Average Error: 0.0 → 0.0
Time: 3.5s
Precision: binary64
\[e^{\left(x \cdot y\right) \cdot y}\]
↓
\[e^{x \cdot \left(y \cdot y\right)}\]
e^{\left(x \cdot y\right) \cdot y}
↓
e^{x \cdot \left(y \cdot y\right)}
double code(double x, double y) {
	return ((double) exp(((double) (((double) (x * y)) * y))));
}
↓
double code(double x, double y) {
	return ((double) exp(((double) (x * ((double) (y * y))))));
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[e^{\left(x \cdot y\right) \cdot y}\]
  2. Using strategy rm

  3. Applied associate-*l*0.0

    \[\leadsto e^{\color{blue}{x \cdot \left(y \cdot y\right)}}\]

  4. Final simplification0.0

    \[\leadsto e^{x \cdot \left(y \cdot y\right)}\]

Reproduce

herbie shell --seed 2020182 
(FPCore (x y)
  :name "Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2"
  :precision binary64
  (exp (* (* x y) y)))