- Split input into 2 regimes
if z < -2.74740209752635133e-102
Initial program 2.6
\[x \cdot \left(\frac{y}{z} - \frac{t}{1 - z}\right)\]
- Using strategy
rm Applied div-inv2.6
\[\leadsto x \cdot \left(\frac{y}{z} - \color{blue}{t \cdot \frac{1}{1 - z}}\right)\]
- Using strategy
rm Applied sub-neg2.6
\[\leadsto x \cdot \color{blue}{\left(\frac{y}{z} + \left(-t \cdot \frac{1}{1 - z}\right)\right)}\]
Applied distribute-lft-in2.6
\[\leadsto \color{blue}{x \cdot \frac{y}{z} + x \cdot \left(-t \cdot \frac{1}{1 - z}\right)}\]
Simplified6.1
\[\leadsto \color{blue}{\frac{x \cdot y}{z}} + x \cdot \left(-t \cdot \frac{1}{1 - z}\right)\]
Simplified6.1
\[\leadsto \frac{x \cdot y}{z} + \color{blue}{\left(-\frac{t}{1 - z}\right) \cdot x}\]
- Using strategy
rm Applied associate-/l*2.5
\[\leadsto \color{blue}{\frac{x}{\frac{z}{y}}} + \left(-\frac{t}{1 - z}\right) \cdot x\]
if -2.74740209752635133e-102 < z
Initial program 6.3
\[x \cdot \left(\frac{y}{z} - \frac{t}{1 - z}\right)\]
- Using strategy
rm Applied div-inv6.3
\[\leadsto x \cdot \left(\frac{y}{z} - \color{blue}{t \cdot \frac{1}{1 - z}}\right)\]
- Using strategy
rm Applied sub-neg6.3
\[\leadsto x \cdot \color{blue}{\left(\frac{y}{z} + \left(-t \cdot \frac{1}{1 - z}\right)\right)}\]
Applied distribute-lft-in6.3
\[\leadsto \color{blue}{x \cdot \frac{y}{z} + x \cdot \left(-t \cdot \frac{1}{1 - z}\right)}\]
Simplified5.4
\[\leadsto \color{blue}{\frac{x \cdot y}{z}} + x \cdot \left(-t \cdot \frac{1}{1 - z}\right)\]
Simplified5.4
\[\leadsto \frac{x \cdot y}{z} + \color{blue}{\left(-\frac{t}{1 - z}\right) \cdot x}\]
- Using strategy
rm Applied div-inv5.5
\[\leadsto \color{blue}{\left(x \cdot y\right) \cdot \frac{1}{z}} + \left(-\frac{t}{1 - z}\right) \cdot x\]
- Recombined 2 regimes into one program.
Final simplification4.4
\[\leadsto \begin{array}{l}
\mathbf{if}\;z \le -2.74740209752635133 \cdot 10^{-102}:\\
\;\;\;\;\frac{x}{\frac{z}{y}} + \left(-\frac{t}{1 - z}\right) \cdot x\\
\mathbf{else}:\\
\;\;\;\;\left(x \cdot y\right) \cdot \frac{1}{z} + \left(-\frac{t}{1 - z}\right) \cdot x\\
\end{array}\]