485864e-5 < (+ (- (exp x) 2.0) (exp (neg x)))
Initial program 3.1
\[\left(e^{x} - 2\right) + e^{-x}\]
- Using strategy
rm Applied exp-neg2.9
\[\leadsto \left(e^{x} - 2\right) + \color{blue}{\frac{1}{e^{x}}}\]
Applied flip3--5.1
\[\leadsto \color{blue}{\frac{{\left(e^{x}\right)}^{3} - {2}^{3}}{e^{x} \cdot e^{x} + \left(2 \cdot 2 + e^{x} \cdot 2\right)}} + \frac{1}{e^{x}}\]
Applied frac-add6.2
\[\leadsto \color{blue}{\frac{\left({\left(e^{x}\right)}^{3} - {2}^{3}\right) \cdot e^{x} + \left(e^{x} \cdot e^{x} + \left(2 \cdot 2 + e^{x} \cdot 2\right)\right) \cdot 1}{\left(e^{x} \cdot e^{x} + \left(2 \cdot 2 + e^{x} \cdot 2\right)\right) \cdot e^{x}}}\]
Simplified5.9
\[\leadsto \frac{\color{blue}{2 \cdot 2 + e^{x} \cdot \left(\left({\left(e^{x}\right)}^{3} - {2}^{3}\right) + \left(e^{x} + 2\right)\right)}}{\left(e^{x} \cdot e^{x} + \left(2 \cdot 2 + e^{x} \cdot 2\right)\right) \cdot e^{x}}\]
Simplified5.9
\[\leadsto \frac{2 \cdot 2 + e^{x} \cdot \left(\left({\left(e^{x}\right)}^{3} - {2}^{3}\right) + \left(e^{x} + 2\right)\right)}{\color{blue}{{\left(e^{x}\right)}^{3} + e^{x} \cdot \left(2 \cdot \left(e^{x} + 2\right)\right)}}\]
- Recombined 2 regimes into one program.
Final simplification0.1
\[\leadsto \begin{array}{l}
\mathbf{if}\;\left(e^{x} - 2\right) + e^{-x} \le 1.4521224485864 \cdot 10^{-5}:\\
\;\;\;\;x \cdot x + \left(\frac{1}{360} \cdot {x}^{6} + \frac{1}{12} \cdot {x}^{4}\right)\\
\mathbf{else}:\\
\;\;\;\;\frac{2 \cdot 2 + e^{x} \cdot \left(\left({\left(e^{x}\right)}^{3} - {2}^{3}\right) + \left(e^{x} + 2\right)\right)}{{\left(e^{x}\right)}^{3} + e^{x} \cdot \left(2 \cdot \left(e^{x} + 2\right)\right)}\\
\end{array}\]