Average Error: 28.2 → 28.2
Time: 1.6s
Precision: binary64
\[{\left(\left(a \cdot b\right) \cdot c\right)}^{\left(\frac{1}{3}\right)}\]
↓
\[{\left(\left(a \cdot b\right) \cdot c\right)}^{\left(\frac{1}{3}\right)}\]
{\left(\left(a \cdot b\right) \cdot c\right)}^{\left(\frac{1}{3}\right)}
↓
{\left(\left(a \cdot b\right) \cdot c\right)}^{\left(\frac{1}{3}\right)}
double code(double a, double b, double c) {
	return ((double) pow(((double) (((double) (a * b)) * c)), ((double) (1.0 / 3.0))));
}
↓
double code(double a, double b, double c) {
	return ((double) pow(((double) (((double) (a * b)) * c)), ((double) (1.0 / 3.0))));
}

Error

Bits error versus a

Bits error versus b

Bits error versus c

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 28.2

    \[{\left(\left(a \cdot b\right) \cdot c\right)}^{\left(\frac{1}{3}\right)}\]

  2. Final simplification28.2

    \[\leadsto {\left(\left(a \cdot b\right) \cdot c\right)}^{\left(\frac{1}{3}\right)}\]

Reproduce

herbie shell --seed 2020153 
(FPCore (a b c)
  :name "(pow (* (* a b) c) (/ 1 3))"
  :precision binary64
  (pow (* (* a b) c) (/ 1.0 3.0)))