Average Error: 15.1 → 15.1
Time: 1.3s
Precision: binary64
\[{\left(a \cdot b\right)}^{\left(\frac{1}{2}\right)}\]
↓
\[{\left(a \cdot b\right)}^{\left(\frac{1}{2}\right)}\]
{\left(a \cdot b\right)}^{\left(\frac{1}{2}\right)}
↓
{\left(a \cdot b\right)}^{\left(\frac{1}{2}\right)}
double code(double a, double b) {
	return ((double) pow(((double) (a * b)), ((double) (1.0 / 2.0))));
}
↓
double code(double a, double b) {
	return ((double) pow(((double) (a * b)), ((double) (1.0 / 2.0))));
}

Error

Bits error versus a

Bits error versus b

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 15.1

    \[{\left(a \cdot b\right)}^{\left(\frac{1}{2}\right)}\]

  2. Final simplification15.1

    \[\leadsto {\left(a \cdot b\right)}^{\left(\frac{1}{2}\right)}\]

Reproduce

herbie shell --seed 2020153 
(FPCore (a b)
  :name "(pow (* a b) (/ 1 2))"
  :precision binary64
  (pow (* a b) (/ 1.0 2.0)))