Average Error: 20.9 → 0.0
Time: 1.6s
Precision: binary64
\[\sqrt{x \cdot x + y}\]
\[\begin{array}{l} \mathbf{if}\;x \le -1.33225531887144938 \cdot 10^{154}:\\ \;\;\;\;y \cdot \frac{\frac{-1}{2}}{x} - x\\ \mathbf{elif}\;x \le 1.1342193858949797 \cdot 10^{138}:\\ \;\;\;\;\sqrt{y + x \cdot x}\\ \mathbf{else}:\\ \;\;\;\;x + y \cdot \frac{\frac{1}{2}}{x}\\ \end{array}\]
\sqrt{x \cdot x + y}
\begin{array}{l}
\mathbf{if}\;x \le -1.33225531887144938 \cdot 10^{154}:\\
\;\;\;\;y \cdot \frac{\frac{-1}{2}}{x} - x\\

\mathbf{elif}\;x \le 1.1342193858949797 \cdot 10^{138}:\\
\;\;\;\;\sqrt{y + x \cdot x}\\

\mathbf{else}:\\
\;\;\;\;x + y \cdot \frac{\frac{1}{2}}{x}\\

\end{array}
double code(double x, double y) {
	return ((double) sqrt(((double) (((double) (x * x)) + y))));
}
double code(double x, double y) {
	double VAR;
	if ((x <= -1.3322553188714494e+154)) {
		VAR = ((double) (((double) (y * ((double) (-0.5 / x)))) - x));
	} else {
		double VAR_1;
		if ((x <= 1.1342193858949797e+138)) {
			VAR_1 = ((double) sqrt(((double) (y + ((double) (x * x))))));
		} else {
			VAR_1 = ((double) (x + ((double) (y * ((double) (0.5 / x))))));
		}
		VAR = VAR_1;
	}
	return VAR;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original20.9
Target0.5
Herbie0.0
\[\begin{array}{l} \mathbf{if}\;x \lt -1.5097698010472593 \cdot 10^{153}:\\ \;\;\;\;-\left(0.5 \cdot \frac{y}{x} + x\right)\\ \mathbf{elif}\;x \lt 5.5823995511225407 \cdot 10^{57}:\\ \;\;\;\;\sqrt{x \cdot x + y}\\ \mathbf{else}:\\ \;\;\;\;0.5 \cdot \frac{y}{x} + x\\ \end{array}\]

Derivation

  1. Split input into 3 regimes
  2. if x < -1.33225531887144938e154

    1. Initial program 64.0

      \[\sqrt{x \cdot x + y}\]
    2. Taylor expanded around -inf 0

      \[\leadsto \color{blue}{-\left(x + \frac{1}{2} \cdot \frac{y}{x}\right)}\]
    3. Simplified0

      \[\leadsto \color{blue}{y \cdot \frac{\frac{-1}{2}}{x} - x}\]

    if -1.33225531887144938e154 < x < 1.1342193858949797e138

    1. Initial program 0.0

      \[\sqrt{x \cdot x + y}\]

    if 1.1342193858949797e138 < x

    1. Initial program 57.4

      \[\sqrt{x \cdot x + y}\]
    2. Taylor expanded around inf 0.1

      \[\leadsto \color{blue}{x + \frac{1}{2} \cdot \frac{y}{x}}\]
    3. Simplified0.1

      \[\leadsto \color{blue}{x + y \cdot \frac{\frac{1}{2}}{x}}\]
  3. Recombined 3 regimes into one program.
  4. Final simplification0.0

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \le -1.33225531887144938 \cdot 10^{154}:\\ \;\;\;\;y \cdot \frac{\frac{-1}{2}}{x} - x\\ \mathbf{elif}\;x \le 1.1342193858949797 \cdot 10^{138}:\\ \;\;\;\;\sqrt{y + x \cdot x}\\ \mathbf{else}:\\ \;\;\;\;x + y \cdot \frac{\frac{1}{2}}{x}\\ \end{array}\]

Reproduce

herbie shell --seed 2020184 
(FPCore (x y)
  :name "Linear.Quaternion:$clog from linear-1.19.1.3"
  :precision binary64

  :herbie-target
  (if (< x -1.5097698010472593e+153) (neg (+ (* 0.5 (/ y x)) x)) (if (< x 5.582399551122541e+57) (sqrt (+ (* x x) y)) (+ (* 0.5 (/ y x)) x)))

  (sqrt (+ (* x x) y)))