Average Error: 10.6 → 2.0
Time: 7.9s
Precision: binary64
\[\]
↓
\[\]
↓
double code(double x, double y, double z, double t, double a) {
	return ((double) (((double) (x - ((double) (y * z)))) / ((double) (t - ((double) (a * z))))));
}

↓
double code(double x, double y, double z, double t, double a) {
	double VAR;
	if (((z <= -1.5239901933061968e-158) || !(z <= 1.1777719673559236e-98))) {
		VAR = ((double) (((double) (x / ((double) (t - ((double) (z * a)))))) - ((double) (y * ((double) (1.0 / ((double) (((double) (t / z)) - a))))))));
	} else {
		VAR = ((double) (((double) (x - ((double) (z * y)))) * ((double) (1.0 / ((double) (t - ((double) (z * a))))))));
	}
	return VAR;
}

Error
Bits error versus x
Bits error versus y
Bits error versus z
Bits error versus t
Bits error versus a
Try it out
Your Program's Arguments
Results
Enter valid numbers for all inputs
Target
Original10.6
Target1.7
Herbie2.0
\[\]
Derivation
  1. Split input into 2 regimes
  2. if  z  < -1.52399019330619684e-158 or 1.1777719673559236e-98 <  z 
    1. Initial program 14.8
      \[\]
    2. Using strategy rm
    3. Applied div-sub14.8
      \[\leadsto \]
    4. Simplified14.8
      \[\leadsto \]
    5. Simplified2.6
      \[\leadsto \]
    6. Using strategy rm
    7. Applied div-inv2.8
      \[\leadsto \]
    if -1.52399019330619684e-158 <  z  < 1.1777719673559236e-98
    1. Initial program 0.1
      \[\]
    2. Using strategy rm
    3. Applied div-inv0.3
      \[\leadsto \]
    4. Simplified0.3
      \[\leadsto \]
  3. Recombined 2 regimes into one program.
  4. Final simplification2.0
    \[\leadsto \]
Reproduce
herbie shell --seed 2020181 
(FPCore (x y z t a)
  :name "Diagrams.Solve.Tridiagonal:solveTriDiagonal from diagrams-solve-0.1, A"
  :precision binary64

  :herbie-target
  (if (< z -32113435955957344.0) (- (/ x (- t (* a z))) (/ y (- (/ t z) a))) (if (< z 3.5139522372978296e-86) (* (- x (* y z)) (/ 1.0 (- t (* a z)))) (- (/ x (- t (* a z))) (/ y (- (/ t z) a)))))

  (/ (- x (* y z)) (- t (* a z))))