Average Error: 29.2 → 0.1
Time: 6.0s
Precision: binary64
\[\log \left(N + 1\right) - \log N\]
\[\begin{array}{l} \mathbf{if}\;N \le 9062.3089972093367:\\ \;\;\;\;\log \left(\frac{1}{N} + 1\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{0.333333333333333315}{{N}^{3}} + \left(\frac{1}{N} - \frac{0.5}{N \cdot N}\right)\\ \end{array}\]
\log \left(N + 1\right) - \log N
\begin{array}{l}
\mathbf{if}\;N \le 9062.3089972093367:\\
\;\;\;\;\log \left(\frac{1}{N} + 1\right)\\

\mathbf{else}:\\
\;\;\;\;\frac{0.333333333333333315}{{N}^{3}} + \left(\frac{1}{N} - \frac{0.5}{N \cdot N}\right)\\

\end{array}
double code(double N) {
	return ((double) (((double) log(((double) (N + 1.0)))) - ((double) log(N))));
}
double code(double N) {
	double VAR;
	if ((N <= 9062.308997209337)) {
		VAR = ((double) log(((double) ((1.0 / N) + 1.0))));
	} else {
		VAR = ((double) ((0.3333333333333333 / ((double) pow(N, 3.0))) + ((double) ((1.0 / N) - (0.5 / ((double) (N * N)))))));
	}
	return VAR;
}

Error

Bits error versus N

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Split input into 2 regimes
  2. if N < 9062.3089972093367

    1. Initial program 0.1

      \[\log \left(N + 1\right) - \log N\]
    2. Using strategy rm
    3. Applied diff-log0.1

      \[\leadsto \color{blue}{\log \left(\frac{N + 1}{N}\right)}\]
    4. Taylor expanded around 0 0.1

      \[\leadsto \log \color{blue}{\left(1 \cdot \frac{1}{N} + 1\right)}\]
    5. Simplified0.1

      \[\leadsto \log \color{blue}{\left(\frac{1}{N} + 1\right)}\]

    if 9062.3089972093367 < N

    1. Initial program 59.4

      \[\log \left(N + 1\right) - \log N\]
    2. Taylor expanded around inf 0.0

      \[\leadsto \color{blue}{\left(0.333333333333333315 \cdot \frac{1}{{N}^{3}} + 1 \cdot \frac{1}{N}\right) - 0.5 \cdot \frac{1}{{N}^{2}}}\]
    3. Simplified0.0

      \[\leadsto \color{blue}{\frac{0.333333333333333315}{{N}^{3}} + \left(\frac{1}{N} - \frac{0.5}{N \cdot N}\right)}\]
  3. Recombined 2 regimes into one program.
  4. Final simplification0.1

    \[\leadsto \begin{array}{l} \mathbf{if}\;N \le 9062.3089972093367:\\ \;\;\;\;\log \left(\frac{1}{N} + 1\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{0.333333333333333315}{{N}^{3}} + \left(\frac{1}{N} - \frac{0.5}{N \cdot N}\right)\\ \end{array}\]

Reproduce

herbie shell --seed 2020182 
(FPCore (N)
  :name "2log (problem 3.3.6)"
  :precision binary64
  (- (log (+ N 1.0)) (log N)))